Java SpatialRelation类代码示例

import com.spatial4j.core.shape.SpatialRelation; //导入依赖的package包/类
public String getBoundingStateForCoordinate(Double lat, Double lng) {

		Point onePoint = ctx.makePoint(lat, lng);

		for (String oneShapeKey : geometries.keySet()) {

			Shape oneShape = geometries.get(oneShapeKey);

			SpatialRelation relation = oneShape.relate(onePoint);
			if (relation == SpatialRelation.CONTAINS || relation == SpatialRelation.INTERSECTS
					|| relation == SpatialRelation.WITHIN) {
				return oneShapeKey;
			} else {
				System.out.println("NOT IN:" + relation.toString());
			}
		}
		return null;
	}
 

import com.spatial4j.core.shape.SpatialRelation; //导入依赖的package包/类
public Boolean isPointInPolygon(Double lat, Double lng) {

		Point onePoint = ctx.makePoint(lat, lng);

		for (Shape oneShape : geometries.values()) {

			SpatialRelation relation = oneShape.relate(onePoint);
			if (relation == SpatialRelation.CONTAINS || relation == SpatialRelation.INTERSECTS
					|| relation == SpatialRelation.WITHIN) {
				return true;
			} else {
				System.out.println("NOT IN:" + relation.toString());
			}
		}
		return false;
	}
 

import com.spatial4j.core.shape.SpatialRelation; //导入依赖的package包/类
private SpatialRelation relateApprox(Shape other) {
  if (biasContainsThenWithin) {
    if (shape1.relate(other) == CONTAINS || shape1.equals(other)
        || shape2.relate(other) == CONTAINS || shape2.equals(other)) return CONTAINS;

    if (shape1.relate(other) == WITHIN && shape2.relate(other) == WITHIN) return WITHIN;

  } else {
    if ((shape1.relate(other) == WITHIN || shape1.equals(other))
        && (shape2.relate(other) == WITHIN || shape2.equals(other))) return WITHIN;

    if (shape1.relate(other) == CONTAINS || shape2.relate(other) == CONTAINS) return CONTAINS;
  }

  if (shape1.relate(other).intersects() || shape2.relate(other).intersects())
    return INTERSECTS;//might actually be 'CONTAINS' if the pair are adjacent but we handle that later
  return DISJOINT;
}
 

import com.spatial4j.core.shape.SpatialRelation; //导入依赖的package包/类
@Override
public SpatialRelation relate(Shape other) {
  SpatialRelation r = relateApprox(other);
  if (r != INTERSECTS && !(r == WITHIN && biasContainsThenWithin))
    return r;
  //See if the correct answer is actually Contains, when the indexed shapes are adjacent,
  // creating a larger shape that contains the input shape.
  Rectangle oRect = (Rectangle)other;
  boolean pairTouches = shape1.relate(shape2).intersects();
  if (!pairTouches)
    return r;
  //test all 4 corners
  if (relate(ctx.makePoint(oRect.getMinX(), oRect.getMinY())) == CONTAINS
      && relate(ctx.makePoint(oRect.getMinX(), oRect.getMaxY())) == CONTAINS
      && relate(ctx.makePoint(oRect.getMaxX(), oRect.getMinY())) == CONTAINS
      && relate(ctx.makePoint(oRect.getMaxX(), oRect.getMaxY())) == CONTAINS)
    return CONTAINS;
  return r;
}
 

import com.spatial4j.core.shape.SpatialRelation; //导入依赖的package包/类
private SpatialRelation relateApprox(Shape other) {
  if (biasContainsThenWithin) {
    if (shape1.relate(other) == CONTAINS || shape1.equals(other)
        || shape2.relate(other) == CONTAINS || shape2.equals(other)) return CONTAINS;

    if (shape1.relate(other) == WITHIN && shape2.relate(other) == WITHIN) return WITHIN;

