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Java LineString.getCoordinateN方法代码示例

本文整理汇总了Java中com.vividsolutions.jts.geom.LineString.getCoordinateN方法的典型用法代码示例。如果您正苦于以下问题:Java LineString.getCoordinateN方法的具体用法?Java LineString.getCoordinateN怎么用?Java LineString.getCoordinateN使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在com.vividsolutions.jts.geom.LineString的用法示例。


在下文中一共展示了LineString.getCoordinateN方法的15个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Java代码示例。

示例1: getLength

import com.vividsolutions.jts.geom.LineString; //导入方法依赖的package包/类
public static double getLength(Geometry geom, Boolean inMeters) throws Exception
{
	if (!(geom instanceof LineString))
		throw new Exception("Specified geometry type is not supported.");

	LineString ls = (LineString)geom;
	if (ls.getNumPoints() == 0)
		return 0.0;

	if (inMeters)
	{
		double length = 0.0;
		DistanceCalc dc = new DistanceCalcEarth();

		Coordinate c0  = ls.getCoordinateN(0);
		for (int i = 1; i < ls.getNumPoints(); ++i)
		{
			Coordinate c1 = ls.getCoordinateN(i);
			length += dc.calcDist(c0.y, c0.x, c1.y, c1.x);
			c0 = c1;
		}

		return length;
	}
	else
		return ls.getLength();
}
 
开发者ID:GIScience,项目名称:openrouteservice,代码行数:28,代码来源:GeomUtility.java

示例2: getLength

import com.vividsolutions.jts.geom.LineString; //导入方法依赖的package包/类
public double getLength(DistanceCalc dc) {
	double res = 0;

	if (this.getGeometry() != null) {
		LineString ls = (LineString) this.getGeometry();
		int nPoints = ls.getNumPoints();

		if (nPoints > 1) {
			Coordinate c = ls.getCoordinateN(0);
			double x0 = c.x;
			double y0 = c.y;
			for (int i = 1; i < ls.getNumPoints(); i++) {
				c = ls.getCoordinateN(i);

				res += dc.calcDist(y0, x0, c.y, c.x);
				x0 = c.x;
				y0 = c.y;
			}
		}
	}

	return res;
}
 
开发者ID:GIScience,项目名称:openrouteservice,代码行数:24,代码来源:RouteSegmentInfo.java

示例3: indicesOf

import com.vividsolutions.jts.geom.LineString; //导入方法依赖的package包/类
public LinearLocation[] indicesOf(Geometry subLine) {
    Coordinate startPt = ((LineString) subLine.getGeometryN(0)).getCoordinateN(0);
    LineString lastLine = (LineString) subLine.getGeometryN(subLine.getNumGeometries() - 1);
    Coordinate endPt = lastLine.getCoordinateN(lastLine.getNumPoints() - 1);

    LocationIndexOfPoint locPt = new LocationIndexOfPoint(this.linearGeom);
    LinearLocation[] subLineLoc = new LinearLocation[2];
    subLineLoc[0] = locPt.indexOf(startPt);

    // check for case where subline is zero length
    if (subLine.getLength() == 0.0) {
        subLineLoc[1] = (LinearLocation) subLineLoc[0].clone();
    } else {
        subLineLoc[1] = locPt.indexOfAfter(endPt, subLineLoc[0]);
    }
    return subLineLoc;
}
 
开发者ID:gegy1000,项目名称:Earth,代码行数:18,代码来源:LocationIndexOfLine.java

示例4: isClosed

import com.vividsolutions.jts.geom.LineString; //导入方法依赖的package包/类
private boolean isClosed(LineString[] array, int dimension) throws InvalidGeometryException {
	int length = array.length;
	int ordinatesLength = 0;
	
	if (length != 0) {
		LineString first = array[0];
		LineString last = array[length - 1];
		Coordinate coordinate1 = first.getCoordinateN(0);
		Coordinate coordinate2 = last.getCoordinateN(last.getNumPoints() - 1);
		
		for(int i=0; i<length && ordinatesLength<NUMBER_OF_COORDINATES_NEEDED_FOR_RING;i++) {
			ordinatesLength += array[i].getNumPoints();
		}
		
		if (ordinatesLength < NUMBER_OF_COORDINATES_NEEDED_FOR_RING) {
			throw new InvalidGeometryException(GeometryValidationErrorType.TOO_FEW_POINTS, coordinate1);
		}
		
