本文整理汇总了Golang中github.com/google/cayley/graph.NextLogOut函数的典型用法代码示例。如果您正苦于以下问题:Golang NextLogOut函数的具体用法?Golang NextLogOut怎么用?Golang NextLogOut使用的例子?那么恭喜您, 这里精选的函数代码示例或许可以为您提供帮助。
在下文中一共展示了NextLogOut函数的15个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Golang代码示例。
示例1: Next
// Next advances the Or graph.iterator. Because the Or is the union of its
// subiterators, it must produce from all subiterators -- unless it it
// shortcircuiting, in which case, it is the first one that returns anything.
func (it *Or) Next() bool {
graph.NextLogIn(it)
var first bool
for {
if it.currentIterator == -1 {
it.currentIterator = 0
first = true
}
curIt := it.internalIterators[it.currentIterator]
if graph.Next(curIt) {
it.result = curIt.Result()
return graph.NextLogOut(it, it.result, true)
}
if it.isShortCircuiting && !first {
break
}
it.currentIterator++
if it.currentIterator == it.itCount {
break
}
}
return graph.NextLogOut(it, nil, false)
}
示例2: Next
// Returns the Next value from the Or graph.iterator. Because the Or is the
// union of its subiterators, it must produce from all subiterators -- unless
// it's shortcircuiting, in which case, it's the first one that returns anything.
func (it *Or) Next() (graph.Value, bool) {
graph.NextLogIn(it)
var curr graph.Value
var exists bool
firstTime := false
for {
if it.currentIterator == -1 {
it.currentIterator = 0
firstTime = true
}
curIt := it.internalIterators[it.currentIterator]
curr, exists = graph.Next(curIt)
if !exists {
if it.isShortCircuiting && !firstTime {
return graph.NextLogOut(it, nil, false)
}
it.currentIterator++
if it.currentIterator == it.itCount {
return graph.NextLogOut(it, nil, false)
}
} else {
it.result = curr
return graph.NextLogOut(it, curr, true)
}
}
panic("unreachable")
}
示例3: Next
// Returns the Next value from the Or graph.iterator. Because the Or is the
// union of its subiterators, it must produce from all subiterators -- unless
// it's shortcircuiting, in which case, it's the first one that returns anything.
func (it *Or) Next() (graph.TSVal, bool) {
graph.NextLogIn(it)
var curr graph.TSVal
var exists bool
firstTime := false
for {
if it.currentIterator == -1 {
it.currentIterator = 0
firstTime = true
}
curIt := it.internalIterators[it.currentIterator]
curr, exists = curIt.Next()
if !exists {
if it.isShortCircuiting && !firstTime {
return graph.NextLogOut(it, nil, false)
}
it.currentIterator++
if it.currentIterator == it.itCount {
return graph.NextLogOut(it, nil, false)
}
} else {
it.Last = curr
return graph.NextLogOut(it, curr, true)
}
}
panic("Somehow broke out of Next() loop in Or")
}
示例4: Next
// Next()ing a LinksTo operates as described above.
func (it *LinksTo) Next() bool {
graph.NextLogIn(it)
it.runstats.Next += 1
if graph.Next(it.nextIt) {
it.runstats.ContainsNext += 1
it.result = it.nextIt.Result()
return graph.NextLogOut(it, it.result, true)
}
// If there's an error in the 'next' iterator, we save it and we're done.
it.err = it.nextIt.Err()
if it.err != nil {
return false
}
// Subiterator is empty, get another one
if !graph.Next(it.primaryIt) {
// Possibly save error
it.err = it.primaryIt.Err()
// We're out of nodes in our subiterator, so we're done as well.
return graph.NextLogOut(it, nil, false)
}
it.nextIt.Close()
it.nextIt = it.qs.QuadIterator(it.dir, it.primaryIt.Result())
// Recurse -- return the first in the next set.
return it.Next()
}
示例5: Next
func (it *Iterator) Next() (graph.TSVal, bool) {
graph.NextLogIn(it)
if it.tree.Max() == nil || it.Last == int64(it.tree.Max().(Int64)) {
return graph.NextLogOut(it, nil, false)
}
it.iterLast = IterateOne(it.tree, it.iterLast)
it.Last = int64(it.iterLast)
return graph.NextLogOut(it, it.Last, true)
}
示例6: Next
// Next advances the iterator.
func (it *Fixed) Next() bool {
graph.NextLogIn(it)
if it.lastIndex == len(it.values) {
return graph.NextLogOut(it, nil, false)
}
out := it.values[it.lastIndex]
it.result = out
it.lastIndex++
return graph.NextLogOut(it, out, true)
}
示例7: Next
// Returns advances the And iterator. Because the And is the intersection of its
// subiterators, it must choose one subiterator to produce a candidate, and check
// this value against the subiterators. A productive choice of primary iterator
// is therefore very important.
func (it *And) Next() bool {
graph.NextLogIn(it)
it.runstats.Next += 1
for graph.Next(it.primaryIt) {
curr := it.primaryIt.Result()
if it.subItsContain(curr, nil) {
it.result = curr
return graph.NextLogOut(it, curr, true)
}
}
return graph.NextLogOut(it, nil, false)
}
示例8: Next
// Next() on an Int64 all iterator is a simple incrementing counter.
