本文整理汇总了Java中geometry.planar.IntOctagon.normalize方法的典型用法代码示例。如果您正苦于以下问题：Java IntOctagon.normalize方法的具体用法？Java IntOctagon.normalize怎么用？Java IntOctagon.normalize使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类geometry.planar.IntOctagon的用法示例。
在下文中一共展示了IntOctagon.normalize方法的3个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Java代码示例。
示例1: insert_incomplete_room
import geometry.planar.IntOctagon; //导入方法依赖的package包/类
/**
* Inserts a new incomplete room with an octagon shape.
*/
private void insert_incomplete_room(AutorouteEngine p_autoroute_engine, int p_lx, int p_ly, int p_rx, int p_uy,
int p_ulx, int p_lrx, int p_llx, int p_urx)
{
IntOctagon new_incomplete_room_shape = new IntOctagon(p_lx, p_ly, p_rx, p_uy, p_ulx, p_lrx, p_llx, p_urx);
new_incomplete_room_shape = new_incomplete_room_shape.normalize();
if (new_incomplete_room_shape.dimension() == 2)
{
IntOctagon new_contained_shape = this.room_shape.intersection(new_incomplete_room_shape);
if (!new_contained_shape.is_empty())
{
int door_dimension = new_contained_shape.dimension();
if (door_dimension > 0)
{
FreeSpaceExpansionRoom new_room =
p_autoroute_engine.add_incomplete_expansion_room(new_incomplete_room_shape, this.from_room.get_layer(), new_contained_shape);
ExpansionDoor new_door = new ExpansionDoor(this.completed_room, new_room, door_dimension);
this.completed_room.add_door(new_door);
new_room.add_door(new_door);
}
}
}
}
示例2: calc_outside_restrained_shape
import geometry.planar.IntOctagon; //导入方法依赖的package包/类
/** Intersects p_room_shape with the half plane defined by the outside of the borderline
* with index p_obstacle_line_no of p_obstacle_shape.
*/
IntOctagon calc_outside_restrained_shape(IntOctagon p_obstacle_shape, int p_obstacle_line_no, IntOctagon p_room_shape)
{
int lx = p_room_shape.lx;
int ly = p_room_shape.ly;
int rx = p_room_shape.rx;
int uy = p_room_shape.uy;
int ulx = p_room_shape.ulx;
int lrx = p_room_shape.lrx;
int llx = p_room_shape.llx;
int urx = p_room_shape.urx;
if (p_obstacle_line_no == 0)
{
uy = p_obstacle_shape.ly;
}
else if (p_obstacle_line_no == 2)
{
lx = p_obstacle_shape.rx;
}
else if (p_obstacle_line_no == 4)
{
ly = p_obstacle_shape.uy;
}
else if (p_obstacle_line_no == 6)
{
rx = p_obstacle_shape.lx;
}
else if (p_obstacle_line_no == 1)
{
ulx = p_obstacle_shape.lrx;
}
else if (p_obstacle_line_no == 3)
{
llx = p_obstacle_shape.urx;
}
else if (p_obstacle_line_no == 5)
{
lrx = p_obstacle_shape.ulx;
}
else if (p_obstacle_line_no == 7)
{
urx = p_obstacle_shape.llx;
}
else
{
System.out.println("ShapeSearchTree45Degree.calc_outside_restrained_shape: p_obstacle_line_no out of range");
}
IntOctagon result = new IntOctagon(lx, ly, rx, uy, ulx, lrx, llx, urx);
return result.normalize();
}
示例3: calc_inside_restrained_shape
import geometry.planar.IntOctagon; //导入方法依赖的package包/类
/** Intersects p_room_shape with the half plane defined by the inside of the borderline
* with index p_obstacle_line_no of p_obstacle_shape.
*/
IntOctagon calc_inside_restrained_shape(IntOctagon p_obstacle_shape, int p_obstacle_line_no, IntOctagon p_room_shape)
{
int lx = p_room_shape.lx;
int ly = p_room_shape.ly;
int rx = p_room_shape.rx;
int uy = p_room_shape.uy;
int ulx = p_room_shape.ulx;
int lrx = p_room_shape.lrx;
int llx = p_room_shape.llx;
int urx = p_room_shape.urx;
if (p_obstacle_line_no == 0)
{
ly = p_obstacle_shape.ly;
}
else if (p_obstacle_line_no == 2)
{
rx = p_obstacle_shape.rx;
}
else if (p_obstacle_line_no == 4)
{
uy = p_obstacle_shape.uy;
}
else if (p_obstacle_line_no == 6)
{
lx = p_obstacle_shape.lx;
}
else if (p_obstacle_line_no == 1)
{
lrx = p_obstacle_shape.lrx;
}
else if (p_obstacle_line_no == 3)
{
urx = p_obstacle_shape.urx;
}
else if (p_obstacle_line_no == 5)
{
ulx = p_obstacle_shape.ulx;
}
else if (p_obstacle_line_no == 7)
{
llx = p_obstacle_shape.llx;
}
else
{
System.out.println("ShapeSearchTree45Degree.calc_inside_restrained_shape: p_obstacle_line_no out of range");
}
IntOctagon result = new IntOctagon(lx, ly, rx, uy, ulx, lrx, llx, urx);
return result.normalize();
}