本文整理汇总了C#中Accord.Math.Decompositions.SingularValueDecomposition.Solve方法的典型用法代码示例。如果您正苦于以下问题：C# SingularValueDecomposition.Solve方法的具体用法？C# SingularValueDecomposition.Solve怎么用？C# SingularValueDecomposition.Solve使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类Accord.Math.Decompositions.SingularValueDecomposition的用法示例。
在下文中一共展示了SingularValueDecomposition.Solve方法的6个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C#代码示例。
示例1: SquareMahalanobis
/// <summary>
/// Gets the Square Mahalanobis distance between two points.
/// </summary>
///
/// <param name="x">A point in space.</param>
/// <param name="y">A point in space.</param>
/// <param name="covariance">
/// The <see cref="SingularValueDecomposition"/> of the covariance
/// matrix of the distribution for the two points x and y.
/// </param>
///
/// <returns>The Square Mahalanobis distance between x and y.</returns>
///
public static double SquareMahalanobis(this double[] x, double[] y, SingularValueDecomposition covariance)
{
double[] d = new double[x.Length];
for (int i = 0; i < x.Length; i++)
d[i] = x[i] - y[i];
double[] z = covariance.Solve(d);
double r = 0.0;
for (int i = 0; i < d.Length; i++)
r += d[i] * z[i];
return Math.Abs(r);
}示例2: InverseTest
public void InverseTest()
{
double[,] value = new double[,]
{
{ 1.0, 1.0 },
{ 2.0, 2.0 }
};
SingularValueDecomposition target = new SingularValueDecomposition(value);
double[,] expected = new double[,]
{
{ 0.1, 0.2 },
{ 0.1, 0.2 }
};
double[,] actual = target.Solve(Matrix.Identity(2));
Assert.IsTrue(Matrix.IsEqual(expected, actual, 0.001));
actual = target.Inverse();
Assert.IsTrue(Matrix.IsEqual(expected, actual, 0.001));
}示例3: InverseTest2
public void InverseTest2()
{
int n = 5;
var I = Matrix.Identity(n);
for (int i = 0; i < n; i++)
{
for (int j = 0; j < n; j++)
{
double[,] value = Matrix.Magic(n);
var target = new SingularValueDecomposition(value);
double[,] solution = target.Solve(I);
double[,] inverse = target.Inverse();
double[,] reverse = target.Reverse();
Assert.IsTrue(Matrix.IsEqual(solution, inverse, 1e-4));
Assert.IsTrue(Matrix.IsEqual(value, reverse, 1e-4));
}
}
}示例4: MahalanobisTest3
public void MahalanobisTest3()
{
// Example from Statistical Distance Calculator
// http://maplepark.com/~drf5n/cgi-bin/dist.cgi
double[,] cov =
{
{ 1.030303, 2.132728, 0.576716 },
{ 2.132728, 4.510515, 1.185771 },
{ 0.576716, 1.185771, 0.398922 }
};
double[] x, y;
double actual, expected;
var svd = new SingularValueDecomposition(cov, true, true, true);
var inv = cov.Inverse();
var pinv = svd.Inverse();
Assert.IsTrue(inv.IsEqual(pinv, 1e-6));
x = new double[] { 2, 4, 1 };
y = new double[] { 0, 0, 0 };
{
var bla = cov.Solve(x);
var blo = svd.Solve(x);
var ble = inv.Multiply(x);
var bli = pinv.Multiply(x);
Assert.IsTrue(bla.IsEqual(blo, 1e-6));
Assert.IsTrue(bla.IsEqual(ble, 1e-6));
Assert.IsTrue(bla.IsEqual(bli, 1e-6));
}
expected = 2.0773536867741504;
actual = Distance.Mahalanobis(x, y, inv);
Assert.AreEqual(expected, actual, 1e-6);
actual = Distance.Mahalanobis(x, y, svd);
Assert.AreEqual(expected, actual, 1e-6);
x = new double[] { 7, 5, 1 };
y = new double[] { 1, 0.52, -79 };
expected = 277.8828871106366;
actual = Distance.Mahalanobis(x, y, inv);
Assert.AreEqual(expected, actual, 1e-5);
actual = Distance.Mahalanobis(x, y, svd);
Assert.AreEqual(expected, actual, 1e-5);
}示例5: SingularValueDecompositionConstructorTest7
public void SingularValueDecompositionConstructorTest7()
{
int count = 100;
double[,] value = new double[count, 3];
double[] output = new double[count];
for (int i = 0; i < count; i++)
{
double x = i + 1;
double y = 2 * (i + 1) - 1;
value[i, 0] = x;
value[i, 1] = y;
value[i, 2] = 1;
output[i] = 4 * x - y + 3;
}
SingularValueDecomposition target = new SingularValueDecomposition(value,
computeLeftSingularVectors: true,
computeRightSingularVectors: true);
{
double[,] expected = value;
double[,] actual = target.LeftSingularVectors.Multiply(
Matrix.Diagonal(target.Diagonal)).Multiply(target.RightSingularVectors.Transpose());
// Checking the decomposition
Assert.IsTrue(Matrix.IsEqual(actual, expected, 1e-8));
}
{
double[] solution = target.Solve(output);
double[] expected= output;
double[] actual = value.Multiply(solution);
Assert.IsTrue(Matrix.IsEqual(actual, expected, 1e-8));
}
}示例6: Minimize
/// <summary>
/// Attempts to find the best values for the parameter vector
/// minimizing the discrepancy between the generated outputs
/// and the expected outputs for a given set of input data.
/// </summary>
///
/// <param name="inputs">A set of input data.</param>
/// <param name="outputs">The values associated with each
/// vector in the <paramref name="inputs"/> data.</param>
///
public double Minimize(double[][] inputs, double[] outputs)
{
Array.Clear(hessian, 0, hessian.Length);
Array.Clear(gradient, 0, gradient.Length);
errors = new double[inputs.Length];
jacobian = new double[inputs.Length, numberOfParameters];
for (int i = 0; i < inputs.Length; i++)
errors[i] = outputs[i] - Function(weights, inputs[i]);
double[] g = new double[numberOfParameters];
for (int i = 0; i < inputs.Length; i++)
{
Gradient(weights, inputs[i], result: g);
for (int j = 0; j < gradient.Length; j++)
jacobian[i, j] = -g[j];
}
// Compute error gradient using Jacobian
jacobian.TransposeAndMultiply(errors, result: gradient);
// Compute Quasi-Hessian Matrix approximation
jacobian.TransposeAndMultiply(jacobian, result: hessian);
decomposition = new SingularValueDecomposition(hessian,
computeLeftSingularVectors: true, computeRightSingularVectors: true, autoTranspose: true);
deltas = decomposition.Solve(gradient);
for (int i = 0; i < deltas.Length; i++)
weights[i] -= deltas[i];
return ComputeError(inputs, outputs);
}