本文整理汇总了C#中System.Tuple<T1,T2,T3,T4,T5,T6>.Equals方法的典型用法代码示例。如果您正苦于以下问题：C# Tuple<T1,T2,T3,T4,T5,T6>.Equals方法的具体用法？C# Tuple<T1,T2,T3,T4,T5,T6>.Equals怎么用？C# Tuple<T1,T2,T3,T4,T5,T6>.Equals使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类System.Tuple<T1,T2,T3,T4,T5,T6>的用法示例。
在下文中一共展示了Tuple<T1,T2,T3,T4,T5,T6>.Equals方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C#代码示例。
示例1: Main
//引入命名空间
using System;
public class Example
{
public static void Main()
{
// Get population data for New York City and Los Angeles, 1960-2000.
Tuple<string, int, int, int, int, int>[] urbanPopulations =
{ Tuple.Create("New York", 7781984, 7894862, 7071639, 7322564, 8008278),
Tuple.Create("Los Angeles", 2479015, 2816061, 2966850, 3485398, 3694820),
Tuple.Create("New York City", 7781984, 7894862, 7071639, 7322564, 8008278),
Tuple.Create("New York", 7781984, 7894862, 7071639, 7322564, 8008278) };
// Compare each tuple with every other tuple for equality.
for (int ctr = 0; ctr <= urbanPopulations.Length - 2; ctr++)
{
var urbanPopulation = urbanPopulations[ctr];
Console.WriteLine(urbanPopulation.ToString() + " = ");
for (int innerCtr = ctr +1; innerCtr <= urbanPopulations.Length - 1; innerCtr++)
Console.WriteLine(" {0}: {1}", urbanPopulations[innerCtr],
urbanPopulation.Equals(urbanPopulations[innerCtr]));
Console.WriteLine();
}
}
}输出：
(New York, 7781984, 7894862, 7071639, 7322564, 8008278) = (Los Angeles, 2479015, 2816061, 2966850, 3485398, 3694820): False (New York City, 7781984, 7894862, 7071639, 7322564, 8008278): False (New York, 7781984, 7894862, 7071639, 7322564, 8008278): True (Los Angeles, 2479015, 2816061, 2966850, 3485398, 3694820) = (New York City, 7781984, 7894862, 7071639, 7322564, 8008278): False (New York, 7781984, 7894862, 7071639, 7322564, 8008278): False (New York City, 7781984, 7894862, 7071639, 7322564, 8008278) = (New York, 7781984, 7894862, 7071639, 7322564, 8008278): False