		return coordinate1.equals2D(coordinate2);
	}

	return false;
}
 
开发者ID:PDOK,项目名称:gml3-jts,代码行数:24,代码来源:GMLToLineConvertor.java

示例5: isClosed

import com.vividsolutions.jts.geom.LineString; //导入方法依赖的package包/类
private boolean isClosed(LineString[] array) throws InvalidGeometryException {
    int length = array.length;
    int ordinatesLength = 0;

    if (length != 0) {
        LineString first = array[0];
        LineString last = array[length - 1];
        Coordinate coordinate1 = first.getCoordinateN(0);
        Coordinate coordinate2 = last.getCoordinateN(last.getNumPoints() - 1);

        for (int i = 0; i < length && ordinatesLength < NUMBER_OF_COORDINATES_NEEDED_FOR_RING; i++) {
            ordinatesLength += array[i].getNumPoints();
        }

        if (ordinatesLength < NUMBER_OF_COORDINATES_NEEDED_FOR_RING) {
            throw new InvalidGeometryException(GeometryValidationErrorType.TOO_FEW_POINTS, coordinate1);
        }

        return coordinate1.equals2D(coordinate2);
    }

    return false;
}
 
开发者ID:PDOK,项目名称:gml3-jts,代码行数:24,代码来源:GML321ToLineConvertor.java

示例6: performMove

import com.vividsolutions.jts.geom.LineString; //导入方法依赖的package包/类
protected void performMove(Point imagePosition, OpenGLContext context) {
    if (selectedGeometry == null) {
        //super.mouseClicked(imagePosition, IClickable.BUTTON1, context);

        if (this.editedPoint == null && selectedGeometry != null) {
            if (type.equals(GeometryImage.POINT)) {
                this.editedPoint = selectedGeometry.getCoordinate();
            } else if (type.equals(GeometryImage.POLYGON)) {
                LineString ls = ((Polygon) selectedGeometry).getExteriorRing();
                for (int i = 0; i < ls.getNumPoints(); i++) {
                    Coordinate point = ls.getCoordinateN(i);
                    if (Math.abs(imagePosition.x - point.x) < 5 * context.getZoom() && Math.abs(imagePosition.y - point.y) < 5 * context.getZoom()) {
                        this.editedPoint = point;
                        break;
                    }
                }
            }
            if (this.editedPoint == null) {
                selectedGeometry.geometryChanged();
                selectedGeometry = null;
            }
        } else {
            if (selectedGeometry != null) {
                selectedGeometry.geometryChanged();
            }
            this.editedPoint = null;
        }
    } else {
        selectedGeometry.geometryChanged();
        editedPoint = null;
        selectedGeometry = null;
    }
}
 
开发者ID:ec-europa,项目名称:sumo,代码行数:34,代码来源:EditGeometryVectorLayer.java

示例7: canMergeGeometries

import com.vividsolutions.jts.geom.LineString; //导入方法依赖的package包/类
private static boolean canMergeGeometries(List<Geometry> geoms)
{
	int i = 0;
	Coordinate pLast = null;
	
	for(Geometry geom : geoms)
	{
		LineString ls = (LineString)geom;
		
		if (i > 0)
		{
			int nCoords = ls.getNumPoints();
			Coordinate pEnd = pLast;
			Coordinate p0 = ls.getCoordinateN(0);
			Coordinate pN = ls.getCoordinateN(nCoords - 1);
			double dist0 = distCalc.calcDist(pEnd.y,  pEnd.x, p0.y, p0.x);
			double distN = distCalc.calcDist(pEnd.y,  pEnd.x, pN.y, pN.x);
			if (dist0 > 15 && distN > 15)
				return false;
		}
		
		pLast = ls.getCoordinateN(ls.getNumPoints() - 1);
		
		i++;
	}
	
	return true;
}
 
开发者ID:GIScience,项目名称:openrouteservice,代码行数:29,代码来源:TrafficUtility.java

示例8: getArea

import com.vividsolutions.jts.geom.LineString; //导入方法依赖的package包/类
/**
 * Convert a linear ring to an area using the coordinate transformation.
 *
 * @param ring the ring to create an area from
 * @param ct the transformation to apply
 * @return the created area.
 */
public static Area getArea(LineString ring, CoordinateTransformer ct) {
    Path2D.Double path = new Path2D.Double();
    Coordinate coord = ring.getCoordinateN(0);
    path.moveTo(ct.getX(coord.x), ct.getY(coord.y));
    for (int i = 1; i < ring.getNumPoints(); i++) {
        coord = ring.getCoordinateN(i);
        path.lineTo(ct.getX(coord.x), ct.getY(coord.y));
    }
    path.closePath();
    return new Area(path);
}
 
