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C# Vector.Clone方法代码示例

本文整理汇总了C#中System.Numerics.Vector.Clone方法的典型用法代码示例。如果您正苦于以下问题:C# Vector.Clone方法的具体用法?C# Vector.Clone怎么用?C# Vector.Clone使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在System.Numerics.Vector的用法示例。


在下文中一共展示了Vector.Clone方法的2个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C#代码示例。

示例1: Approximate

        /// <summary>
        /// Approximates the solution to the matrix equation <b>Ax = b</b>.
        /// </summary>
        /// <param name="rhs">The right hand side vector.</param>
        /// <param name="lhs">The left hand side vector. Also known as the result vector.</param>
        public void Approximate(Vector rhs, Vector lhs)
        {
            if (rhs == null)
            {
                throw new ArgumentNullException("rhs");
            }

            if (lhs == null)
            {
                throw new ArgumentNullException("lhs");
            }

            if (_upper == null)
            {
                throw new ArgumentException(Resources.ArgumentMatrixDoesNotExist);
            }

            if ((lhs.Count != rhs.Count) || (lhs.Count != _upper.RowCount))
            {
                throw new ArgumentException(Resources.ArgumentVectorsSameLength, "rhs");
            }

            // Solve equation here
            // Pivot(vector, result);
            // Solve L*Y = B(piv,:)
            Vector rowValues = new DenseVector(_lower.RowCount);
            for (var i = 0; i < _lower.RowCount; i++)
            {
                _lower.Row(i, rowValues);

                var sum = Complex.Zero;
                for (var j = 0; j < i; j++)
                {
                    sum += rowValues[j] * lhs[j];
                }

                lhs[i] = rhs[i] - sum;
            }

            // Solve U*X = Y;
            for (var i = _upper.RowCount - 1; i > -1; i--)
            {
                _upper.Row(i, rowValues);

                var sum = Complex.Zero;
                for (var j = _upper.RowCount - 1; j > i; j--)
                {
                    sum += rowValues[j] * lhs[j];
                }

                lhs[i] = 1 / rowValues[i] * (lhs[i] - sum);
            }

            // We have a column pivot so we only need to pivot the
            // end result not the incoming right hand side vector
            var temp = (Vector)lhs.Clone();

            Pivot(temp, lhs);
        }
开发者ID:KeithVanderzanden,项目名称:mmbot,代码行数:64,代码来源:Ilutp.cs

示例2: Solve

        /// <summary>
        /// Solves a system of linear equations, <b>Ax = b</b>, with A QR factorized.
        /// </summary>
        /// <param name="input">The right hand side vector, <b>b</b>.</param>
        /// <param name="result">The left hand side <see cref="Matrix{T}"/>, <b>x</b>.</param>
        public override void Solve(Vector<Complex> input, Vector<Complex> result)
        {
            // Ax=b where A is an m x n matrix
            // Check that b is a column vector with m entries
            if (FullR.RowCount != input.Count)
            {
                throw new ArgumentException(Resources.ArgumentVectorsSameLength);
            }

            // Check that x is a column vector with n entries
            if (FullR.ColumnCount != result.Count)
            {
                throw Matrix.DimensionsDontMatch<ArgumentException>(FullR, result);
            }

            var inputCopy = input.Clone();

            // Compute Y = transpose(Q)*B
            var column = new Complex[FullR.RowCount];
            for (var k = 0; k < FullR.RowCount; k++)
            {
                column[k] = inputCopy[k];
            }

            for (var i = 0; i < FullR.RowCount; i++)
            {
                var s = Complex.Zero;
                for (var k = 0; k < FullR.RowCount; k++)
                {
                    s += Q.At(k, i).Conjugate()*column[k];
                }

                inputCopy[i] = s;
            }

            // Solve R*X = Y;
            for (var k = FullR.ColumnCount - 1; k >= 0; k--)
            {
                inputCopy[k] /= FullR.At(k, k);
                for (var i = 0; i < k; i++)
                {
                    inputCopy[i] -= inputCopy[k]*FullR.At(i, k);
                }
            }

            for (var i = 0; i < FullR.ColumnCount; i++)
            {
                result[i] = inputCopy[i];
            }
        }
开发者ID:Jungwon,项目名称:mathnet-numerics,代码行数:55,代码来源:UserQR.cs


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