本文整理汇总了Java中org.apache.directory.api.ldap.model.exception.LdapReferralException.setResolvedDn方法的典型用法代码示例。如果您正苦于以下问题：Java LdapReferralException.setResolvedDn方法的具体用法？Java LdapReferralException.setResolvedDn怎么用？Java LdapReferralException.setResolvedDn使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类org.apache.directory.api.ldap.model.exception.LdapReferralException的用法示例。
在下文中一共展示了LdapReferralException.setResolvedDn方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Java代码示例。
示例1: buildReferralException
import org.apache.directory.api.ldap.model.exception.LdapReferralException; //导入方法依赖的package包/类
private LdapReferralException buildReferralException( Entry parentEntry, Dn childDn ) throws LdapException
{
// Get the Ref attributeType
Attribute refs = parentEntry.get( SchemaConstants.REF_AT );
List<String> urls = new ArrayList<String>();
try
{
// manage each Referral, building the correct URL for each of them
for ( Value<?> url : refs )
{
// we have to replace the parent by the referral
LdapUrl ldapUrl = new LdapUrl( url.getString() );
// We have a problem with the Dn : we can't use the UpName,
// as we may have some spaces around the ',' and '+'.
// So we have to take the Rdn one by one, and create a
// new Dn with the type and value UP form
Dn urlDn = ldapUrl.getDn().add( childDn );
ldapUrl.setDn( urlDn );
urls.add( ldapUrl.toString() );
}
}
catch ( LdapURLEncodingException luee )
{
throw new LdapOperationErrorException( luee.getMessage(), luee );
}
// Return with an exception
LdapReferralException lre = new LdapReferralException( urls );
lre.setRemainingDn( childDn );
lre.setResolvedDn( parentEntry.getDn() );
lre.setResolvedObject( parentEntry );
return lre;
}
示例2: buildReferralExceptionForSearch
import org.apache.directory.api.ldap.model.exception.LdapReferralException; //导入方法依赖的package包/类
private LdapReferralException buildReferralExceptionForSearch( Entry parentEntry, Dn childDn, SearchScope scope )
throws LdapException
{
// Get the Ref attributeType
Attribute refs = parentEntry.get( SchemaConstants.REF_AT );
List<String> urls = new ArrayList<String>();
// manage each Referral, building the correct URL for each of them
for ( Value<?> url : refs )
{
// we have to replace the parent by the referral
try
{
LdapUrl ldapUrl = new LdapUrl( url.getString() );
StringBuilder urlString = new StringBuilder();
if ( ( ldapUrl.getDn() == null ) || ( ldapUrl.getDn() == Dn.ROOT_DSE ) )
{
ldapUrl.setDn( parentEntry.getDn() );
}
else
{
// We have a problem with the Dn : we can't use the UpName,
// as we may have some spaces around the ',' and '+'.
// So we have to take the Rdn one by one, and create a
// new Dn with the type and value UP form
Dn urlDn = ldapUrl.getDn().add( childDn );
ldapUrl.setDn( urlDn );
}
urlString.append( ldapUrl.toString() ).append( "??" );
switch ( scope )
{
case OBJECT:
urlString.append( "base" );
break;
case SUBTREE:
urlString.append( "sub" );
break;
case ONELEVEL:
urlString.append( "one" );
break;
}
urls.add( urlString.toString() );
}
catch ( LdapURLEncodingException luee )
{
// The URL is not correct, returns it as is
urls.add( url.getString() );
}
}
// Return with an exception
LdapReferralException lre = new LdapReferralException( urls );
lre.setRemainingDn( childDn );
lre.setResolvedDn( parentEntry.getDn() );
lre.setResolvedObject( parentEntry );
return lre;
}