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Java Potion.isSplash方法代码示例

本文整理汇总了Java中org.bukkit.potion.Potion.isSplash方法的典型用法代码示例。如果您正苦于以下问题:Java Potion.isSplash方法的具体用法?Java Potion.isSplash怎么用?Java Potion.isSplash使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在org.bukkit.potion.Potion的用法示例。


在下文中一共展示了Potion.isSplash方法的3个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Java代码示例。

示例1: parseItem

import org.bukkit.potion.Potion; //导入方法依赖的package包/类
public ItemStack parseItem(Element el, Material type, short damage) throws InvalidXMLException {
    int amount = XMLUtils.parseNumber(el.getAttribute("amount"), Integer.class, 1);

    // If the item is a potion with non-zero damage, and there is
    // no modern potion ID, decode the legacy damage value.
    final Potion legacyPotion;
    if(type == Material.POTION && damage > 0 && el.getAttribute("potion") == null) {
        try {
            legacyPotion = Potion.fromDamage(damage);
        } catch(IllegalArgumentException e) {
            throw new InvalidXMLException("Invalid legacy potion damage value " + damage + ": " + e.getMessage(), el, e);
        }

        // If the legacy splash bit is set, convert to a splash potion
        if(legacyPotion.isSplash()) {
            type = Material.SPLASH_POTION;
            legacyPotion.setSplash(false);
        }

        // Potions always have damage 0
        damage = 0;
    } else {
        legacyPotion = null;
    }

    ItemStack itemStack = new ItemStack(type, amount, damage);
    if(itemStack.getType() != type) {
        throw new InvalidXMLException("Invalid item/block", el);
    }

    final ItemMeta meta = itemStack.getItemMeta();
    if(meta != null) { // This happens if the item is "air"
        parseItemMeta(el, meta);

        // If we decoded a legacy potion, apply it now, but only if there are no custom effects.
        // This emulates the old behavior of custom effects overriding default effects.
        if(legacyPotion != null) {
            final PotionMeta potionMeta = (PotionMeta) meta;
            if(!potionMeta.hasCustomEffects()) {
                potionMeta.setBasePotionData(new PotionData(legacyPotion.getType(),
                                                            legacyPotion.hasExtendedDuration(),
                                                            legacyPotion.getLevel() == 2));
            }
        }

        itemStack.setItemMeta(meta);
    }

    return itemStack;
}
 
开发者ID:OvercastNetwork,项目名称:ProjectAres,代码行数:51,代码来源:GlobalItemParser.java

示例2: build

import org.bukkit.potion.Potion; //导入方法依赖的package包/类
public Potion build() {
   Potion potion = new Potion(type);
   potion.setLevel(this.level);
   if(potion.isSplash()) {
      potion.setHasExtendedDuration(this.extended);
   }
   return potion;
}
 
开发者ID:PaulBGD,项目名称:MiniMiniGames,代码行数:9,代码来源:PotionBuilder.java

示例3: fromPotion

import org.bukkit.potion.Potion; //导入方法依赖的package包/类
/**
    * This parses an Potion into an instance of PotionLayer. This lets you get the potion type, if the potion is strong, if the potion is long, if the potion is lingering, and if the potion is a
    * splash potion.
    * 
    * @param item
    * @return {@link PotionLayer}. If it fails to parse, or the item argument is not a valid potion this will return null.
    * @throws Exception
    */
   @Deprecated
   private static PotionLayer fromPotion(Potion potion) throws Exception {
PotionType type = PotionType.match(potion.getType());
if (type == null) {
    throw new Exception("no enum for " + potion.getType().name());
}
return new PotionLayer(type, potion.getLevel() > 1, potion.hasExtendedDuration(), false, potion.isSplash());
   }
 
开发者ID:AlexMl,项目名称:ZvP,代码行数:17,代码来源:PotionLayer.java


注:本文中的org.bukkit.potion.Potion.isSplash方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。