本文整理汇总了Java中com.intellij.usages.rules.UsageInModule类的典型用法代码示例。如果您正苦于以下问题：Java UsageInModule类的具体用法？Java UsageInModule怎么用？Java UsageInModule使用的例子？那么, 这里精选的类代码示例或许可以为您提供帮助。
UsageInModule类属于com.intellij.usages.rules包，在下文中一共展示了UsageInModule类的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Java代码示例。
示例1: groupUsage
import com.intellij.usages.rules.UsageInModule; //导入依赖的package包/类
@Override
public UsageGroup groupUsage(@NotNull Usage usage) {
if (usage instanceof UsageInModule) {
UsageInModule usageInModule = (UsageInModule)usage;
Module module = usageInModule.getModule();
if (module != null) return new ModuleUsageGroup(module);
}
if (usage instanceof UsageInLibrary) {
UsageInLibrary usageInLibrary = (UsageInLibrary)usage;
OrderEntry entry = usageInLibrary.getLibraryEntry();
if (entry != null) return new LibraryUsageGroup(entry);
}
return null;
}
示例2: groupUsage
import com.intellij.usages.rules.UsageInModule; //导入依赖的package包/类
@Override
public UsageGroup groupUsage(@Nonnull Usage usage) {
if (usage instanceof UsageInModule) {
UsageInModule usageInModule = (UsageInModule)usage;
Module module = usageInModule.getModule();
if (module != null) return new ModuleUsageGroup(module);
}
if (usage instanceof UsageInLibrary) {
UsageInLibrary usageInLibrary = (UsageInLibrary)usage;
OrderEntry entry = usageInLibrary.getLibraryEntry();
if (entry != null) return new LibraryUsageGroup(entry);
}
return null;
}