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Java Node.getLastChild方法代码示例

本文整理汇总了Java中mf.org.w3c.dom.Node.getLastChild方法的典型用法代码示例。如果您正苦于以下问题:Java Node.getLastChild方法的具体用法?Java Node.getLastChild怎么用?Java Node.getLastChild使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在mf.org.w3c.dom.Node的用法示例。


在下文中一共展示了Node.getLastChild方法的7个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Java代码示例。

示例1: getLastElementChild

import mf.org.w3c.dom.Node; //导入方法依赖的package包/类
private Element getLastElementChild(Node n) {
    final Node top = n;
    while (n != null) {
        if (n.getNodeType() == Node.ELEMENT_NODE) {
            return (Element) n;
        }
        Node next = n.getLastChild();
        while (next == null) {         
            if (top == n) {
                break;
            }
            next = n.getPreviousSibling();
            if (next == null) {
                n = n.getParentNode();
                if (n == null || top == n) {
                    return null;
                }
            }
        }
        n = next;
    }
    return null;
}
 
开发者ID:MaTriXy,项目名称:xerces-for-android,代码行数:24,代码来源:ElementImpl.java

示例2: getLastChildElement

import mf.org.w3c.dom.Node; //导入方法依赖的package包/类
/** Finds and returns the last child element node. 
 *  Overload previous method for non-Xerces node impl.
 */
public static Element getLastChildElement(Node parent) {
    
    // search for node
    Node child = parent.getLastChild();
    while (child != null) {
        if (child.getNodeType() == Node.ELEMENT_NODE) {
            return (Element)child;
        }
        child = child.getPreviousSibling();
    }
    
    // not found
    return null;
    
}
 
开发者ID:MaTriXy,项目名称:xerces-for-android,代码行数:19,代码来源:DOMUtil.java

示例3: getLastVisibleChildElement

import mf.org.w3c.dom.Node; //导入方法依赖的package包/类
/** Finds and returns the last visible child element node. */
public static Element getLastVisibleChildElement(Node parent) {
    
    // search for node
    Node child = parent.getLastChild();
    while (child != null) {
        if (child.getNodeType() == Node.ELEMENT_NODE &&
                !isHidden(child)) {
            return (Element)child;
        }
        child = child.getPreviousSibling();
    }
    
    // not found
    return null;
    
}
 
开发者ID:MaTriXy,项目名称:xerces-for-android,代码行数:18,代码来源:DOMUtil.java

示例4: getLastChildElementNS

import mf.org.w3c.dom.Node; //导入方法依赖的package包/类
/** Finds and returns the last child node with the given qualified name. */
public static Element getLastChildElementNS(Node parent,
        String uri, String localpart) {
    
    // search for node
    Node child = parent.getLastChild();
    while (child != null) {
        if (child.getNodeType() == Node.ELEMENT_NODE) {
            String childURI = child.getNamespaceURI();
            if (childURI != null && childURI.equals(uri) &&
                    child.getLocalName().equals(localpart)) {
                return (Element)child;
            }
        }
        child = child.getPreviousSibling();
    }
    
    // not found
    return null;
    
}
 
开发者ID:MaTriXy,项目名称:xerces-for-android,代码行数:22,代码来源:DOMUtil.java

示例5: previousNode

import mf.org.w3c.dom.Node; //导入方法依赖的package包/类
/** The method previousNode(Node) returns the previous node 
 *  from the actual DOM tree.
 */
Node previousNode(Node node) {
    
    Node result;
    
    // if we're at the root, return null.
    if (node == fRoot) return null;
    
    // get sibling
    result = node.getPreviousSibling();
    if (result == null) {
        //if 1st sibling, return parent
        result = node.getParentNode();
        return result;
    }
    
    // if sibling has children, keep getting last child of child.
    if (result.hasChildNodes()
        && !(!fEntityReferenceExpansion
            && result != null
            && result.getNodeType() == Node.ENTITY_REFERENCE_NODE)) 
   