开发者ID:gegy1000,项目名称:Earth,代码行数:19,代码来源:Jts2Awt.java

示例9: getPath

import com.vividsolutions.jts.geom.LineString; //导入方法依赖的package包/类
/**
 * Convert a linestring to a path using the coordinate transformation.
 *
 * @param string the string to create a path from.
 * @param ct the transformation to apply.
 * @return the path created.
 */
public static Path2D getPath(LineString string, CoordinateTransformer ct) {
    Path2D.Double path = new Path2D.Double();
    Coordinate coord = string.getCoordinateN(0);
    path.moveTo(ct.getX(coord.x), ct.getY(coord.y));
    for (int i = 1; i < string.getNumPoints(); i++) {
        coord = string.getCoordinateN(i);
        path.lineTo(ct.getX(coord.x), ct.getY(coord.y));
    }
    return path;
}
 
开发者ID:gegy1000,项目名称:Earth,代码行数:18,代码来源:Jts2Awt.java

示例10: isSequenced

import com.vividsolutions.jts.geom.LineString; //导入方法依赖的package包/类
/**
 * Tests whether a {@link Geometry} is sequenced correctly.
 * {@link LineString}s are trivially sequenced.
 * {@link MultiLineString}s are checked for correct sequencing.
 * Otherwise, <code>isSequenced</code> is defined
 * to be <code>true</code> for geometries that are not lineal.
 *
 * @param geom the geometry to test
 * @return <code>true</code> if the geometry is sequenced or is not lineal
 */
public static boolean isSequenced(Geometry geom) {
    if (!(geom instanceof MultiLineString)) {
        return true;
    }

    MultiLineString mls = (MultiLineString) geom;
    // the nodes in all subgraphs which have been completely scanned
    Set prevSubgraphNodes = new TreeSet();

    Coordinate lastNode = null;
    List currNodes = new ArrayList();
    for (int i = 0; i < mls.getNumGeometries(); i++) {
        LineString line = (LineString) mls.getGeometryN(i);
        Coordinate startNode = line.getCoordinateN(0);
        Coordinate endNode = line.getCoordinateN(line.getNumPoints() - 1);

        /**
         * If this linestring is connected to a previous subgraph, geom is not sequenced
         */
        if (prevSubgraphNodes.contains(startNode)) {
            return false;
        }
        if (prevSubgraphNodes.contains(endNode)) {
            return false;
        }

        if (lastNode != null) {
            if (!startNode.equals(lastNode)) {
                // start new connected sequence
                prevSubgraphNodes.addAll(currNodes);
                currNodes.clear();
            }
        }
        currNodes.add(startNode);
        currNodes.add(endNode);
        lastNode = endNode;
    }
    return true;
}
 
开发者ID:gegy1000,项目名称:Earth,代码行数:50,代码来源:LineSequencer.java

示例11: getSegmentLength

import com.vividsolutions.jts.geom.LineString; //导入方法依赖的package包/类
/**
 * Gets the length of the segment in the given
 * Geometry containing this location.
 *
 * @param linearGeom a linear geometry
 * @return the length of the segment
 */
public double getSegmentLength(Geometry linearGeom) {
    LineString lineComp = (LineString) linearGeom.getGeometryN(this.componentIndex);

    // ensure segment index is valid
    int segIndex = this.segmentIndex;
    if (this.segmentIndex >= lineComp.getNumPoints() - 1) {
        segIndex = lineComp.getNumPoints() - 2;
    }

    Coordinate p0 = lineComp.getCoordinateN(segIndex);
    Coordinate p1 = lineComp.getCoordinateN(segIndex + 1);
    return p0.distance(p1);
}
 
开发者ID:gegy1000,项目名称:Earth,代码行数:21,代码来源:LinearLocation.java

示例12: getCoordinate

import com.vividsolutions.jts.geom.LineString; //导入方法依赖的package包/类
/**
 * Gets the {@link Coordinate} along the
 * given linear {@link Geometry} which is
 * referenced by this location.
 *
 * @param linearGeom the linear geometry referenced by this location
 * @return the <tt>Coordinate</tt> at the location
 */
public Coordinate getCoordinate(Geometry linearGeom) {
    LineString lineComp = (LineString) linearGeom.getGeometryN(this.componentIndex);
    Coordinate p0 = lineComp.getCoordinateN(this.segmentIndex);
    if (this.segmentIndex >= lineComp.getNumPoints() - 1) {
        return p0;
    }
    Coordinate p1 = lineComp.getCoordinateN(this.segmentIndex + 1);
    return pointAlongSegmentByFraction(p0, p1, this.segmentFraction);
}
 