  } else {
    if ((shape1.relate(other) == WITHIN || shape1.equals(other))
        && (shape2.relate(other) == WITHIN || shape2.equals(other))) return WITHIN;

    if (shape1.relate(other) == CONTAINS || shape2.relate(other) == CONTAINS) return CONTAINS;
  }

  if (shape1.relate(other).intersects() || shape2.relate(other).intersects())
    return INTERSECTS;//might actually be 'CONTAINS' if these 2 are adjacent
  return DISJOINT;
}
 

import com.spatial4j.core.shape.SpatialRelation; //导入依赖的package包/类
@Override
public Object evaluateRecord(OIdentifiable iRecord, ODocument iCurrentResult, OSQLFilterCondition iCondition, Object iLeft,
    Object iRight, OCommandContext iContext) {

  List<Number> left = (List<Number>) iLeft;

  double lat = left.get(0).doubleValue();
  double lon = left.get(1).doubleValue();

  Shape shape = factory.context().makePoint(lon, lat);
  List<Number> right = (List<Number>) iRight;

  double lat1 = right.get(0).doubleValue();
  double lon1 = right.get(1).doubleValue();
  Shape shape1 = factory.context().makePoint(lon1, lat1);

  Map map = (Map) right.get(2);
  double distance = 0;

  Number n = (Number) map.get("maxDistance");
  if (n != null) {
    distance = n.doubleValue();
  }
  Point p = (Point) shape1;
  Circle circle = factory.context().makeCircle(p.getX(), p.getY(),
      DistanceUtils.dist2Degrees(distance, DistanceUtils.EARTH_MEAN_RADIUS_KM));
  double docDistDEG = factory.context().getDistCalc().distance((Point) shape, p);
  final double docDistInKM = DistanceUtils.degrees2Dist(docDistDEG, DistanceUtils.EARTH_EQUATORIAL_RADIUS_KM);
  iContext.setVariable("distance", docDistInKM);
  return shape.relate(circle) == SpatialRelation.WITHIN;
}
 

import com.spatial4j.core.shape.SpatialRelation; //导入依赖的package包/类
@Override
public Object evaluateRecord(OIdentifiable iRecord, ODocument iCurrentResult, OSQLFilterCondition iCondition, Object iLeft,
    Object iRight, OCommandContext iContext) {
  List<Number> left = (List<Number>) iLeft;

  double lat = left.get(0).doubleValue();
  double lon = left.get(1).doubleValue();

  Shape shape = SpatialContext.GEO.makePoint(lon, lat);

  Shape shape1 = shapeFactory.makeShape(new OSpatialCompositeKey((List<?>) iRight), SpatialContext.GEO);

  return shape.relate(shape1) == SpatialRelation.WITHIN;
}
 

import com.spatial4j.core.shape.SpatialRelation; //导入依赖的package包/类
@Override
public Object execute(Object iThis, OIdentifiable iCurrentRecord, Object iCurrentResult, Object[] iParams,
    OCommandContext iContext) {
  Shape shape = factory.fromObject(iParams[0]);

  Shape shape1 = factory.fromObject(iParams[1]);

  return shape.relate(shape1) == SpatialRelation.CONTAINS && shape1.relate(shape) == SpatialRelation.CONTAINS;
}
 

import com.spatial4j.core.shape.SpatialRelation; //导入依赖的package包/类
@Override
public Object execute(Object iThis, OIdentifiable iCurrentRecord, Object iCurrentResult, Object[] iParams,
    OCommandContext iContext) {
  Shape shape = factory.fromObject(iParams[0]);

  Shape shape1 = factory.fromObject(iParams[1]);

