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Golang GroupVersion.WithResource方法代码示例

本文整理汇总了Golang中k8s/io/client-go/1/5/pkg/api/unversioned.GroupVersion.WithResource方法的典型用法代码示例。如果您正苦于以下问题:Golang GroupVersion.WithResource方法的具体用法?Golang GroupVersion.WithResource怎么用?Golang GroupVersion.WithResource使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在k8s/io/client-go/1/5/pkg/api/unversioned.GroupVersion的用法示例。


在下文中一共展示了GroupVersion.WithResource方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Golang代码示例。

示例1: serverPreferredResources

// serverPreferredResources returns the supported resources with the version preferred by the
// server. If namespaced is true, only namespaced resources will be returned.
func (d *DiscoveryClient) serverPreferredResources(namespaced bool) ([]unversioned.GroupVersionResource, error) {
	results := []unversioned.GroupVersionResource{}
	serverGroupList, err := d.ServerGroups()
	if err != nil {
		return results, err
	}

	var failedGroups map[unversioned.GroupVersion]error
	for _, apiGroup := range serverGroupList.Groups {
		preferredVersion := apiGroup.PreferredVersion
		groupVersion := unversioned.GroupVersion{Group: apiGroup.Name, Version: preferredVersion.Version}
		apiResourceList, err := d.ServerResourcesForGroupVersion(preferredVersion.GroupVersion)
		if err != nil {
			if failedGroups == nil {
				failedGroups = make(map[unversioned.GroupVersion]error)
			}
			failedGroups[groupVersion] = err
			continue
		}
		for _, apiResource := range apiResourceList.APIResources {
			// ignore the root scoped resources if "namespaced" is true.
			if namespaced && !apiResource.Namespaced {
				continue
			}
			if strings.Contains(apiResource.Name, "/") {
				continue
			}
			results = append(results, groupVersion.WithResource(apiResource.Name))
		}
	}
	if len(failedGroups) > 0 {
		return results, &ErrGroupDiscoveryFailed{Groups: failedGroups}
	}
	return results, nil
}
开发者ID:ncdc,项目名称:kubernetes,代码行数:37,代码来源:discovery_client.go


注:本文中的k8s/io/client-go/1/5/pkg/api/unversioned.GroupVersion.WithResource方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。