本文整理汇总了Java中com.google.javascript.jscomp.CodingConvention.SubclassType类的典型用法代码示例。如果您正苦于以下问题：Java SubclassType类的具体用法？Java SubclassType怎么用？Java SubclassType使用的例子？那么恭喜您, 这里精选的类代码示例或许可以为您提供帮助。
SubclassType类属于com.google.javascript.jscomp.CodingConvention包，在下文中一共展示了SubclassType类的4个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Java代码示例。
示例1: testApplySubclassRelationship
import com.google.javascript.jscomp.CodingConvention.SubclassType; //导入依赖的package包/类
public void testApplySubclassRelationship() {
JSTypeRegistry registry = new JSTypeRegistry(null);
Node nodeA = new Node(Token.FUNCTION);
FunctionType ctorA = registry.createConstructorType("A", nodeA,
new Node(Token.PARAM_LIST), null, null);
Node nodeB = new Node(Token.FUNCTION);
FunctionType ctorB = registry.createConstructorType("B", nodeB,
new Node(Token.PARAM_LIST), null, null);
conv.applySubclassRelationship(ctorA, ctorB, SubclassType.INHERITS);
assertTrue(ctorB.getPrototype().hasOwnProperty("constructor"));
assertEquals(nodeB, ctorB.getPrototype().getPropertyNode("constructor"));
assertTrue(ctorB.hasOwnProperty("superClass_"));
assertEquals(nodeB, ctorB.getPropertyNode("superClass_"));
}
示例2: checkCallConventions
import com.google.javascript.jscomp.CodingConvention.SubclassType; //导入依赖的package包/类
/**
* Validate class-defining calls.
* Because JS has no 'native' syntax for defining classes, we need
* to do this manually.
*/
private void checkCallConventions(NodeTraversal t, Node n) {
SubclassRelationship relationship =
compiler.getCodingConvention().getClassesDefinedByCall(n);
TypedScope scope = t.getTypedScope();
if (relationship != null) {
ObjectType superClass = TypeValidator.getInstanceOfCtor(
scope.getVar(relationship.superclassName));
ObjectType subClass = TypeValidator.getInstanceOfCtor(
scope.getVar(relationship.subclassName));
if (relationship.type == SubclassType.INHERITS &&
superClass != null && !superClass.isEmptyType() &&
subClass != null && !subClass.isEmptyType()) {
validator.expectSuperType(t, n, superClass, subClass);
}
}
}
示例3: testApplySubclassRelationship
import com.google.javascript.jscomp.CodingConvention.SubclassType; //导入依赖的package包/类
public void testApplySubclassRelationship() {
JSTypeRegistry registry = new JSTypeRegistry(null);
Node nodeA = new Node(Token.FUNCTION);
FunctionType ctorA =
registry.createConstructorType("A", nodeA, new Node(Token.PARAM_LIST), null, null, false);
Node nodeB = new Node(Token.FUNCTION);
FunctionType ctorB =
registry.createConstructorType("B", nodeB, new Node(Token.PARAM_LIST), null, null, false);
conv.applySubclassRelationship(
new NominalTypeBuilderOti(ctorA, ctorA.getInstanceType()),
new NominalTypeBuilderOti(ctorB, ctorB.getInstanceType()),
SubclassType.INHERITS);
assertTrue(ctorB.getPrototype().hasOwnProperty("constructor"));
assertEquals(nodeB, ctorB.getPrototype().getPropertyNode("constructor"));
assertTrue(ctorB.hasOwnProperty("superClass_"));
assertEquals(nodeB, ctorB.getPropertyNode("superClass_"));
}
示例4: checkCallConventions
import com.google.javascript.jscomp.CodingConvention.SubclassType; //导入依赖的package包/类
/**
* Validate class-defining calls.
* Because JS has no 'native' syntax for defining classes, we need
* to do this manually.
*/
private void checkCallConventions(NodeTraversal t, Node n) {
SubclassRelationship relationship =
compiler.getCodingConvention().getClassesDefinedByCall(n);
Scope scope = t.getScope();
if (relationship != null) {
ObjectType superClass = TypeValidator.getInstanceOfCtor(
scope.getVar(relationship.superclassName));
ObjectType subClass = TypeValidator.getInstanceOfCtor(
scope.getVar(relationship.subclassName));
if (relationship.type == SubclassType.INHERITS &&
superClass != null && !superClass.isEmptyType() &&
subClass != null && !subClass.isEmptyType()) {
validator.expectSuperType(t, n, superClass, subClass);
}
}
}