  return shape.relate(shape1) == SpatialRelation.DISJOINT;
}
 

import com.spatial4j.core.shape.SpatialRelation; //导入依赖的package包/类
/**
 * Like {@link #getSubCells()} but with the results filtered by a shape. If
 * that shape is a {@link com.spatial4j.core.shape.Point} then it must call
 * {@link #getSubCell(com.spatial4j.core.shape.Point)}. The returned cells
 * should have {@link Cell#getShapeRel()} set to their relation with {@code
 * shapeFilter}. In addition, {@link Cell#isLeaf()}
 * must be true when that relation is WITHIN.
 * <p/>
 * Precondition: Never called when getLevel() == maxLevel.
 *
 * @param shapeFilter an optional filter for the returned cells.
 * @return A set of cells (no dups), sorted. Not Modifiable.
 */
public Collection<Cell> getSubCells(Shape shapeFilter) {
  //Note: Higher-performing subclasses might override to consider the shape filter to generate fewer cells.
  if (shapeFilter instanceof Point) {
    Cell subCell = getSubCell((Point) shapeFilter);
    subCell.shapeRel = SpatialRelation.CONTAINS;
    return Collections.singletonList(subCell);
  }
  Collection<Cell> cells = getSubCells();

  if (shapeFilter == null) {
    return cells;
  }

  //TODO change API to return a filtering iterator
  List<Cell> copy = new ArrayList<>(cells.size());
  for (Cell cell : cells) {
    SpatialRelation rel = cell.getShape().relate(shapeFilter);
    if (rel == SpatialRelation.DISJOINT)
      continue;
    cell.shapeRel = rel;
    if (rel == SpatialRelation.WITHIN)
      cell.setLeaf();
    copy.add(cell);
  }
  return copy;
}
 

import com.spatial4j.core.shape.SpatialRelation; //导入依赖的package包/类
@Test
public void testShapePair() {
  ctx = SpatialContext.GEO;
  setupCtx2D(ctx);

  Shape leftShape = new ShapePair(ctx.makeRectangle(-74, -56, -8, 1), ctx.makeRectangle(-180, 134, -90, 90), true);
  Shape queryShape = ctx.makeRectangle(-180, 180, -90, 90);
  assertEquals(SpatialRelation.WITHIN, leftShape.relate(queryShape));
}
 

import com.spatial4j.core.shape.SpatialRelation; //导入依赖的package包/类
@Override
public SpatialRelation relate(Shape other) {
  SpatialRelation r = relateApprox(other);
  if (r == DISJOINT)
    return r;
  if (r == CONTAINS)
    return r;
  if (r == WITHIN && !biasContainsThenWithin)
    return r;

  //See if the correct answer is actually Contains, when the indexed shapes are adjacent,
  // creating a larger shape that contains the input shape.
  boolean pairTouches = shape1.relate(shape2).intersects();
  if (!pairTouches)
    return r;
  //test all 4 corners
  // Note: awkwardly, we use a non-geo context for this because in geo, -180 & +180 are the same place, which means
  //  that "other" might wrap the world horizontally and yet all it's corners could be in shape1 (or shape2) even
  //  though shape1 is only adjacent to the dateline. I couldn't think of a better way to handle this.
  Rectangle oRect = (Rectangle)other;
  if (cornerContainsNonGeo(oRect.getMinX(), oRect.getMinY())
      && cornerContainsNonGeo(oRect.getMinX(), oRect.getMaxY())
      && cornerContainsNonGeo(oRect.getMaxX(), oRect.getMinY())
      && cornerContainsNonGeo(oRect.getMaxX(), oRect.getMaxY()) )
    return CONTAINS;
  return r;
}
 

import com.spatial4j.core.shape.SpatialRelation; //导入依赖的package包/类
@Override
public Object evaluateRecord(OIdentifiable iRecord, ODocument iCurrentResult, OSQLFilterCondition iCondition, Object iLeft,
    Object iRight, OCommandContext iContext) {

  List<Number> left = (List<Number>) iLeft;

  double lat = left.get(0).doubleValue();
  double lon = left.get(1).doubleValue();

  Shape shape = SpatialContext.GEO.makePoint(lon, lat);
  List<Number> right = (List<Number>) iRight;

  double lat1 =  right.get(0).doubleValue();
  double lon1 =  right.get(1).doubleValue();
  Shape shape1 = SpatialContext.GEO.makePoint(lon1, lat1);

  Map map = (Map) right.get(2);
  double distance = 0;

