本文整理汇总了C#中System.Web.Razor.Parser.SyntaxTree.Block.LocateOwner方法的典型用法代码示例。如果您正苦于以下问题：C# Block.LocateOwner方法的具体用法？C# Block.LocateOwner怎么用？C# Block.LocateOwner使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类System.Web.Razor.Parser.SyntaxTree.Block的用法示例。
在下文中一共展示了Block.LocateOwner方法的4个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C#代码示例。
示例1: LocateOwnerReturnsNullIfNoSpanReturnsTrueForOwnsSpan
public void LocateOwnerReturnsNullIfNoSpanReturnsTrueForOwnsSpan() {
// Arrange
Block block = new Block(BlockType.Markup, new SyntaxTreeNode[] {
new MarkupSpan(SourceLocation.Zero, "Foo "),
new StatementBlock(new SyntaxTreeNode[] {
new TransitionSpan(new SourceLocation(4, 0, 4), "@"),
new CodeSpan(new SourceLocation(5, 0, 5), "bar"),
}),
new MarkupSpan(new SourceLocation(8,0,8), " Baz")
});
TextChange change = new TextChange(128, 1, new StringTextBuffer("Foo @bar Baz"), 1, new StringTextBuffer("Foo @bor Baz"));
// Act
Span actual = block.LocateOwner(change);
// Assert
Assert.IsNull(actual);
}示例2: TreesAreDifferent
internal static bool TreesAreDifferent(Block leftTree, Block rightTree, IEnumerable<TextChange> changes, CancellationToken cancelToken)
{
// Apply all the pending changes to the original tree
// PERF: If this becomes a bottleneck, we can probably do it the other way around,
// i.e. visit the tree and find applicable changes for each node.
foreach (TextChange change in changes)
{
cancelToken.ThrowIfCancellationRequested();
Span changeOwner = leftTree.LocateOwner(change);
// Apply the change to the tree
if (changeOwner == null)
{
return true;
}
EditResult result = changeOwner.EditHandler.ApplyChange(changeOwner, change, force: true);
changeOwner.ReplaceWith(result.EditedSpan);
}
// Now compare the trees
bool treesDifferent = !leftTree.EquivalentTo(rightTree);
return treesDifferent;
}示例3: TreesAreDifferent
internal static bool TreesAreDifferent(Block leftTree, Block rightTree, TextChange[] changes)
{
// Apply all the pending changes to the original tree
// PERF: If this becomes a bottleneck, we can probably do it the other way around,
// i.e. visit the tree and find applicable changes for each node.
foreach (TextChange change in changes)
{
Span changeOwner = leftTree.LocateOwner(change);
// Apply the change to the tree
if (changeOwner == null)
{
return true;
}
EditResult result = changeOwner.EditHandler.ApplyChange(changeOwner, change, force: true);
changeOwner.ReplaceWith(result.EditedSpan);
}
// Now compare the trees
bool treesDifferent = !leftTree.EquivalentTo(rightTree);
#if DEBUG
if (RazorDebugHelpers.OutputDebuggingEnabled)
{
Debug.WriteLine(String.Format(CultureInfo.CurrentCulture, "Processed {0} changes, trees were{1} different", changes.Length, treesDifferent ? String.Empty : " not"));
}
#endif
return treesDifferent;
}示例4: TreesAreDifferent
private static bool TreesAreDifferent(Block leftTree, Block rightTree, TextChange change) {
Span changeOwner = leftTree.LocateOwner(change);
// Apply the change to the tree
if (changeOwner == null) {
return true;
}
changeOwner.ApplyChange(change, force: true);
// Now compare the trees
return !Equals(leftTree, rightTree);
}