本文整理汇总了Java中org.hibernate.criterion.Restrictions.disjunction方法的典型用法代码示例。如果您正苦于以下问题：Java Restrictions.disjunction方法的具体用法？Java Restrictions.disjunction怎么用？Java Restrictions.disjunction使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类org.hibernate.criterion.Restrictions的用法示例。
在下文中一共展示了Restrictions.disjunction方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Java代码示例。
示例1: buildCriterions
import org.hibernate.criterion.Restrictions; //导入方法依赖的package包/类
private void buildCriterions(Collection<com.bstek.dorado.data.provider.Criterion> criterions,DetachedCriteria dc){
for(com.bstek.dorado.data.provider.Criterion c : criterions){
if (c instanceof SingleValueFilterCriterion){
SingleValueFilterCriterion fc = (SingleValueFilterCriterion) c;
dc.add(this.buildCriterion(fc));
}
if (c instanceof Junction) {
Junction jun = (Junction) c;
org.hibernate.criterion.Junction junction = null;
if (jun instanceof Or) {
junction = Restrictions.disjunction();
} else if (jun instanceof And) {
junction = Restrictions.conjunction();
}
Collection<com.bstek.dorado.data.provider.Criterion> subCriterions = jun.getCriterions();
if (subCriterions != null) {
buildCriterions(subCriterions, junction);
}
dc.add(junction);
}
}
}
示例2: buildCriterions
import org.hibernate.criterion.Restrictions; //导入方法依赖的package包/类
private void buildCriterions(Collection<com.bstek.dorado.data.provider.Criterion> criterions, DetachedCriteria dc) {
for (com.bstek.dorado.data.provider.Criterion c : criterions) {
if (c instanceof SingleValueFilterCriterion) {
SingleValueFilterCriterion fc = (SingleValueFilterCriterion) c;
dc.add(this.buildCriterion(fc));
}
if (c instanceof Junction) {
Junction jun = (Junction) c;
org.hibernate.criterion.Junction junction = null;
if (jun instanceof Or) {
junction = Restrictions.disjunction();
} else if (jun instanceof And) {
junction = Restrictions.conjunction();
}
Collection<com.bstek.dorado.data.provider.Criterion> subCriterions = jun.getCriterions();
if (subCriterions != null) {
buildCriterions(subCriterions, junction);
}
dc.add(junction);
}
}
}