  Number n = (Number) map.get("maxDistance");
  if (n != null) {
    distance = n.doubleValue();
  }
  Point p = (Point) shape1;
  Circle circle = SpatialContext.GEO.makeCircle(p.getX(), p.getY(),
      DistanceUtils.dist2Degrees(distance, DistanceUtils.EARTH_MEAN_RADIUS_KM));
  double docDistDEG = SpatialContext.GEO.getDistCalc().distance((Point) shape, p);
  final double docDistInKM = DistanceUtils.degrees2Dist(docDistDEG, DistanceUtils.EARTH_EQUATORIAL_RADIUS_KM);
  iContext.setVariable("distance", docDistInKM);
  return shape.relate(circle) == SpatialRelation.WITHIN;
}
 

import com.spatial4j.core.shape.SpatialRelation; //导入依赖的package包/类
/**
 * Like {@link #getSubCells()} but with the results filtered by a shape. If
 * that shape is a {@link com.spatial4j.core.shape.Point} then it must call
 * {@link #getSubCell(com.spatial4j.core.shape.Point)}. The returned cells
 * should have {@link Node#getShapeRel()} set to their relation with {@code
 * shapeFilter}. In addition, {@link org.apache.lucene.spatial.prefix.tree.Node#isLeaf()}
 * must be true when that relation is WITHIN.
 * <p/>
 * Precondition: Never called when getLevel() == maxLevel.
 *
 * @param shapeFilter an optional filter for the returned cells.
 * @return A set of cells (no dups), sorted. Not Modifiable.
 */
public Collection<Node> getSubCells(Shape shapeFilter) {
  //Note: Higher-performing subclasses might override to consider the shape filter to generate fewer cells.
  if (shapeFilter instanceof Point) {
    Node subCell = getSubCell((Point) shapeFilter);
    subCell.shapeRel = SpatialRelation.CONTAINS;
    return Collections.singletonList(subCell);
  }
  Collection<Node> cells = getSubCells();

  if (shapeFilter == null) {
    return cells;
  }

  //TODO change API to return a filtering iterator
  List<Node> copy = new ArrayList<Node>(cells.size());
  for (Node cell : cells) {
    SpatialRelation rel = cell.getShape().relate(shapeFilter);
    if (rel == SpatialRelation.DISJOINT)
      continue;
    cell.shapeRel = rel;
    if (rel == SpatialRelation.WITHIN)
      cell.setLeaf();
    copy.add(cell);
  }
  return copy;
}
 

import com.spatial4j.core.shape.SpatialRelation; //导入依赖的package包/类
/**
 * Like {@link #getSubCells()} but with the results filtered by a shape. If
 * that shape is a {@link com.spatial4j.core.shape.Point} then it must call
 * {@link #getSubCell(com.spatial4j.core.shape.Point)}. The returned cells
 * should have {@link Cell#getShapeRel()} set to their relation with {@code
 * shapeFilter}. In addition, {@link Cell#isLeaf()}
 * must be true when that relation is WITHIN.
 * <p/>
 * Precondition: Never called when getLevel() == maxLevel.
 *
 * @param shapeFilter an optional filter for the returned cells.
 * @return A set of cells (no dups), sorted. Not Modifiable.
 */
public Collection<Cell> getSubCells(Shape shapeFilter) {
  //Note: Higher-performing subclasses might override to consider the shape filter to generate fewer cells.
  if (shapeFilter instanceof Point) {
    Cell subCell = getSubCell((Point) shapeFilter);
    subCell.shapeRel = SpatialRelation.CONTAINS;
    return Collections.singletonList(subCell);
  }
  Collection<Cell> cells = getSubCells();

  if (shapeFilter == null) {
    return cells;
  }

  //TODO change API to return a filtering iterator
  List<Cell> copy = new ArrayList<Cell>(cells.size());
  for (Cell cell : cells) {
    SpatialRelation rel = cell.getShape().relate(shapeFilter);
    if (rel == SpatialRelation.DISJOINT)
      continue;
    cell.shapeRel = rel;
    if (rel == SpatialRelation.WITHIN)
      cell.setLeaf();
    copy.add(cell);
  }
  return copy;
}