本文整理汇总了C#中Funq.Container.EasyRegister方法的典型用法代码示例。如果您正苦于以下问题：C# Container.EasyRegister方法的具体用法？C# Container.EasyRegister怎么用？C# Container.EasyRegister使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类Funq.Container的用法示例。
在下文中一共展示了Container.EasyRegister方法的4个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C#代码示例。
示例1: should_be_able_to_inject_dependency
public void should_be_able_to_inject_dependency()
{
var c = new Container();
c.EasyRegister<IFoo, Foo>();
c.EasyRegister<IBar, Bar>();
var bar = c.Resolve<IBar>() as Bar;
Assert.IsNotNull(bar.Foo);
}示例2: should_be_able_to_chain_dependencies
public void should_be_able_to_chain_dependencies()
{
var c = new Container();
var testFoo = new Foo();
c.Register<IFoo>(testFoo);
c.EasyRegister<IBar, Bar>();
c.EasyRegister<IBaz, Baz>();
var baz = c.Resolve<IBaz>() as Baz;
var bar = baz.Bar as Bar;
Assert.AreSame(bar.Foo, testFoo);
}示例3: should_be_able_to_get_service_impl
public void should_be_able_to_get_service_impl()
{
var c = new Container();
c.EasyRegister<IFoo, Foo>();
Assert.IsInstanceOf<Foo>(c.Resolve<IFoo>());
}示例4: should_be_able_to_get_service_impl
public void should_be_able_to_get_service_impl()
{
var c = new Container();
c.EasyRegister<IFoo, Foo>();
c.Resolve<IFoo>().GetType().ShouldEqual(typeof(Foo));
}