开发者ID:gegy1000,项目名称:Earth,代码行数:18,代码来源:LinearLocation.java

示例13: getSegment

import com.vividsolutions.jts.geom.LineString; //导入方法依赖的package包/类
/**
 * Gets a {@link LineSegment} representing the segment of the
 * given linear {@link Geometry} which contains this location.
 *
 * @param linearGeom a linear geometry
 * @return the <tt>LineSegment</tt> containing the location
 */
public LineSegment getSegment(Geometry linearGeom) {
    LineString lineComp = (LineString) linearGeom.getGeometryN(this.componentIndex);
    Coordinate p0 = lineComp.getCoordinateN(this.segmentIndex);
    // check for endpoint - return last segment of the line if so
    if (this.segmentIndex >= lineComp.getNumPoints() - 1) {
        Coordinate prev = lineComp.getCoordinateN(lineComp.getNumPoints() - 2);
        return new LineSegment(prev, p0);
    }
    Coordinate p1 = lineComp.getCoordinateN(this.segmentIndex + 1);
    return new LineSegment(p0, p1);
}
 
开发者ID:gegy1000,项目名称:Earth,代码行数:19,代码来源:LinearLocation.java

示例14: isOnRoundCap

import com.vividsolutions.jts.geom.LineString; //导入方法依赖的package包/类
/**
 * Determine if the {@link Coordinate} is on the round cap of the buffer
 * computed from the input {@link LineString} and the input distance. To
 * determine that, it has to be at the given distance to the first or last
 * point of the input {@link LineString} but closer to the first or last line
 * segments.
 * @param c a {@link Coordinate}
 * @param line the input {@link LineString}
 * @param distance distance used to compute the buffer
 * @param tolerance tolerance used to compare distances
 * @param startCoordinate if true, used the first point of the input
 *          {@link LineString}
 * @return true if the input {@link Coordinate} is on the round cap
 */
private static boolean isOnRoundCap(Coordinate c, LineString line,
    double distance, double tolerance, boolean startCoordinate) {
  Coordinate c1 = startCoordinate ? line.getCoordinateN(0) : line
      .getCoordinateN(line.getNumPoints() - 1);
  double d = c.distance(c1);
  if (d > distance - tolerance && d < distance + tolerance) {
    Coordinate c2 = startCoordinate ? line.getCoordinateN(1) : line
        .getCoordinateN(line.getNumPoints() - 2);
    LineSegment l = new LineSegment(c2, c1);
    d = l.distancePerpendicular(c);
    return (d < distance - tolerance);
  }
  return false;
}
 
开发者ID:IGNF,项目名称:geoxygene,代码行数:29,代码来源:JtsAlgorithms.java

示例15: removeCollinearVertices

import com.vividsolutions.jts.geom.LineString; //导入方法依赖的package包/类
/**
 * Removes collinear points from the provided linestring.
 * 
 * @param ls the {@link LineString} to be simplified.
 * @return a new version of the provided {@link LineString} with collinear points removed.
 */
static LineString removeCollinearVertices(final LineString ls) {
    if (ls == null) {
        throw new NullPointerException("The provided linestring is null");
    }

    final int N = ls.getNumPoints();
    final boolean isLinearRing = ls instanceof LinearRing;

    List<Coordinate> retain = new ArrayList<Coordinate>();
    retain.add(ls.getCoordinateN(0));

    int i0 = 0, i1 = 1, i2 = 2;
    Coordinate firstCoord = ls.getCoordinateN(i0);
    Coordinate midCoord;
    Coordinate lastCoord;
    while (i2 < N) {
        midCoord = ls.getCoordinateN(i1);
        lastCoord = ls.getCoordinateN(i2);

        final int orientation = CGAlgorithms
                .computeOrientation(firstCoord, midCoord, lastCoord);
        // Colllinearity test
        if (orientation != CGAlgorithms.COLLINEAR) {
            // add midcoord and change head
            retain.add(midCoord);
            i0 = i1;
            firstCoord = ls.getCoordinateN(i0);
        }
        i1++;
        i2++;
    }
    retain.add(ls.getCoordinateN(N - 1));

    //
    // Return value
    //
    final int size = retain.size();
    // nothing changed?
    if (size == N) {
        // free everything and return original
        retain.clear();

        return ls;
    }

    return isLinearRing ? ls.getFactory()
            .createLinearRing(retain.toArray(new Coordinate[size])) : ls.getFactory()
            .createLineString(retain.toArray(new Coordinate[size]));
}
 
开发者ID:GIScience,项目名称:openrouteservice,代码行数:56,代码来源:JTS.java


注:本文中的com.vividsolutions.jts.geom.LineString.getCoordinateN方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。