本文整理汇总了Java中jdk.nashorn.internal.ir.Symbol.isInternal方法的典型用法代码示例。如果您正苦于以下问题：Java Symbol.isInternal方法的具体用法？Java Symbol.isInternal怎么用？Java Symbol.isInternal使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类jdk.nashorn.internal.ir.Symbol的用法示例。
在下文中一共展示了Symbol.isInternal方法的5个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Java代码示例。
示例1: enterBinaryNode
import jdk.nashorn.internal.ir.Symbol; //导入方法依赖的package包/类
@Override
public boolean enterBinaryNode(final BinaryNode binaryNode) {
if(binaryNode.isAssignment()) {
final Expression lhs = binaryNode.lhs();
if(!binaryNode.isSelfModifying()) {
tagNeverOptimistic(lhs);
}
if(lhs instanceof IdentNode) {
final Symbol symbol = ((IdentNode)lhs).getSymbol();
// Assignment to internal symbols is never optimistic, except for self-assignment expressions
if(symbol.isInternal() && !binaryNode.rhs().isSelfModifying()) {
tagNeverOptimistic(binaryNode.rhs());
}
}
} else if(binaryNode.isTokenType(TokenType.INSTANCEOF)) {
tagNeverOptimistic(binaryNode.lhs());
tagNeverOptimistic(binaryNode.rhs());
}
return true;
}
示例2: enterBinaryNode
import jdk.nashorn.internal.ir.Symbol; //导入方法依赖的package包/类
@Override
public boolean enterBinaryNode(final BinaryNode binaryNode) {
if(binaryNode.isAssignment()) {
final Expression lhs = binaryNode.lhs();
if(!binaryNode.isSelfModifying()) {
tagNeverOptimistic(lhs);
}
if(lhs instanceof IdentNode) {
final Symbol symbol = ((IdentNode)lhs).getSymbol();
// Assignment to internal symbols is never optimistic, except for self-assignment expressions
if(symbol.isInternal() && !binaryNode.rhs().isSelfModifying()) {
tagNeverOptimistic(binaryNode.rhs());
}
}
} else if(binaryNode.isTokenType(TokenType.INSTANCEOF)
|| binaryNode.isTokenType(TokenType.EQ_STRICT)
|| binaryNode.isTokenType(TokenType.NE_STRICT)) {
tagNeverOptimistic(binaryNode.lhs());
tagNeverOptimistic(binaryNode.rhs());
}
return true;
}
示例3: symbolNeedsToBeScope
import jdk.nashorn.internal.ir.Symbol; //导入方法依赖的package包/类
/**
* Determines if the symbol has to be a scope symbol. In general terms, it has to be a scope symbol if it can only
* be reached from the current block by traversing a function node, a split node, or a with node.
* @param symbol the symbol checked for needing to be a scope symbol
* @return true if the symbol has to be a scope symbol.
*/
private boolean symbolNeedsToBeScope(final Symbol symbol) {
if (symbol.isThis() || symbol.isInternal()) {
return false;
}
final FunctionNode func = lc.getCurrentFunction();
if ( func.allVarsInScope() || (!symbol.isBlockScoped() && func.isProgram())) {
return true;
}
boolean previousWasBlock = false;
for (final Iterator<LexicalContextNode> it = lc.getAllNodes(); it.hasNext();) {
final LexicalContextNode node = it.next();
if (node instanceof FunctionNode || isSplitArray(node)) {
// We reached the function boundary or a splitting boundary without seeing a definition for the symbol.
// It needs to be in scope.
return true;
} else if (node instanceof WithNode) {
if (previousWasBlock) {
// We reached a WithNode; the symbol must be scoped. Note that if the WithNode was not immediately
// preceded by a block, this means we're currently processing its expression, not its body,
// therefore it doesn't count.
return true;
}
previousWasBlock = false;
} else if (node instanceof Block) {
if (((Block)node).getExistingSymbol(symbol.getName()) == symbol) {
// We reached the block that defines the symbol without reaching either the function boundary, or a
// WithNode. The symbol need not be scoped.
return false;
}
previousWasBlock = true;
} else {
previousWasBlock = false;
}
}
throw new AssertionError();
}
示例4: isInternalExpression
import jdk.nashorn.internal.ir.Symbol; //导入方法依赖的package包/类
/**
* An internal expression has a symbol that is tagged internal. Check if
* this is such a node
*
* @param expression expression to check for internal symbol
* @return true if internal, false otherwise
*/
private static boolean isInternalExpression(final Expression expression) {
if (!(expression instanceof IdentNode)) {
return false;
}
final Symbol symbol = ((IdentNode)expression).getSymbol();
return symbol != null && symbol.isInternal();
}
示例5: symbolNeedsToBeScope
import jdk.nashorn.internal.ir.Symbol; //导入方法依赖的package包/类
/**
* Determines if the symbol has to be a scope symbol. In general terms, it has to be a scope symbol if it can only
* be reached from the current block by traversing a function node, a split node, or a with node.
* @param symbol the symbol checked for needing to be a scope symbol
* @return true if the symbol has to be a scope symbol.
*/
private boolean symbolNeedsToBeScope(final Symbol symbol) {
if (symbol.isThis() || symbol.isInternal()) {
return false;
}
final FunctionNode func = lc.getCurrentFunction();
if ( func.allVarsInScope() || (!symbol.isBlockScoped() && func.isProgram())) {
return true;
}
boolean previousWasBlock = false;
for (final Iterator<LexicalContextNode> it = lc.getAllNodes(); it.hasNext();) {
final LexicalContextNode node = it.next();
if (node instanceof FunctionNode || isSplitLiteral(node)) {
// We reached the function boundary or a splitting boundary without seeing a definition for the symbol.
// It needs to be in scope.
return true;
} else if (node instanceof WithNode) {
if (previousWasBlock) {
// We reached a WithNode; the symbol must be scoped. Note that if the WithNode was not immediately
// preceded by a block, this means we're currently processing its expression, not its body,
// therefore it doesn't count.
return true;
}
previousWasBlock = false;
} else if (node instanceof Block) {
if (((Block)node).getExistingSymbol(symbol.getName()) == symbol) {
// We reached the block that defines the symbol without reaching either the function boundary, or a
// WithNode. The symbol need not be scoped.
return false;
}
previousWasBlock = true;
} else {
previousWasBlock = false;
}
}
throw new AssertionError();
}