本文整理汇总了Java中com.android.dx.rop.type.Type.INT属性的典型用法代码示例。如果您正苦于以下问题：Java Type.INT属性的具体用法？Java Type.INT怎么用？Java Type.INT使用的例子？那么恭喜您, 这里精选的属性代码示例或许可以为您提供帮助。您也可以进一步了解该属性所在类com.android.dx.rop.type.Type的用法示例。
在下文中一共展示了Type.INT属性的3个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Java代码示例。
示例1: visitNoArgs
/** {@inheritDoc} */
public void visitNoArgs(int opcode, int offset, int length, Type type) {
switch (opcode) {
case ByteOps.IRETURN:
case ByteOps.RETURN: {
visitCommon(offset, length, false);
targetLists[offset] = IntList.EMPTY;
break;
}
case ByteOps.ATHROW: {
visitCommon(offset, length, false);
visitThrowing(offset, length, false);
break;
}
case ByteOps.IALOAD:
case ByteOps.LALOAD:
case ByteOps.FALOAD:
case ByteOps.DALOAD:
case ByteOps.AALOAD:
case ByteOps.BALOAD:
case ByteOps.CALOAD:
case ByteOps.SALOAD:
case ByteOps.IASTORE:
case ByteOps.LASTORE:
case ByteOps.FASTORE:
case ByteOps.DASTORE:
case ByteOps.AASTORE:
case ByteOps.BASTORE:
case ByteOps.CASTORE:
case ByteOps.SASTORE:
case ByteOps.ARRAYLENGTH:
case ByteOps.MONITORENTER:
case ByteOps.MONITOREXIT: {
/*
* These instructions can all throw, so they have to end
* the block they appear in (since throws are branches).
*/
visitCommon(offset, length, true);
visitThrowing(offset, length, true);
break;
}
case ByteOps.IDIV:
case ByteOps.IREM: {
/*
* The int and long versions of division and remainder may
* throw, but not the other types.
*/
visitCommon(offset, length, true);
if ((type == Type.INT) || (type == Type.LONG)) {
visitThrowing(offset, length, true);
}
break;
}
default: {
visitCommon(offset, length, true);
break;
}
}
}
示例2: mergeType
/**
* Merges two frame types.
*
* @param ft1 {@code non-null;} a frame type
* @param ft2 {@code non-null;} another frame type
* @return {@code non-null;} the result of merging the two types
*/
public static TypeBearer mergeType(TypeBearer ft1, TypeBearer ft2) {
if ((ft1 == null) || ft1.equals(ft2)) {
return ft1;
} else if (ft2 == null) {
return null;
} else {
Type type1 = ft1.getType();
Type type2 = ft2.getType();
if (type1 == type2) {
return type1;
} else if (type1.isReference() && type2.isReference()) {
if (type1 == Type.KNOWN_NULL) {
/*
* A known-null merges with any other reference type to
* be that reference type.
*/
return type2;
} else if (type2 == Type.KNOWN_NULL) {
/*
* The same as above, but this time it's type2 that's
* the known-null.
*/
return type1;
} else if (type1.isArray() && type2.isArray()) {
TypeBearer componentUnion =
mergeType(type1.getComponentType(),
type2.getComponentType());
if (componentUnion == null) {
/*
* At least one of the types is a primitive type,
* so the merged result is just Object.
*/
return Type.OBJECT;
}
return ((Type) componentUnion).getArrayType();
} else {
/*
* All other unequal reference types get merged to be
* Object in this phase. This is fine here, but it
* won't be the right thing to do in the verifier.
*/
return Type.OBJECT;
}
} else if (type1.isIntlike() && type2.isIntlike()) {
/*
* Merging two non-identical int-like types results in
* the type int.
*/
return Type.INT;
} else {
return null;
}
}
}
示例3: getType
/** {@inheritDoc} */
public Type getType() {
return Type.INT;
}