本文整理汇总了Java中com.google.appengine.labs.repackaged.org.json.JSONObject.getString方法的典型用法代码示例。如果您正苦于以下问题：Java JSONObject.getString方法的具体用法？Java JSONObject.getString怎么用？Java JSONObject.getString使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类com.google.appengine.labs.repackaged.org.json.JSONObject的用法示例。
在下文中一共展示了JSONObject.getString方法的3个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Java代码示例。
示例1: parsePnoSettings
import com.google.appengine.labs.repackaged.org.json.JSONObject; //导入方法依赖的package包/类
private static HashMap<String, String> parsePnoSettings(String settingsString) {
if (!RiseUtils.strIsNullOrEmpty(settingsString)) {
try {
JSONArray settingsArray = new JSONArray(settingsString);
HashMap<String, String> settings = new HashMap<String, String>();
for (int i = 0; i < settingsArray.length(); i++) {
JSONObject setting = settingsArray.getJSONObject(i);
String name = setting.getString("name");
String value = setting.optString("value", null);
settings.put(name, value);
}
return settings;
} catch (JSONException e) {
e.printStackTrace();
}
}
return null;
}
示例2: fromJSON
import com.google.appengine.labs.repackaged.org.json.JSONObject; //导入方法依赖的package包/类
/**
* Creates a new instance of {@link Application} based on the values derived from the specified {@code json}.
*
* @param json
* the {@code JSONObject} from which the details are to be derived
* @return The {@link Application} derived from {@code json}.
* @throws IllegalArgumentException
* If any of the required derived values are invalid.
* @throws JSONException
* If {@code json} is malformed.
* @throws NullPointerException
* If {@code json} is {@code null}.
*/
public static Application fromJSON(JSONObject json) throws JSONException {
return new Application(json.getString("apiKey"), json.getString("name"));
}
示例3: fromJSON
import com.google.appengine.labs.repackaged.org.json.JSONObject; //导入方法依赖的package包/类
/**
* Creates a new instance of {@link Contact} based on the values derived from the specified {@code json}.
*
* @param json
* the {@code JSONObject} from which the details are to be derived
* @return The {@link Contact} derived from {@code json}.
* @throws IllegalArgumentException
* If the derived email address is empty.
* @throws JSONException
* If {@code json} is malformed.
* @throws NullPointerException
* If {@code json} is {@code null}.
*/
public static Contact fromJSON(JSONObject json) throws JSONException {
return new Contact(json.getString("email"), json.optString("name", null));
}