本文整理汇总了C#中System.Globalization.Calendar.GetDaysInYear方法的典型用法代码示例。如果您正苦于以下问题:C# Calendar.GetDaysInYear方法的具体用法?C# Calendar.GetDaysInYear怎么用?C# Calendar.GetDaysInYear使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类System.Globalization.Calendar
的用法示例。
在下文中一共展示了Calendar.GetDaysInYear方法的5个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C#代码示例。
示例1: AssertEquivalent
/// <summary>
/// Checks that each day from the given start year to the end year (inclusive) is equal
/// between the BCL and the Noda Time calendar. Additionally, the number of days in each month and year
/// and the number of months (and leap year status) in each year is checked.
/// </summary>
internal static void AssertEquivalent(Calendar bcl, CalendarSystem noda, int fromYear, int toYear)
{
// We avoid asking the BCL to create a DateTime on each iteration, simply
// because the BCL implementation is so slow. Instead, we just check at the start of each month that
// we're at the date we expect.
DateTime bclDate = bcl.ToDateTime(fromYear, 1, 1, 0, 0, 0, 0);
for (int year = fromYear; year <= toYear; year++)
{
Assert.AreEqual(bcl.GetDaysInYear(year), noda.GetDaysInYear(year), "Year: {0}", year);
Assert.AreEqual(bcl.GetMonthsInYear(year), noda.GetMonthsInYear(year), "Year: {0}", year);
for (int month = 1; month <= noda.GetMonthsInYear(year); month++)
{
// Sanity check at the start of each month. Even this is surprisingly slow.
// (These three tests make up about 20% of the total execution time for the test.)
Assert.AreEqual(year, bcl.GetYear(bclDate));
Assert.AreEqual(month, bcl.GetMonth(bclDate));
Assert.AreEqual(1, bcl.GetDayOfMonth(bclDate));
Assert.AreEqual(bcl.GetDaysInMonth(year, month), noda.GetDaysInMonth(year, month),
"Year: {0}; Month: {1}", year, month);
Assert.AreEqual(bcl.IsLeapYear(year), noda.IsLeapYear(year), "Year: {0}", year);
for (int day = 1; day <= noda.GetDaysInMonth(year, month); day++)
{
LocalDate nodaDate = new LocalDate(year, month, day, noda);
Assert.AreEqual(bclDate, nodaDate.ToDateTimeUnspecified(),
"Original calendar system date: {0:yyyy-MM-dd}", nodaDate);
Assert.AreEqual(nodaDate, LocalDate.FromDateTime(bclDate, noda));
Assert.AreEqual(year, nodaDate.Year);
Assert.AreEqual(month, nodaDate.Month);
Assert.AreEqual(day, nodaDate.Day);
bclDate = bclDate.AddDays(1);
}
}
}
}
示例2: Year
// ----------------------------------------------------------------------
public static TimeSpan Year( Calendar calendar, int year )
{
return Days( calendar.GetDaysInYear( year ) );
}
示例3: TestDaysInYear
public void TestDaysInYear (Calendar calendar, int year)
{
var daysInYear = calendar.GetDaysInYear (year);
var daysInMonths = 0;
var monthInYear = calendar.GetMonthsInYear (year);
for (var m = 1; m <= monthInYear; m++)
daysInMonths += calendar.GetDaysInMonth (year, m);
Assert.AreEqual (daysInYear, daysInMonths, string.Format("Calendar:{0} Year:{1}",calendar.GetType(), year));
}
示例4: InternalGetWeekOfYearFullDays
// This is copied from the generic implementation of GetWeekOfYearFullDays() in Calendar.cs. The generic implementation is not good enough
// in the case of FristFullWeek and FirstFourDayWeek since it needs the data for B.C. year 1 near 0001/1/1.
// We override the generic implementation to handle this special case.
// Parameters
//
internal static int InternalGetWeekOfYearFullDays(Calendar cal, DateTime time, int firstDayOfWeek, int fullDays, int daysOfMinYearMinusOne) {
int dayForJan1;
int offset;
int day;
int dayOfYear = cal.GetDayOfYear(time) - 1; // Make the day of year to be 0-based, so that 1/1 is day 0.
