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Java LdapName.getPrefix方法代码示例

本文整理汇总了Java中javax.naming.ldap.LdapName.getPrefix方法的典型用法代码示例。如果您正苦于以下问题:Java LdapName.getPrefix方法的具体用法?Java LdapName.getPrefix怎么用?Java LdapName.getPrefix使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在javax.naming.ldap.LdapName的用法示例。


在下文中一共展示了LdapName.getPrefix方法的4个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Java代码示例。

示例1: convertToRelativeName

import javax.naming.ldap.LdapName; //导入方法依赖的package包/类
public static LdapName convertToRelativeName(LdapName dn, LdapName base)
        throws NamingException {
    if (base.size() == 0) {
        return dn;
    }

    if (dn.size() < base.size()) {
        // TODO add error message
        throw new NamingException("");
    }

    Name prefix = dn.getPrefix(base.size());
    if (!prefix.equals(base)) {
        // TODO add error message
        throw new NamingException("");
    }

    return (LdapName) dn.getSuffix(base.size());

}
 
开发者ID:shannah,项目名称:cn1,代码行数:21,代码来源:LdapUtils.java

示例2: testGetPrefix003

import javax.naming.ldap.LdapName; //导入方法依赖的package包/类
/**
 * <p>
 * Test method for 'javax.naming.ldap.LdapName.getPrefix(int)'
 * </p>
 * <p>
 * Here we are testing if this method correctly returns a Name that is a
 * prefix of this LdapName.
 * </p>
 * <p>
 * The expected result is an IndexOutOfBaundsException if the range is not
 * in [0,size()].
 * </p>
 */
public void testGetPrefix003() throws Exception {
    String test = "t=test";
    try {
        LdapName ln = new LdapName(test);
        ln.getPrefix(-1);
        fail("IndexOutOfBoundsException expected");
    } catch (IndexOutOfBoundsException e) {}

}
 
开发者ID:shannah,项目名称:cn1,代码行数:23,代码来源:LdapNameTest.java

示例3: testGetPrefix004

import javax.naming.ldap.LdapName; //导入方法依赖的package包/类
/**
 * <p>
 * Test method for 'javax.naming.ldap.LdapName.getPrefix(int)'
 * </p>
 * <p>
 * Here we are testing if this method correctly returns a Name that is a
 * prefix of this LdapName.
 * </p>
 * <p>
 * The expected result is an IndexOutOfBaundsException if the range is not
 * in [0,size()].
 * </p>
 */
public void testGetPrefix004() throws Exception {
    String test = "t=test";
    try {
        LdapName ln = new LdapName(test);
        ln.getPrefix(2);
        fail("IndexOutOfBoundsException expected");
    } catch (IndexOutOfBoundsException e) {}
}
 
开发者ID:shannah,项目名称:cn1,代码行数:22,代码来源:LdapNameTest.java

示例4: testStartsWithName004

import javax.naming.ldap.LdapName; //导入方法依赖的package包/类
/**
 * <p>
 * Test method for 'javax.naming.ldap.LdapName.startsWith(Name)'
 * </p>
 * <p>
 * Here we are testing if this method correctly returns true if an LdapName
 * starts with the given prefix.
 * </p>
 * <p>
 * The expected result is a false.
 * </p>
 */
public void testStartsWithName004() throws Exception {
    String test = "t=test,cn=test,o=other";
    LdapName ln = new LdapName(test);
    LdapName n = (LdapName) ln.getPrefix(ln.size());
    assertTrue(ln.startsWith(n));
}
 
开发者ID:shannah,项目名称:cn1,代码行数:19,代码来源:LdapNameTest.java


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