本文整理汇总了Java中org.apache.hadoop.fs.AbstractFileSystem.getUri方法的典型用法代码示例。如果您正苦于以下问题：Java AbstractFileSystem.getUri方法的具体用法？Java AbstractFileSystem.getUri怎么用？Java AbstractFileSystem.getUri使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类org.apache.hadoop.fs.AbstractFileSystem的用法示例。
在下文中一共展示了AbstractFileSystem.getUri方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Java代码示例。
示例1: ChRootedFs
import org.apache.hadoop.fs.AbstractFileSystem; //导入方法依赖的package包/类
public ChRootedFs(final AbstractFileSystem fs, final Path theRoot)
throws URISyntaxException {
super(fs.getUri(), fs.getUri().getScheme(),
fs.getUri().getAuthority() != null, fs.getUriDefaultPort());
myFs = fs;
myFs.checkPath(theRoot);
chRootPathPart = new Path(myFs.getUriPath(theRoot));
chRootPathPartString = chRootPathPart.toUri().getPath();
/*
* We are making URI include the chrootedPath: e.g. file:///chrootedPath.
* This is questionable since Path#makeQualified(uri, path) ignores
* the pathPart of a uri. Since this class is internal we can ignore
* this issue but if we were to make it external then this needs
* to be resolved.
*/
// Handle the two cases:
// scheme:/// and scheme://authority/
myUri = new URI(myFs.getUri().toString() +
(myFs.getUri().getAuthority() == null ? "" : Path.SEPARATOR) +
chRootPathPart.toUri().getPath().substring(1));
super.checkPath(theRoot);
}