//
// Calculate the number of days between the first day of year (1/1) and the first day of the week.
// This value will be a positive value from 0 ~ 6. We call this value as "offset".
//
// If offset is 0, it means that the 1/1 is the start of the first week.
// Assume the first day of the week is Monday, it will look like this:
// Sun Mon Tue Wed Thu Fri Sat
// 12/31 1/1 1/2 1/3 1/4 1/5 1/6
// +--> First week starts here.
//
// If offset is 1, it means that the first day of the week is 1 day ahead of 1/1.
// Assume the first day of the week is Monday, it will look like this:
// Sun Mon Tue Wed Thu Fri Sat
// 1/1 1/2 1/3 1/4 1/5 1/6 1/7
// +--> First week starts here.
//
// If offset is 2, it means that the first day of the week is 2 days ahead of 1/1.
// Assume the first day of the week is Monday, it will look like this:
// Sat Sun Mon Tue Wed Thu Fri Sat
// 1/1 1/2 1/3 1/4 1/5 1/6 1/7 1/8
// +--> First week starts here.
// Day of week is 0-based.
// Get the day of week for 1/1. This can be derived from the day of week of the target day.
// Note that we can get a negative value. It's ok since we are going to make it a positive value when calculating the offset.
dayForJan1 = (int)cal.GetDayOfWeek(time) - (dayOfYear % 7);
// Now, calucalte the offset. Substract the first day of week from the dayForJan1. And make it a positive value.
offset = (firstDayOfWeek - dayForJan1 + 14) % 7;
if (offset != 0 && offset >= fullDays)
{
//
// If the offset is greater than the value of fullDays, it means that
// the first week of the year starts on the week where Jan/1 falls on.
//
offset -= 7;
}
//
// Calculate the day of year for specified time by taking offset into account.
//
day = dayOfYear - offset;
if (day >= 0) {
//
// If the day of year value is greater than zero, get the week of year.
//
return (day/7 + 1);
}
//
// Otherwise, the specified time falls on the week of previous year.
// Note that it is not always week 52 or 53, because it depends on the calendar. Different calendars have different number of days in a year.
//
// Repeat the previous calculation logic using the previous year and calculate the week of year for the last day of previous year.
int year = cal.GetYear(time);
if (year <= cal.GetYear(cal.MinSupportedDateTime)) {
// This specified time is in 0001/1/1 ~ 0001/1/7.
dayOfYear = daysOfMinYearMinusOne;
} else {
dayOfYear = cal.GetDaysInYear(year - 1);
}
dayForJan1 = dayForJan1 - (dayOfYear % 7);
// Now, calucalte the offset. Substract the first day of week from the dayForJan1. And make it a positive value.
offset = (firstDayOfWeek - dayForJan1 + 14) % 7;
if (offset != 0 && offset >= fullDays)
{
//
// If the offset is greater than the value of fullDays, it means that
// the first week of the year starts on the week where Jan/1 falls on.
//
offset -= 7;
}
//
// Calculate the day of year for specified time by taking offset into account.
//
day = dayOfYear - offset;
return (day/7 + 1);
}
示例5: InternalGetWeekOfYearFullDays
internal static int InternalGetWeekOfYearFullDays(Calendar cal, DateTime time, int firstDayOfWeek, int fullDays, int daysOfMinYearMinusOne)
{
int daysInYear = cal.GetDayOfYear(time) - 1;
int num = ((int) cal.GetDayOfWeek(time)) - (daysInYear % 7);
int num2 = ((firstDayOfWeek - num) + 14) % 7;
if ((num2 != 0) && (num2 >= fullDays))
{
num2 -= 7;
}
int num3 = daysInYear - num2;
if (num3 < 0)
{
int year = cal.GetYear(time);
if (year <= cal.GetYear(cal.MinSupportedDateTime))
{
daysInYear = daysOfMinYearMinusOne;
}
else
{
daysInYear = cal.GetDaysInYear(year - 1);
}
num -= daysInYear % 7;
num2 = ((firstDayOfWeek - num) + 14) % 7;
if ((num2 != 0) && (num2 >= fullDays))
{
num2 -= 7;
}
num3 = daysInYear - num2;
}
return ((num3 / 7) + 1);
}