// Return the next integer, and mark it as the result.
func (it *Int64) Next() bool {
graph.NextLogIn(it)
if it.at == -1 {
return graph.NextLogOut(it, nil, false)
}
val := it.at
it.at = it.at + 1
if it.at > it.max {
it.at = -1
}
it.result = val
return graph.NextLogOut(it, val, true)
}
示例9: Next
// Next() on an Int64 all iterator is a simple incrementing counter.
// Return the next integer, and mark it as the result.
func (it *Int64) Next() (graph.Value, bool) {
graph.NextLogIn(it)
if it.at == -1 {
return graph.NextLogOut(it, nil, false)
}
val := it.at
it.at = it.at + 1
if it.at > it.max {
it.at = -1
}
it.Last = val
return graph.NextLogOut(it, val, true)
}
示例10: Next
// Next advances the Not iterator. It returns whether there is another valid
// new value. It fetches the next value of the all iterator which is not
// contained by the primary iterator.
func (it *Not) Next() bool {
graph.NextLogIn(it)
it.runstats.Next += 1
for graph.Next(it.allIt) {
if curr := it.allIt.Result(); !it.primaryIt.Contains(curr) {
it.result = curr
it.runstats.ContainsNext += 1
return graph.NextLogOut(it, curr, true)
}
}
it.err = it.allIt.Err()
return graph.NextLogOut(it, nil, false)
}
示例11: Next
// Returns the Next value from the And iterator. Because the And is the
// intersection of its subiterators, it must choose one subiterator to produce a
// candidate, and check this value against the subiterators. A productive choice
// of primary iterator is therefore very important.
func (it *And) Next() (graph.TSVal, bool) {
graph.NextLogIn(it)
var curr graph.TSVal
var exists bool
for {
curr, exists = it.primaryIt.Next()
if !exists {
return graph.NextLogOut(it, nil, false)
}
if it.checkSubIts(curr) {
it.Last = curr
return graph.NextLogOut(it, curr, true)
}
}
panic("Somehow broke out of Next() loop in And")
}
示例12: Next
// Next advances the iterator. This is simpler than Contains. We have a
// subiterator we can get a value from, and we can take that resultant quad,
// pull our direction out of it, and return that.
func (it *HasA) Next() bool {
graph.NextLogIn(it)
it.runstats.Next += 1
if it.resultIt != nil {
it.resultIt.Close()
}
it.resultIt = &Null{}
if !graph.Next(it.primaryIt) {
return graph.NextLogOut(it, 0, false)
}
tID := it.primaryIt.Result()
val := it.qs.QuadDirection(tID, it.dir)
it.result = val
return graph.NextLogOut(it, val, true)
}
示例13: Next
func (it *Iterator) Next() bool {
graph.NextLogIn(it)
if it.iter == nil {
return graph.NextLogOut(it, nil, false)
}
result, _, err := it.iter.Next()
if err != nil {
return graph.NextLogOut(it, nil, false)
}
if !it.checkValid(result) {
return it.Next()
}
it.result = result
return graph.NextLogOut(it, it.result, true)
}
示例14: Next
func (it *Materialize) Next() bool {
graph.NextLogIn(it)
if !it.hasRun {
it.materializeSet()
}
if it.aborted {
return graph.Next(it.subIt)
}
it.index++
it.subindex = 0
if it.index >= len(it.values) {
return graph.NextLogOut(it, nil, false)
}
return graph.NextLogOut(it, it.Result(), true)
}
示例15: Next
// Returns the Next value from the And iterator. Because the And is the
// intersection of its subiterators, it must choose one subiterator to produce a
// candidate, and check this value against the subiterators. A productive choice
// of primary iterator is therefore very important.
func (it *And) Next() (graph.Value, bool) {
graph.NextLogIn(it)
var curr graph.Value
var exists bool
for {
curr, exists = graph.Next(it.primaryIt)
if !exists {
return graph.NextLogOut(it, nil, false)
}
if it.subItsContain(curr) {
it.result = curr
return graph.NextLogOut(it, curr, true)
}
}
panic("unreachable")
}