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Java ObjectName.unquote方法代码示例

本文整理汇总了Java中javax.management.ObjectName.unquote方法的典型用法代码示例。如果您正苦于以下问题:Java ObjectName.unquote方法的具体用法?Java ObjectName.unquote怎么用?Java ObjectName.unquote使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在javax.management.ObjectName的用法示例。


在下文中一共展示了ObjectName.unquote方法的5个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Java代码示例。

示例1: removeResourceLink

import javax.management.ObjectName; //导入方法依赖的package包/类
/**
 * Remove any resource link reference with the specified name.
 *
 * @param resourceLinkName Name of the resource link reference to remove
 */
public void removeResourceLink(String resourceLinkName) {

    resourceLinkName = ObjectName.unquote(resourceLinkName);
    NamingResources nresources = (NamingResources) this.resource;
    if (nresources == null) {
        return;
    }
    ContextResourceLink resourceLink = 
                        nresources.findResourceLink(resourceLinkName);
    if (resourceLink == null) {
        throw new IllegalArgumentException
            ("Invalid resource Link name '" + resourceLinkName + "'");
    }
    nresources.removeResourceLink(resourceLinkName);
}
 
开发者ID:liaokailin,项目名称:tomcat7,代码行数:21,代码来源:NamingResourcesMBean.java

示例2: removeResource

import javax.management.ObjectName; //导入方法依赖的package包/类
/**
 * Remove any resource reference with the specified name.
 *
 * @param resourceName Name of the resource reference to remove
 */
public void removeResource(String resourceName) {

    resourceName = ObjectName.unquote(resourceName);
    NamingResources nresources = getNamingResources();
    if (nresources == null) {
        return;
    }
    ContextResource resource = nresources.findResource(resourceName);
    if (resource == null) {
        throw new IllegalArgumentException
            ("Invalid resource name '" + resourceName + "'");
    }
    nresources.removeResource(resourceName);
}
 
开发者ID:lamsfoundation,项目名称:lams,代码行数:20,代码来源:StandardContextMBean.java

示例3: removeResourceLink

import javax.management.ObjectName; //导入方法依赖的package包/类
/**
 * Remove any resource link with the specified name.
 *
 * @param resourceLinkName Name of the resource reference to remove
 */
public void removeResourceLink(String resourceLinkName) {

    resourceLinkName = ObjectName.unquote(resourceLinkName);
    NamingResources nresources = getNamingResources();
    if (nresources == null) {
        return;
    }
    ContextResourceLink resource = nresources.findResourceLink(resourceLinkName);
    if (resource == null) {
        throw new IllegalArgumentException
            ("Invalid resource name '" + resourceLinkName + "'");
    }
    nresources.removeResourceLink(resourceLinkName);
}
 
开发者ID:lamsfoundation,项目名称:lams,代码行数:20,代码来源:StandardContextMBean.java

示例4: makeCompliantRegionPath

import javax.management.ObjectName; //导入方法依赖的package包/类
public static String makeCompliantRegionPath(String value) {
  if (isQuoted(value)) {
    value = ObjectName.unquote(value);
  } else {
    if (containsSpecialChar(value)) {
      value = ObjectName.quote(value);
    }
  }
  return value;
}
 
开发者ID:ampool,项目名称:monarch,代码行数:11,代码来源:MBeanJMXAdapter.java

示例5: removeResourceLink

import javax.management.ObjectName; //导入方法依赖的package包/类
/**
 * Remove any resource link reference with the specified name.
 *
 * @param resourceLinkName
 *            Name of the resource link reference to remove
 */
public void removeResourceLink(String resourceLinkName) {

	resourceLinkName = ObjectName.unquote(resourceLinkName);
	NamingResources nresources = (NamingResources) this.resource;
	if (nresources == null) {
		return;
	}
	ContextResourceLink resourceLink = nresources.findResourceLink(resourceLinkName);
	if (resourceLink == null) {
		throw new IllegalArgumentException("Invalid resource Link name '" + resourceLinkName + "'");
	}
	nresources.removeResourceLink(resourceLinkName);
}
 
开发者ID:how2j,项目名称:lazycat,代码行数:20,代码来源:NamingResourcesMBean.java


注:本文中的javax.management.ObjectName.unquote方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。