Java PointerTargetNodeList.get方法代码示例

import net.didion.jwnl.data.list.PointerTargetNodeList; //导入方法依赖的package包/类
/** Get the group that this verb belongs to. */
public PointerTargetNodeList getVerbGroup(Synset synset) throws JWNLException {
	// We need to go through all this hastle because
	// 1. a verb does not always have links to all the verbs in its group
	// 2. two verbs in the same group sometimes have reciprocal links, and we want
	//    to make sure that each verb synset appears in the final list only once

	PointerTargetNodeList nodes = new PointerTargetNodeList();
	nodes.add(new PointerTargetNode(synset, PointerType.VERB_GROUP));
	int maxIndex = 0;
	int index = -1;
	do {
		index++;
		PointerTargetNode node = (PointerTargetNode) nodes.get(index);
		for (Iterator itr = getPointerTargets(node.getSynset(), PointerType.VERB_GROUP).iterator(); itr.hasNext();) {
			PointerTargetNode testNode = (PointerTargetNode) itr.next();
			if (!nodes.contains(testNode)) {
				nodes.add(testNode);
				maxIndex++;
			}
		}
	} while (index < maxIndex);

	return nodes;
}
 

import net.didion.jwnl.data.list.PointerTargetNodeList; //导入方法依赖的package包/类
/**
 * Looks up the synsets that correspond to the nodes in a node list.
 * 
 * @param nodes node list
 * @return synsets
 */
private static Synset[] getSynsets(PointerTargetNodeList nodes) {
	Synset[] synsets = new Synset[nodes.size()];
	
	for (int i = 0; i < nodes.size(); i++) {
		PointerTargetNode node  = (PointerTargetNode) nodes.get(i);
		synsets[i] = node.getSynset();
	}
	
	return synsets;
}
 

import net.didion.jwnl.data.list.PointerTargetNodeList; //导入方法依赖的package包/类
/**
 * Find a relationship between two asymmetric lists ordered from deepest
 * to shallowest ancestor. Each node has it's PointerType set to the kind of
 * relationship one need to follow to get from it to the next node in the list.
 * Take the dog/cat relationship. To get to carnivore, a hypernym relationship
 * must be used to get from dog to carnivore, but then a hyponym relationship
 * must be used to get from carnivore to cat. The list will look like this:
 * dog(hyper) -> canine(hyper) -> carnivore(hypo) -> feline(hypo) -> cat(hypo).
 * In this instance, cat's PointerType is meaningless, but is kept to facilitate
 * things like reversing the relationship (which just involves setting each node's
 * pointer type to the symmetric type of its current type.
 */
private Relationship findAsymmetricRelationship(
    PointerTargetNodeList sourceNodes, PointerTargetNodeList targetNodes,
    PointerType type, Synset sourceSynset, Synset targetSynset) {

	// If the deepest ancestors of the words are not the same,
	// then there is no relationship between the words.
	if (!sourceNodes.get(0).equals(targetNodes.get(0))) return null;

	PointerTargetNodeList relationship = new PointerTargetNodeList();
	int targetStart = 0;
	int commonParentIndex = 0;
	for (int i = sourceNodes.size() - 1; i >= 0; i--) {
		PointerTargetNode testNode = (PointerTargetNode)sourceNodes.get(i);
		int idx = targetNodes.indexOf(testNode);
		if (idx >= 0) {
			targetStart = idx;
			break;
		} else {
			relationship.add(testNode.clone());
			commonParentIndex++;
		}
	}
	for (int i = targetStart; i < targetNodes.size(); i++) {
		PointerTargetNode node = (PointerTargetNode)((PointerTargetNode)targetNodes.get(i)).clone();
		node.setType(type.getSymmetricType());
		relationship.add(node);
	}
	return new AsymmetricRelationship(type, relationship, commonParentIndex, sourceSynset, targetSynset);
}