本文整理汇总了C#中com.ximpleware.VTDNav.XPathStringLength方法的典型用法代码示例。如果您正苦于以下问题：C# VTDNav.XPathStringLength方法的具体用法？C# VTDNav.XPathStringLength怎么用？C# VTDNav.XPathStringLength使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类com.ximpleware.VTDNav的用法示例。
在下文中一共展示了VTDNav.XPathStringLength方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C#代码示例。
示例1: getStringLen
private int getStringLen(VTDNav vn)
{
if (argCount1 == 0)
{
try
{
if (vn.atTerminal == true)
{
int type = vn.getTokenType(vn.LN);
if (type == VTDNav.TOKEN_ATTR_NAME || type == VTDNav.TOKEN_ATTR_NS)
{
return vn.getStringLength(vn.LN + 1);
}
else
{
return vn.getStringLength(vn.LN);
}
}
else
{
int k = vn.getCurrentIndex2();
// int type = vn.getTokenType(k);
return vn.XPathStringLength(k);
}
}
catch (NavException e)
{
return 0;
}
}
else if (argCount1 == 1)
{
int result = 0;
if (argumentList.e.NodeSet)
{
int a = 0x7fffffff, k = -1;
vn.push2();
int size = vn.contextStack2.size;
try
{
if (argumentList.e.needReordering)
{
argumentList.e.adjust(vn.getTokenCount());
while ((k = argumentList.e.evalNodeSet(vn)) != -1)
{
if (k < a)
a = k; // a is always smaller
}
if (a == 0x7fffffff)
{
a = -1;
}
}
else
{
a = argumentList.e.evalNodeSet(vn);
}
if (a == -1)
result = 0;
else
{
int type = vn.getTokenType(a);
if (type == VTDNav.TOKEN_ATTR_NAME || type == VTDNav.TOKEN_ATTR_NS || type == VTDNav.TOKEN_PI_NAME)
{
result = vn.getStringLength(a + 1);
}
else if (type == VTDNav.TOKEN_STARTING_TAG || type == VTDNav.TOKEN_DOCUMENT)
{
result = vn.XPathStringLength(a);
}
else
{
result = vn.getStringLength(a);
}
}
}
catch (VTDException e)
{
}
argumentList.e.reset(vn);
vn.contextStack2.size = size;
vn.pop2();
return result;
}
else
return argumentList.e.evalString(vn).Length;
}
else
{
throw new System.ArgumentException("string-length()'s argument count is invalid");
}
}