本文整理汇总了C#中System.Linq.Queryable.All<TSource>方法的典型用法代码示例。如果您正苦于以下问题：C# Queryable.All<TSource>方法的具体用法？C# Queryable.All<TSource>怎么用？C# Queryable.All<TSource>使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。
在下文中一共展示了Queryable.All<TSource>方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C#代码示例。
示例1: AllEx1
class Pet
{
public string Name { get; set; }
public int Age { get; set; }
}
public static void AllEx1()
{
// Create an array of Pets.
Pet[] pets = { new Pet { Name="Barley", Age=10 },
new Pet { Name="Boots", Age=4 },
new Pet { Name="Whiskers", Age=6 } };
// Determine whether all pet names in the array start with 'B'.
bool allStartWithB =
pets.AsQueryable().All(pet => pet.Name.StartsWith("B"));
Console.WriteLine(
"{0} pet names start with 'B'.",
allStartWithB ? "All" : "Not all");
}输出：
Not all pet names start with 'B'.
示例2: AllEx2
class Pet
{
public string Name { get; set; }
public int Age { get; set; }
}
class Person
{
public string LastName { get; set; }
public Pet[] Pets { get; set; }
}
public static void AllEx2()
{
List<Person> people = new List<Person>
{ new Person { LastName = "Haas",
Pets = new Pet[] { new Pet { Name="Barley", Age=10 },
new Pet { Name="Boots", Age=14 },
new Pet { Name="Whiskers", Age=6 }}},
new Person { LastName = "Fakhouri",
Pets = new Pet[] { new Pet { Name = "Snowball", Age = 1}}},
new Person { LastName = "Antebi",
Pets = new Pet[] { new Pet { Name = "Belle", Age = 8} }},
new Person { LastName = "Philips",
Pets = new Pet[] { new Pet { Name = "Sweetie", Age = 2},
new Pet { Name = "Rover", Age = 13}} }
};
// Determine which people have pets that are all older than 5.
IEnumerable<string> names = from person in people
where person.Pets.AsQueryable().All(pet => pet.Age > 5)
select person.LastName;
foreach (string name in names)
Console.WriteLine(name);
/* This code produces the following output:
*
* Haas
* Antebi
*/
}