    {
        while (result.hasChildNodes()) {
            result = result.getLastChild();
        }
    }          
        
    return result;
}
 
开发者ID:MaTriXy,项目名称:xerces-for-android,代码行数:33,代码来源:NodeIteratorImpl.java

示例6: getLastChild

import mf.org.w3c.dom.Node; //导入方法依赖的package包/类
/** Internal function.
 *  Return the last child Node, from the input node
 *  after applying filter, whatToshow.
 *  The current node is not consulted or set.
 */
Node getLastChild(Node node) {
    
    if (node == null) return null;
    
    if ( !fEntityReferenceExpansion
         && node.getNodeType() == Node.ENTITY_REFERENCE_NODE)
        return null;
        
    Node newNode = node.getLastChild();
    if (newNode == null)  return null; 
    
    int accept = acceptNode(newNode);
    
    if (accept == NodeFilter.FILTER_ACCEPT)
        return newNode;
    else 
    if (accept == NodeFilter.FILTER_SKIP
        && newNode.hasChildNodes()) 
    {
        Node lChild = getLastChild(newNode);
        if (lChild == null) {
            return getPreviousSibling(newNode, node);
        }
        return lChild;
    }
    else 
    //if (accept == NodeFilter.REJECT_NODE) 
    {
        return getPreviousSibling(newNode, node);
    }
    
    
}
 
开发者ID:MaTriXy,项目名称:xerces-for-android,代码行数:39,代码来源:TreeWalkerImpl.java

示例7: synchronizeData

import mf.org.w3c.dom.Node; //导入方法依赖的package包/类
/** Synchronizes the node's data. */
protected void synchronizeData() {

    // no need to sync in the future
    needsSyncData(false);

    // fluff up enough nodes to fill identifiers hash
    if (fIdElement != null) {

        // REVISIT: There has to be a more efficient way of
        //          doing this. But keep in mind that the
        //          tree can have been altered and re-ordered
        //          before all of the element nodes with ID
        //          attributes have been registered. For now
        //          this is reasonable and safe. -Ac

        IntVector path = new IntVector();
        for (int i = 0; i < fIdCount; i++) {

            // ignore if it's already been registered
            int elementNodeIndex = fIdElement[i];
            String idName      = fIdName[i];
            if (idName == null) {
                continue;
            }

            // find path from this element to the root
            path.removeAllElements();
            int index = elementNodeIndex;
            do {
                path.addElement(index);
                int pchunk = index >> CHUNK_SHIFT;
                int pindex = index & CHUNK_MASK;
                index = getChunkIndex(fNodeParent, pchunk, pindex);
            } while (index != -1);

            // Traverse path (backwards), fluffing the elements
            // along the way. When this loop finishes, "place"
            // will contain the reference to the element node
            // we're interested in. -Ac
            Node place = this;
            for (int j = path.size() - 2; j >= 0; j--) {
                index = path.elementAt(j);
                Node child = place.getLastChild();
                while (child != null) {
                    if (child instanceof DeferredNode) {
                        int nodeIndex =
                            ((DeferredNode)child).getNodeIndex();
                        if (nodeIndex == index) {
                            place = child;
                            break;
                        }
                    }
                    child = child.getPreviousSibling();
                }
            }

            // register the element
            Element element = (Element)place;
            putIdentifier0(idName, element);
            fIdName[i] = null;

            // see if there are more IDs on this element
            while (i + 1 < fIdCount &&
                fIdElement[i + 1] == elementNodeIndex) {
                idName = fIdName[++i];
                if (idName == null) {
                    continue;
                }
                putIdentifier0(idName, element);
            }
        }

    } // if identifiers

}
 
开发者ID:MaTriXy,项目名称:xerces-for-android,代码行数:77,代码来源:DeferredDocumentImpl.java


注:本文中的mf.org.w3c.dom.Node.getLastChild方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。