本文整理汇总了C#中System.Numerics.Complex.SquareRoot方法的典型用法代码示例。如果您正苦于以下问题：C# Complex.SquareRoot方法的具体用法？C# Complex.SquareRoot怎么用？C# Complex.SquareRoot使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类System.Numerics.Complex的用法示例。
在下文中一共展示了Complex.SquareRoot方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C#代码示例。
示例1: CanComputeSquareRoot
public void CanComputeSquareRoot()
{
var complex = new Complex(1.19209289550780998537e-7, 1.19209289550780998537e-7);
AssertHelpers.AlmostEqual(
new Complex(0.00037933934912842666, 0.00015712750315077684), complex.SquareRoot(), 15);
complex = new Complex(0.0, 1.19209289550780998537e-7);
AssertHelpers.AlmostEqual(
new Complex(0.00024414062499999973, 0.00024414062499999976), complex.SquareRoot(), 15);
complex = new Complex(0.0, -1.19209289550780998537e-7);
AssertHelpers.AlmostEqual(
new Complex(0.00024414062499999973, -0.00024414062499999976), complex.SquareRoot(), 15);
complex = new Complex(0.0, 0.5);
AssertHelpers.AlmostEqual(new Complex(0.5, 0.5), complex.SquareRoot(), 15);
complex = new Complex(0.0, -0.5);
AssertHelpers.AlmostEqual(new Complex(0.5, -0.5), complex.SquareRoot(), 15);
complex = new Complex(0.0, -8.388608e6);
AssertHelpers.AlmostEqual(new Complex(2048.0, -2048.0), complex.SquareRoot(), 15);
complex = new Complex(8.388608e6, 1.19209289550780998537e-7);
AssertHelpers.AlmostEqual(new Complex(2896.3093757400989, 2.0579515874459933e-11), complex.SquareRoot(), 15);
complex = new Complex(0.0, 0.0);
AssertHelpers.AlmostEqual(Complex.Zero, complex.SquareRoot(), 15);
}