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Golang LRPAuction.Attempts方法代码示例

本文整理汇总了Golang中github.com/cloudfoundry-incubator/auction/auctiontypes.LRPAuction.Attempts方法的典型用法代码示例。如果您正苦于以下问题:Golang LRPAuction.Attempts方法的具体用法?Golang LRPAuction.Attempts怎么用?Golang LRPAuction.Attempts使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在github.com/cloudfoundry-incubator/auction/auctiontypes.LRPAuction的用法示例。


在下文中一共展示了LRPAuction.Attempts方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Golang代码示例。

示例1:

		})

		Context("when the cell rejects the start auction", func() {
			BeforeEach(func() {
				startAuction = BuildLRPAuction("pg-3", "domain", 1, linuxRootFSURL, 10, 10, clock.Now())

				clients["A-cell"].PerformReturns(rep.Work{LRPs: []rep.LRP{startAuction.LRP}}, nil)
				clients["B-cell"].PerformReturns(rep.Work{LRPs: []rep.LRP{startAuction.LRP}}, nil)

				clock.Increment(time.Minute)
				s := auctionrunner.NewScheduler(workPool, zones, clock, logger)
				results = s.Schedule(auctiontypes.AuctionRequest{LRPs: []auctiontypes.LRPAuction{startAuction}})
			})

			It("marks the start auction as failed", func() {
				startAuction.Attempts = 1
				Expect(results.SuccessfulLRPs).To(BeEmpty())
				Expect(results.FailedLRPs).To(ConsistOf(startAuction))
			})
		})

		Context("when there is no room", func() {
			BeforeEach(func() {
				startAuction = BuildLRPAuctionWithPlacementError("pg-4", "domain", 0, linuxRootFSURL, 1000, 1000, clock.Now(), rep.ErrorInsufficientResources.Error())
				clock.Increment(time.Minute)
				s := auctionrunner.NewScheduler(workPool, zones, clock, logger)
				results = s.Schedule(auctiontypes.AuctionRequest{LRPs: []auctiontypes.LRPAuction{startAuction}})
			})

			It("should not attempt to start the LRP", func() {
				Expect(clients["A-cell"].PerformCallCount()).To(Equal(0))
开发者ID:emc-xchallenge,项目名称:auction,代码行数:31,代码来源:scheduler_test.go


注:本文中的github.com/cloudfoundry-incubator/auction/auctiontypes.LRPAuction.Attempts方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。