本文整理汇总了C#中SimpleCalculator.Parse.secondNum方法的典型用法代码示例。如果您正苦于以下问题：C# Parse.secondNum方法的具体用法？C# Parse.secondNum怎么用？C# Parse.secondNum使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类SimpleCalculator.Parse的用法示例。
在下文中一共展示了Parse.secondNum方法的5个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C#代码示例。
示例1: Main
static void Main(string[] args)
{
int count = 0;
Constant currentConstant = new Constant();
Evaluate expression;
while (true)
{
Console.Write("[{0}]> ", count);
string input = Console.ReadLine();
expression = new Evaluate(input, currentConstant);
if (input.ToLower() == "exit" || input.ToLower() == "quit")
{
break;
}
else if (input.IndexOf("=")> -1)
{
//set variable
Parse addConstant = new Parse(input, currentConstant);
addConstant.setOperatorIndex();
currentConstant.addConst(addConstant.StringFirst(), addConstant.secondNum());
// = saved 'x' as '3'
Console.WriteLine("= saved '" + addConstant.StringFirst() + "' as '" + addConstant.secondNum() + "'");
}
else
{
int answer = expression.doMath();
Console.WriteLine(" = {0}", answer);
count++;
}
}
}示例2: ParseOnlyAllowsSimpleExpressions
public void ParseOnlyAllowsSimpleExpressions()
{
Parse twoPlusThree = new Parse("2 - 5 + 3");
twoPlusThree.setOperatorIndex();
twoPlusThree.firstNum();
twoPlusThree.secondNum();
}示例3: ParseCanFindSecondNum
public void ParseCanFindSecondNum()
{
Parse twoPlusThree = new Parse("2 + 3");
twoPlusThree.setOperatorIndex();
twoPlusThree.firstNum();
Assert.AreEqual(3, twoPlusThree.secondNum());
}示例4: ParseOnlyAllowsNumbersSecond
public void ParseOnlyAllowsNumbersSecond()
{
Parse twoPlusThree = new Parse("2 + b");
twoPlusThree.setOperatorIndex();
twoPlusThree.firstNum();
twoPlusThree.secondNum();
}示例5: ParseAllowsConstantsSecond
public void ParseAllowsConstantsSecond()
{
Constant newConstant = new Constant();
Parse aplus3 = new Parse("3 + a", newConstant);
aplus3.addConst("a", 5);
aplus3.setOperatorIndex();
aplus3.firstNum();
Assert.AreEqual(5, aplus3.secondNum());
}