本文整理汇总了Java中java.awt.geom.Path2D.contains方法的典型用法代码示例。如果您正苦于以下问题：Java Path2D.contains方法的具体用法？Java Path2D.contains怎么用？Java Path2D.contains使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类java.awt.geom.Path2D的用法示例。
在下文中一共展示了Path2D.contains方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Java代码示例。
示例1: testContains
import java.awt.geom.Path2D; //导入方法依赖的package包/类
static void testContains(Path2D pathA, Path2D pathB) {
boolean resA = pathA.contains(pt2d);
boolean resB = pathB.contains(pt2d);
if (resA != resB) {
throw new IllegalStateException("Contains(pt) are not equals ["
+ resA + "|" + resB + "] !");
}
resA = pathA.contains(pt2d.getX(), pt2d.getY());
resB = pathB.contains(pt2d.getX(), pt2d.getY());
if (resA != resB) {
throw new IllegalStateException("Contains(x,y) are not equals ["
+ resA + "|" + resB + "] !");
}
resA = pathA.contains(rect2d);
resB = pathB.contains(rect2d);
if (resA != resB) {
throw new IllegalStateException("Contains(rect2d) are not equals ["
+ resA + "|" + resB + "] !");
}
resA = pathA.contains(1.0, 2.0, 13.0, 17.0);
resB = pathB.contains(1.0, 2.0, 13.0, 17.0);
if (resA != resB) {
throw new IllegalStateException("Contains(doubles) are not equals ["
+ resA + "|" + resB + "] !");
}
log("testContains: passed.");
}