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Java ApiCompatibilityUtils.getBlockCount方法代码示例

本文整理汇总了Java中org.chromium.base.ApiCompatibilityUtils.getBlockCount方法的典型用法代码示例。如果您正苦于以下问题:Java ApiCompatibilityUtils.getBlockCount方法的具体用法?Java ApiCompatibilityUtils.getBlockCount怎么用?Java ApiCompatibilityUtils.getBlockCount使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在org.chromium.base.ApiCompatibilityUtils的用法示例。


在下文中一共展示了ApiCompatibilityUtils.getBlockCount方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Java代码示例。

示例1: doInBackground

import org.chromium.base.ApiCompatibilityUtils; //导入方法依赖的package包/类
@Override
protected Long doInBackground(Void... params) {
    File downloadDirectory = Environment.getExternalStoragePublicDirectory(
            Environment.DIRECTORY_DOWNLOADS);

    // Create the downloads directory, if necessary.
    if (!downloadDirectory.exists()) {
        try {
            // mkdirs() can fail, so we still need to check if the directory exists
            // later.
            downloadDirectory.mkdirs();
        } catch (SecurityException e) {
            Log.e(TAG, "SecurityException when creating download directory.", e);
        }
    }

    // Determine how much space is available on the storage device where downloads
    // reside.  If the downloads directory doesn't exist, it is likely that the user
    // doesn't have an SD card installed.
    long blocks = 0;
    if (downloadDirectory.exists()) {
        StatFs statFs = new StatFs(downloadDirectory.getPath());
        if (mFetchTotalSize) {
            blocks = ApiCompatibilityUtils.getBlockCount(statFs);
        } else {
            blocks = ApiCompatibilityUtils.getAvailableBlocks(statFs);
        }

        return blocks * ApiCompatibilityUtils.getBlockSize(statFs);
    } else {
        Log.e(TAG, "Download directory doesn't exist.");
        return 0L;
    }
}
 
开发者ID:rkshuai,项目名称:chromium-for-android-56-debug-video,代码行数:35,代码来源:SpaceDisplay.java


注:本文中的org.chromium.base.ApiCompatibilityUtils.getBlockCount方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。