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C# XYZ.Count方法代码示例

本文整理汇总了C#中XYZ.Count方法的典型用法代码示例。如果您正苦于以下问题:C# XYZ.Count方法的具体用法?C# XYZ.Count怎么用?C# XYZ.Count使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在XYZ的用法示例。


在下文中一共展示了XYZ.Count方法的3个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C#代码示例。

示例1: CreateFilletedRectangleCurveLoop

        private CurveLoop CreateFilletedRectangleCurveLoop(XYZ[] corners, double filletRadius)
        {
            int sz = corners.Count();
            if (sz != 4)
                return null;

            XYZ[] radii = new XYZ[4] { 
                new XYZ( corners[0].X + filletRadius, corners[0].Y + filletRadius, 0.0 ),
                new XYZ( corners[1].X - filletRadius, corners[1].Y + filletRadius, 0.0 ),
                new XYZ( corners[2].X - filletRadius, corners[2].Y - filletRadius, 0.0 ),
                new XYZ( corners[3].X + filletRadius, corners[3].Y - filletRadius, 0.0 ),
            };

            XYZ[] fillets = new XYZ[8] { 
                new XYZ( corners[0].X, corners[0].Y + filletRadius, 0.0 ),
                new XYZ( corners[0].X + filletRadius, corners[0].Y, 0.0 ),
                new XYZ( corners[1].X - filletRadius, corners[1].Y, 0.0 ),
                new XYZ( corners[1].X, corners[1].Y + filletRadius, 0.0 ),
                new XYZ( corners[2].X, corners[2].Y - filletRadius, 0.0 ),
                new XYZ( corners[2].X - filletRadius, corners[2].Y, 0.0 ),
                new XYZ( corners[3].X + filletRadius, corners[3].Y, 0.0 ),
                new XYZ( corners[3].X, corners[3].Y - filletRadius, 0.0 )
            };

            CurveLoop curveLoop = new CurveLoop();
            for (int ii = 0; ii < 4; ii++)
            {
                curveLoop.Append(Line.CreateBound(fillets[ii * 2 + 1], fillets[(ii * 2 + 2) % 8]));
                double startAngle = Math.PI * ((ii + 3) % 4) / 2;
                curveLoop.Append(CreateXYArc(radii[(ii + 1) % 4], filletRadius, startAngle, startAngle + Math.PI / 2));
            }

            return curveLoop;
        }
开发者ID:whztt07,项目名称:RevitIFC,代码行数:34,代码来源:IFCProfileDef.cs

示例2: InternalSetPositions

        /// <summary>
        /// Set the positions of the internal family instance from a list of XYZ points
        /// </summary>
        /// <param name="points"></param>
        private void InternalSetPositions( XYZ[] points )
        {
            TransactionManager.Instance.EnsureInTransaction(Document);

            IList<ElementId> placePointIds = AdaptiveComponentInstanceUtils.GetInstancePlacementPointElementRefIds(InternalFamilyInstance);

            if (placePointIds.Count() != points.Count())
                throw new Exception("The input list of points does not have the same number of values required by the adaptive component.");

            // Set the position of each placement point
            int i = 0;
            foreach (var id in placePointIds)
            {
                var point = (Autodesk.Revit.DB.ReferencePoint)Document.GetElement(id);
                point.Position = points[i];
                i++;
            }

            TransactionManager.Instance.TransactionTaskDone();
        }
开发者ID:whztt07,项目名称:Dynamo,代码行数:24,代码来源:AdaptiveComponent.cs

示例3: CreatePolyCurveLoop

        private CurveLoop CreatePolyCurveLoop(XYZ[] corners)
        {
            int sz = corners.Count();
            if (sz == 0)
                return null;

            CurveLoop curveLoop = new CurveLoop();
            for (int ii = 0; ii < sz; ii++)
                curveLoop.Append(Line.CreateBound(corners[ii], corners[(ii + 1) % sz]));
            return curveLoop;
        }
开发者ID:whztt07,项目名称:RevitIFC,代码行数:11,代码来源:IFCProfileDef.cs


注:本文中的XYZ.Count方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。