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Java Stack.removeAllElements方法代码示例

本文整理汇总了Java中java.util.Stack.removeAllElements方法的典型用法代码示例。如果您正苦于以下问题:Java Stack.removeAllElements方法的具体用法?Java Stack.removeAllElements怎么用?Java Stack.removeAllElements使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在java.util.Stack的用法示例。


在下文中一共展示了Stack.removeAllElements方法的2个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Java代码示例。

示例1: getNodeForPath

import java.util.Stack; //导入方法依赖的package包/类
/**
  * Returns the TreeStateNode identified by path.  This mirrors
  * the behavior of getNodeForPath, but tries to take advantage of
  * path if it is an instance of AbstractTreePath.
  */
private TreeStateNode getNodeForPath(TreePath path,
                                       boolean onlyIfVisible,
                                       boolean shouldCreate) {
    if(path != null) {
        TreeStateNode      node;

        node = getMapping(path);
        if(node != null) {
            if(onlyIfVisible && !node.isVisible())
                return null;
            return node;
        }

        // Check all the parent paths, until a match is found.
        Stack<TreePath> paths;

        if(tempStacks.size() == 0) {
            paths = new Stack<TreePath>();
        }
        else {
            paths = tempStacks.pop();
        }

        try {
            paths.push(path);
            path = path.getParentPath();
            node = null;
            while(path != null) {
                node = getMapping(path);
                if(node != null) {
                    // Found a match, create entries for all paths in
                    // paths.
                    while(node != null && paths.size() > 0) {
                        path = paths.pop();
                        node.getLoadedChildren(shouldCreate);

                        int            childIndex = treeModel.
                                  getIndexOfChild(node.getUserObject(),
                                              path.getLastPathComponent());

                        if(childIndex == -1 ||
                           childIndex >= node.getChildCount() ||
                           (onlyIfVisible && !node.isVisible())) {
                            node = null;
                        }
                        else
                            node = (TreeStateNode)node.getChildAt
                                           (childIndex);
                    }
                    return node;
                }
                paths.push(path);
                path = path.getParentPath();
            }
        }
        finally {
            paths.removeAllElements();
            tempStacks.push(paths);
        }
        // If we get here it means they share a different root!
        // We could throw an exception...
    }
    return null;
}
 
开发者ID:SunburstApps,项目名称:OpenJSharp,代码行数:70,代码来源:VariableHeightLayoutCache.java

示例2: getNodeForPath

import java.util.Stack; //导入方法依赖的package包/类
/**
 * Messages getTreeNodeForPage(path, onlyIfVisible, shouldCreate,
 * path.length) as long as path is non-null and the length is {@literal >} 0.
 * Otherwise returns null.
 */
private FHTreeStateNode getNodeForPath(TreePath path,
                                         boolean onlyIfVisible,
                                         boolean shouldCreate) {
    if(path != null) {
        FHTreeStateNode      node;

        node = getMapping(path);
        if(node != null) {
            if(onlyIfVisible && !node.isVisible())
                return null;
            return node;
        }
        if(onlyIfVisible)
            return null;

        // Check all the parent paths, until a match is found.
        Stack<TreePath> paths;

        if(tempStacks.size() == 0) {
            paths = new Stack<TreePath>();
        }
        else {
            paths = tempStacks.pop();
        }

        try {
            paths.push(path);
            path = path.getParentPath();
            node = null;
            while(path != null) {
                node = getMapping(path);
                if(node != null) {
                    // Found a match, create entries for all paths in
                    // paths.
                    while(node != null && paths.size() > 0) {
                        path = paths.pop();
                        node = node.createChildFor(path.
                                                   getLastPathComponent());
                    }
                    return node;
                }
                paths.push(path);
                path = path.getParentPath();
            }
        }
        finally {
            paths.removeAllElements();
            tempStacks.push(paths);
        }
        // If we get here it means they share a different root!
        return null;
    }
    return null;
}
 
开发者ID:SunburstApps,项目名称:OpenJSharp,代码行数:60,代码来源:FixedHeightLayoutCache.java


注:本文中的java.util.Stack.removeAllElements方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。