本文整理汇总了Java中org.apache.commons.math3.linear.FieldMatrix.power方法的典型用法代码示例。如果您正苦于以下问题：Java FieldMatrix.power方法的具体用法？Java FieldMatrix.power怎么用？Java FieldMatrix.power使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类org.apache.commons.math3.linear.FieldMatrix的用法示例。
在下文中一共展示了FieldMatrix.power方法的3个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Java代码示例。
示例1: exactK
import org.apache.commons.math3.linear.FieldMatrix; //导入方法依赖的package包/类
/**
* Calculates the exact value of {@code P(D_n < d)} using method described
* in [1] and {@link org.apache.commons.math3.fraction.BigFraction} (see
* above).
*
* @param d statistic
* @return the two-sided probability of {@code P(D_n < d)}
* @throws MathArithmeticException if algorithm fails to convert {@code h}
* to a {@link org.apache.commons.math3.fraction.BigFraction} in expressing
* {@code d} as {@code (k - h) / m} for integer {@code k, m} and
* {@code 0 <= h < 1}.
*/
private double exactK(double d) throws MathArithmeticException {
final int k = (int) FastMath.ceil(n * d);
final FieldMatrix<BigFraction> H = this.createH(d);
final FieldMatrix<BigFraction> Hpower = H.power(n);
BigFraction pFrac = Hpower.getEntry(k - 1, k - 1);
for (int i = 1; i <= n; ++i) {
pFrac = pFrac.multiply(i).divide(n);
}
/*
* BigFraction.doubleValue converts numerator to double and the
* denominator to double and divides afterwards. That gives NaN quite
* easy. This does not (scale is the number of digits):
*/
return pFrac.bigDecimalValue(20, BigDecimal.ROUND_HALF_UP).doubleValue();
}
示例2: exactK
import org.apache.commons.math3.linear.FieldMatrix; //导入方法依赖的package包/类
/**
* Calculates the exact value of {@code P(D_n < d)} using the method described in [1] (reference
* in class javadoc above) and {@link org.apache.commons.math3.fraction.BigFraction} (see
* above).
*
* @param d statistic
* @param n sample size
* @return the two-sided probability of \(P(D_n < d)\)
* @throws MathArithmeticException if algorithm fails to convert {@code h} to a
* {@link org.apache.commons.math3.fraction.BigFraction} in expressing {@code d} as \((k
* - h) / m\) for integer {@code k, m} and \(0 \le h < 1\).
*/
private double exactK(double d, int n)
throws MathArithmeticException {
final int k = (int) Math.ceil(n * d);
final FieldMatrix<BigFraction> H = this.createExactH(d, n);
final FieldMatrix<BigFraction> Hpower = H.power(n);
BigFraction pFrac = Hpower.getEntry(k - 1, k - 1);
for (int i = 1; i <= n; ++i) {
pFrac = pFrac.multiply(i).divide(n);
}
/*
* BigFraction.doubleValue converts numerator to double and the denominator to double and
* divides afterwards. That gives NaN quite easy. This does not (scale is the number of
* digits):
*/
return pFrac.bigDecimalValue(20, BigDecimal.ROUND_HALF_UP).doubleValue();
}
示例3: exactK
import org.apache.commons.math3.linear.FieldMatrix; //导入方法依赖的package包/类
/**
* Calculates the exact value of {@code P(D_n < d)} using method described
* in [1] and {@link org.apache.commons.math3.fraction.BigFraction} (see
* above).
*
* @param d statistic
* @return the two-sided probability of {@code P(D_n < d)}
* @throws MathArithmeticException if algorithm fails to convert {@code h}
* to a {@link org.apache.commons.math3.fraction.BigFraction} in expressing
* {@code d} as {@code (k - h) / m} for integer {@code k, m} and
* {@code 0 <= h < 1}.
*/
private double exactK(double d) throws MathArithmeticException {
final int k = (int) Math.ceil(n * d);
final FieldMatrix<BigFraction> H = this.createH(d);
final FieldMatrix<BigFraction> Hpower = H.power(n);
BigFraction pFrac = Hpower.getEntry(k - 1, k - 1);
for (int i = 1; i <= n; ++i) {
pFrac = pFrac.multiply(i).divide(n);
}
/*
* BigFraction.doubleValue converts numerator to double and the
* denominator to double and divides afterwards. That gives NaN quite
* easy. This does not (scale is the number of digits):
*/
return pFrac.bigDecimalValue(20, BigDecimal.ROUND_HALF_UP).doubleValue();
}