本文整理汇总了C#中ICSharpCode.TreeView.SharpTreeNode.RotateLeft方法的典型用法代码示例。如果您正苦于以下问题：C# SharpTreeNode.RotateLeft方法的具体用法？C# SharpTreeNode.RotateLeft怎么用？C# SharpTreeNode.RotateLeft使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类ICSharpCode.TreeView.SharpTreeNode的用法示例。
在下文中一共展示了SharpTreeNode.RotateLeft方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C#代码示例。
示例1: Rebalance
/// <summary>
/// Balances the subtree rooted in <paramref name="node"/> and recomputes the 'height' field.
/// This method assumes that the children of this node are already balanced and have an up-to-date 'height' value.
/// </summary>
/// <returns>The new root node</returns>
static SharpTreeNode Rebalance(SharpTreeNode node)
{
Debug.Assert(node.left == null || Math.Abs(node.left.Balance) <= 1);
Debug.Assert(node.right == null || Math.Abs(node.right.Balance) <= 1);
// Keep looping until it's balanced. Not sure if this is stricly required; this is based on
// the Rope code where node merging made this necessary.
while (Math.Abs(node.Balance) > 1) {
// AVL balancing
// note: because we don't care about the identity of concat nodes, this works a little different than usual
// tree rotations: in our implementation, the "this" node will stay at the top, only its children are rearranged
if (node.Balance > 1) {
if (node.right.Balance < 0) {
node.right = node.right.RotateRight();
}
node = node.RotateLeft();
// If 'node' was unbalanced by more than 2, we've shifted some of the inbalance to the left node; so rebalance that.
node.left = Rebalance(node.left);
} else if (node.Balance < -1) {
if (node.left.Balance > 0) {
node.left = node.left.RotateLeft();
}
node = node.RotateRight();
// If 'node' was unbalanced by more than 2, we've shifted some of the inbalance to the right node; so rebalance that.
node.right = Rebalance(node.right);
}
}
Debug.Assert(Math.Abs(node.Balance) <= 1);
node.height = (byte)(1 + Math.Max(Height(node.left), Height(node.right)));
node.totalListLength = -1; // mark for recalculation
// since balancing checks the whole tree up to the root, the whole path will get marked as invalid
return node;
}