本文整理汇总了Java中org.bouncycastle.math.raw.Nat224.gte方法的典型用法代码示例。如果您正苦于以下问题：Java Nat224.gte方法的具体用法？Java Nat224.gte怎么用？Java Nat224.gte使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类org.bouncycastle.math.raw.Nat224的用法示例。
在下文中一共展示了Nat224.gte方法的12个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Java代码示例。
示例1: add
import org.bouncycastle.math.raw.Nat224; //导入方法依赖的package包/类
public static void add(int[] x, int[] y, int[] z)
{
int c = Nat224.add(x, y, z);
if (c != 0 || (z[6] == P6 && Nat224.gte(z, P)))
{
addPInvTo(z);
}
}
示例2: addOne
import org.bouncycastle.math.raw.Nat224; //导入方法依赖的package包/类
public static void addOne(int[] x, int[] z)
{
int c = Nat.inc(7, x, z);
if (c != 0 || (z[6] == P6 && Nat224.gte(z, P)))
{
addPInvTo(z);
}
}
示例3: fromBigInteger
import org.bouncycastle.math.raw.Nat224; //导入方法依赖的package包/类
public static int[] fromBigInteger(BigInteger x)
{
int[] z = Nat224.fromBigInteger(x);
if (z[6] == P6 && Nat224.gte(z, P))
{
Nat224.subFrom(P, z);
}
return z;
}
示例4: reduce32
import org.bouncycastle.math.raw.Nat224; //导入方法依赖的package包/类
public static void reduce32(int x, int[] z)
{
long cc = 0;
if (x != 0)
{
long xx07 = x & M;
cc += (z[0] & M) - xx07;
z[0] = (int)cc;
cc >>= 32;
if (cc != 0)
{
cc += (z[1] & M);
z[1] = (int)cc;
cc >>= 32;
cc += (z[2] & M);
z[2] = (int)cc;
cc >>= 32;
}
cc += (z[3] & M) + xx07;
z[3] = (int)cc;
cc >>= 32;
// assert cc == 0 || cc == 1;
}
if ((cc != 0 && Nat.incAt(7, z, 4) != 0)
|| (z[6] == P6 && Nat224.gte(z, P)))
{
addPInvTo(z);
}
}
示例5: twice
import org.bouncycastle.math.raw.Nat224; //导入方法依赖的package包/类
public static void twice(int[] x, int[] z)
{
int c = Nat.shiftUpBit(7, x, 0, z);
if (c != 0 || (z[6] == P6 && Nat224.gte(z, P)))
{
addPInvTo(z);
}
}
示例6: add
import org.bouncycastle.math.raw.Nat224; //导入方法依赖的package包/类
public static void add(int[] x, int[] y, int[] z)
{
int c = Nat224.add(x, y, z);
if (c != 0 || (z[6] == P6 && Nat224.gte(z, P)))
{
Nat.add33To(7, PInv33, z);
}
}
示例7: addOne
import org.bouncycastle.math.raw.Nat224; //导入方法依赖的package包/类
public static void addOne(int[] x, int[] z)
{
int c = Nat.inc(7, x, z);
if (c != 0 || (z[6] == P6 && Nat224.gte(z, P)))
{
Nat.add33To(7, PInv33, z);
}
}
示例8: reduce
import org.bouncycastle.math.raw.Nat224; //导入方法依赖的package包/类
public static void reduce(int[] xx, int[] z)
{
long cc = Nat224.mul33Add(PInv33, xx, 7, xx, 0, z, 0);
int c = Nat224.mul33DWordAdd(PInv33, cc, z, 0);
// assert c == 0L || c == 1L;
if (c != 0 || (z[6] == P6 && Nat224.gte(z, P)))
{
Nat.add33To(7, PInv33, z);
}
}
示例9: reduce32
import org.bouncycastle.math.raw.Nat224; //导入方法依赖的package包/类
public static void reduce32(int x, int[] z)
{
if ((x != 0 && Nat224.mul33WordAdd(PInv33, x, z, 0) != 0)
|| (z[6] == P6 && Nat224.gte(z, P)))
{
Nat.add33To(7, PInv33, z);
}
}
示例10: twice
import org.bouncycastle.math.raw.Nat224; //导入方法依赖的package包/类
public static void twice(int[] x, int[] z)
{
int c = Nat.shiftUpBit(7, x, 0, z);
if (c != 0 || (z[6] == P6 && Nat224.gte(z, P)))
{
Nat.add33To(7, PInv33, z);
}
}
示例11: fromBigInteger
import org.bouncycastle.math.raw.Nat224; //导入方法依赖的package包/类
public static int[] fromBigInteger(BigInteger x)
{
int[] z = Nat224.fromBigInteger(x);
if (z[6] == P6 && Nat224.gte(z, P))
{
Nat.add33To(7, PInv33, z);
}
return z;
}
示例12: reduce
import org.bouncycastle.math.raw.Nat224; //导入方法依赖的package包/类
public static void reduce(int[] xx, int[] z)
{
long xx10 = xx[10] & M, xx11 = xx[11] & M, xx12 = xx[12] & M, xx13 = xx[13] & M;
final long n = 1;
long t0 = (xx[7] & M) + xx11 - n;
long t1 = (xx[8] & M) + xx12;
long t2 = (xx[9] & M) + xx13;
long cc = 0;
cc += (xx[0] & M) - t0;
long z0 = cc & M;
cc >>= 32;
cc += (xx[1] & M) - t1;
z[1] = (int)cc;
cc >>= 32;
cc += (xx[2] & M) - t2;
z[2] = (int)cc;
cc >>= 32;
cc += (xx[3] & M) + t0 - xx10;
long z3 = cc & M;
cc >>= 32;
cc += (xx[4] & M) + t1 - xx11;
z[4] = (int)cc;
cc >>= 32;
cc += (xx[5] & M) + t2 - xx12;
z[5] = (int)cc;
cc >>= 32;
cc += (xx[6] & M) + xx10 - xx13;
z[6] = (int)cc;
cc >>= 32;
cc += n;
// assert cc >= 0;
z3 += cc;
z0 -= cc;
z[0] = (int)z0;
cc = z0 >> 32;
if (cc != 0)
{
cc += (z[1] & M);
z[1] = (int)cc;
cc >>= 32;
cc += (z[2] & M);
z[2] = (int)cc;
z3 += cc >> 32;
}
z[3] = (int)z3;
cc = z3 >> 32;
// assert cc == 0 || cc == 1;
if ((cc != 0 && Nat.incAt(7, z, 4) != 0)
|| (z[6] == P6 && Nat224.gte(z, P)))
{
addPInvTo(z);
}
}