本文整理汇总了C#中XObject.ToFriendlyName方法的典型用法代码示例。如果您正苦于以下问题：C# XObject.ToFriendlyName方法的具体用法？C# XObject.ToFriendlyName怎么用？C# XObject.ToFriendlyName使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类XObject的用法示例。
在下文中一共展示了XObject.ToFriendlyName方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C#代码示例。
示例1: Deserialize
public void Deserialize(XObject source, IMemberContext target, IAdviceRequester adviceRequester)
{
if (source == null)
return;
if (source.NodeType != XmlNodeType.Element)
throw new ArgumentException("Parameter must be an XML element.", "source");
if (_log.IsDebugEnabled)
_log.Debug("Deserializing " + source.ToFriendlyName() + " into " + target + ".");
var elem = (XElement)source;
Type targetType = _typeConverter.GetActualType(source, target, adviceRequester);
if (targetType == null)
throw new ArgumentException("Unable to get target type for target '" + target + "'.");
IObjectContext targetObject = _objectContextFactory.CreateForDeserialization(target, targetType, adviceRequester);
if (targetObject == null)
throw new ArgumentException("Unable to create target object for target '" + target + "'.");
target.SetValue(targetObject);
List<IMapping<XObject, IMemberContext>> mappings = _mapper.MapForDeserialization(elem, target, adviceRequester)
.ToList();
if (mappings == null)
throw new ArgumentException("Unable to map source '" + source + "' and target '" + target + "'.");
DeserializeRecursively(mappings, adviceRequester);
target.CommitChanges();
}示例2: Select
public IDeserializer Select(XObject source, IMemberContext target, IAdviceRequester adviceRequester)
{
Type actualType = _typeConverter.GetActualType(source, target, adviceRequester);
if (actualType == null)
return null;
if (_log.IsDebugEnabled)
_log.Debug("Selected collection deserialization for source '" + source.ToFriendlyName() + "' and target '" + target + "'.");
return _deserializer;
}