本文整理汇总了C#中Microsoft.CodeAnalysis.CSharp.Syntax.NameSyntax.GetNameToken方法的典型用法代码示例。如果您正苦于以下问题:C# NameSyntax.GetNameToken方法的具体用法?C# NameSyntax.GetNameToken怎么用?C# NameSyntax.GetNameToken使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类Microsoft.CodeAnalysis.CSharp.Syntax.NameSyntax
的用法示例。
在下文中一共展示了NameSyntax.GetNameToken方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C#代码示例。
示例1: TryClassifySymbol
private bool TryClassifySymbol(
NameSyntax name,
ISymbol symbol,
SemanticModel semanticModel,
CancellationToken cancellationToken,
out ClassifiedSpan classifiedSpan)
{
if (symbol != null)
{
// see through using aliases
if (symbol.Kind == SymbolKind.Alias)
{
symbol = (symbol as IAliasSymbol).Target;
}
else if (symbol.IsConstructor() && name.IsParentKind(SyntaxKind.Attribute))
{
symbol = symbol.ContainingType;
}
}
if (name.IsVar &&
IsInVarContext(name))
{
var alias = semanticModel.GetAliasInfo(name, cancellationToken);
if (alias == null || alias.Name != "var")
{
if (!IsSymbolCalledVar(symbol))
{
// We bound to a symbol. If we bound to a symbol called "var" then we want to
// classify this appropriately as a type. Otherwise, we want to classify this as
// a keyword.
classifiedSpan = new ClassifiedSpan(name.Span, ClassificationTypeNames.Keyword);
return true;
}
}
}
if (symbol != null)
{
// Use .Equals since we can't rely on object identity for constructed types.
if (symbol is ITypeSymbol)
{
var classification = GetClassificationForType((ITypeSymbol)symbol);
if (classification != null)
{
var token = name.GetNameToken();
classifiedSpan = new ClassifiedSpan(token.Span, classification);
return true;
}
}
}
classifiedSpan = default(ClassifiedSpan);
return false;
}