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Java Point.setZ方法代码示例

本文整理汇总了Java中com.esri.core.geometry.Point.setZ方法的典型用法代码示例。如果您正苦于以下问题:Java Point.setZ方法的具体用法?Java Point.setZ怎么用?Java Point.setZ使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在com.esri.core.geometry.Point的用法示例。


在下文中一共展示了Point.setZ方法的4个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Java代码示例。

示例1: constructGeometryFromString

import com.esri.core.geometry.Point; //导入方法依赖的package包/类
private com.esri.ges.spatial.Geometry constructGeometryFromString(String geoString) throws GeometryException
{
	String[] pairs = geoString.split(" ");
	
	Polygon polygon = new Polygon();
	Boolean firstit = true;
	for(String coords: pairs)
	{
		
		String[] tuple = coords.split(",");
		Double x = Double.parseDouble(tuple[0]);
		Double y = Double.parseDouble(tuple[1]);
		Point p = new Point(x,y);
		Double z = Double.NaN;
		if (tuple.length>2)
		{
			z = Double.parseDouble(tuple[2]);
			p.setZ(z);
		}
		if(firstit)
		{
			polygon.startPath(p);
			firstit=false;
		}
		else
		{
			polygon.lineTo(p);
		}
	}
	polygon.closeAllPaths();
	String json = GeometryEngine.geometryToJson(srIn, polygon);
	return spatial.fromJson(json);
}
 
开发者ID:Esri,项目名称:defense-solutions-proofs-of-concept,代码行数:34,代码来源:QueryReportProcessor.java

示例2: constructCAPGeometry

import com.esri.core.geometry.Point; //导入方法依赖的package包/类
private com.esri.ges.spatial.Geometry constructCAPGeometry(String geoString)
		throws GeometryException {
	try {
		String[] pairs = geoString.split(" ");

		Polygon polygon = new Polygon();
		Boolean firstit = true;
		for (String coords : pairs) {

			String[] tuple = coords.split(",");
			Double x = Double.parseDouble(tuple[0]);
			Double y = Double.parseDouble(tuple[1]);
			Point p = new Point(x, y);
			Double z = Double.NaN;
			if (tuple.length > 2) {
				z = Double.parseDouble(tuple[2]);
				p.setZ(z);
			}
			if (firstit) {
				polygon.startPath(p);
				firstit = false;
			} else {
				polygon.lineTo(p);
			}
		}
		polygon.closeAllPaths();
		String json = GeometryEngine.geometryToJson(srIn, polygon);
		return spatial.fromJson(json);
	} catch (GeometryException ex) {
		LOG.error(ex.getMessage());
		LOG.error(ex.getStackTrace());
		return null;
	}
}
 
开发者ID:Esri,项目名称:defense-solutions-proofs-of-concept,代码行数:35,代码来源:PolygonProcessor.java

示例3: constructGeometryFromString

import com.esri.core.geometry.Point; //导入方法依赖的package包/类
private MapGeometry constructGeometryFromString(String geoString)
{
	String[] pairs = geoString.split(" ");
	
	Polygon polygon = new Polygon();
	Boolean firstit = true;
	for(String coords: pairs)
	{
		
		String[] tuple = coords.split(",");
		Double x = Double.parseDouble(tuple[0]);
		Double y = Double.parseDouble(tuple[1]);
		Point p = new Point(x,y);
		Double z = Double.NaN;
		if (tuple.length>2)
		{
			z = Double.parseDouble(tuple[2]);
			p.setZ(z);
		}
		if(firstit)
		{
			polygon.startPath(p);
			firstit=false;
		}
		else
		{
			polygon.lineTo(p);
		}
	}
	polygon.closeAllPaths();
	MapGeometry mapgeo = new MapGeometry(polygon, srOut);
	return mapgeo;
}
 
开发者ID:Esri,项目名称:defense-solutions-proofs-of-concept,代码行数:34,代码来源:QueryReportProcessor.java

示例4: constructGeometryFromString

import com.esri.core.geometry.Point; //导入方法依赖的package包/类
private MapGeometry constructGeometryFromString(String geoString) {
	String[] pairs = geoString.split(" ");

	Polygon polygon = new Polygon();
	Boolean firstit = true;
	for (String coords : pairs) {

		String[] tuple = coords.split(",");
		Double x = Double.parseDouble(tuple[0]);
		Double y = Double.parseDouble(tuple[1]);
		Point p = new Point(x, y);
		Double z = Double.NaN;
		if (tuple.length > 2) {
			z = Double.parseDouble(tuple[2]);
			p.setZ(z);
		}
		if (firstit) {
			polygon.startPath(p);
			firstit = false;
		} else {
			polygon.lineTo(p);
		}
	}
	polygon.closeAllPaths();
	MapGeometry mapgeo = new MapGeometry(polygon, srOut);
	return mapgeo;
}
 
开发者ID:Esri,项目名称:defense-solutions-proofs-of-concept,代码行数:28,代码来源:SpatialQProcessor.java


注:本文中的com.esri.core.geometry.Point.setZ方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。