本文整理汇总了Java中cern.colt.matrix.DoubleMatrix2D.viewColumn方法的典型用法代码示例。如果您正苦于以下问题：Java DoubleMatrix2D.viewColumn方法的具体用法？Java DoubleMatrix2D.viewColumn怎么用？Java DoubleMatrix2D.viewColumn使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类cern.colt.matrix.DoubleMatrix2D的用法示例。
在下文中一共展示了DoubleMatrix2D.viewColumn方法的3个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Java代码示例。
示例1: normalizePiz
import cern.colt.matrix.DoubleMatrix2D; //导入方法依赖的package包/类
/**
* Normalizes matrix of p(i|z) such that \forall_z: \sum_i p(i|z) = 1.
*
* @param piz normalized matrix of p(i|z)
*/
@Override
protected void normalizePiz(DoubleMatrix2D piz) {
for (int i = 0; i < piz.columns(); i++) {
DoubleMatrix1D tmp = piz.viewColumn(i);
double norm = tmp.aggregate(Functions.plus, Functions.identity);
if (norm != 0.0) {
tmp.assign(Functions.mult(1 / norm));
}
}
}
示例2: normalizePuz
import cern.colt.matrix.DoubleMatrix2D; //导入方法依赖的package包/类
/**
* Normalizes matrix of p(z|u) such that \forall_z: \sum_u p(z|u) = 1.
*
* @param pu_z normalized matrix of p(z|u)
*/
protected void normalizePuz(DoubleMatrix2D pu_z) {
for (int z = 0; z < pu_z.columns(); z++) {
final DoubleMatrix1D pu_Z = pu_z.viewColumn(z);
pu_Z.assign(mult(1 / pu_Z.aggregate(plus, identity)));
}
}
示例3: quickSort
import cern.colt.matrix.DoubleMatrix2D; //导入方法依赖的package包/类
/**
Sorts the matrix rows into ascending order, according to the <i>natural ordering</i> of the matrix values in the given column.
The returned view is backed by this matrix, so changes in the returned view are reflected in this matrix, and vice-versa.
To sort ranges use sub-ranging views. To sort columns by rows, use dice views. To sort descending, use flip views ...
<p>
<b>Example:</b>
<table border="1" cellspacing="0">
<tr nowrap>
<td valign="top"><tt>4 x 2 matrix: <br>
7, 6<br>
5, 4<br>
3, 2<br>
1, 0 <br>
</tt></td>
<td align="left" valign="top">
<p><tt>column = 0;<br>
view = quickSort(matrix,column);<br>
System.out.println(view); </tt><tt><br>
==> </tt></p>
</td>
<td valign="top">
<p><tt>4 x 2 matrix:<br>
1, 0<br>
3, 2<br>
5, 4<br>
7, 6</tt><br>
The matrix IS NOT SORTED.<br>
The new VIEW IS SORTED.</p>
</td>
</tr>
</table>
@param matrix the matrix to be sorted.
@param column the index of the column inducing the order.
@return a new matrix view having rows sorted by the given column.
<b>Note that the original matrix is left unaffected.</b>
@throws IndexOutOfBoundsException if <tt>column < 0 || column >= matrix.columns()</tt>.
*/
public DoubleMatrix2D sort(DoubleMatrix2D matrix, int column) {
if (column < 0 || column >= matrix.columns()) throw new IndexOutOfBoundsException("column="+column+", matrix="+Formatter.shape(matrix));
int[] rowIndexes = new int[matrix.rows()]; // row indexes to reorder instead of matrix itself
for (int i=rowIndexes.length; --i >= 0; ) rowIndexes[i] = i;
final DoubleMatrix1D col = matrix.viewColumn(column);
IntComparator comp = new IntComparator() {
public int compare(int a, int b) {
double av = col.getQuick(a);
double bv = col.getQuick(b);
if (av!=av || bv!=bv) return compareNaN(av,bv); // swap NaNs to the end
return av<bv ? -1 : (av==bv ? 0 : 1);
}
};
runSort(rowIndexes,0,rowIndexes.length,comp);
// view the matrix according to the reordered row indexes
// take all columns in the original order
return matrix.viewSelection(rowIndexes,null);
}