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C# RecurrencePattern.GetOccurrence方法代码示例

本文整理汇总了C#中RecurrencePattern.GetOccurrence方法的典型用法代码示例。如果您正苦于以下问题:C# RecurrencePattern.GetOccurrence方法的具体用法?C# RecurrencePattern.GetOccurrence怎么用?C# RecurrencePattern.GetOccurrence使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在RecurrencePattern的用法示例。


在下文中一共展示了RecurrencePattern.GetOccurrence方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C#代码示例。

示例1: getOutlookInstance

 private static AppointmentItem getOutlookInstance(RecurrencePattern oPattern, DateTime instanceDate) {
     //First check if this is not yet an exception
     AppointmentItem ai = null;
     try {
         ai = oPattern.GetOccurrence(instanceDate);
     } catch { }
     if (ai == null) {
         //The Outlook API is rubbish as the date argument is how it exists NOW (not OriginalDate). 
         //If this has changed >1 in Google then there's no way of knowing what it might be!
         
         foreach (Microsoft.Office.Interop.Outlook.Exception oExp in oPattern.Exceptions) {
             if (oExp.OriginalDate.Date == instanceDate.Date) {
                 try {
                     log.Debug("Found Outlook exception for " + instanceDate);
                     if (exceptionIsDeleted(oExp)) {
                         log.Debug("This exception is deleted.");
                         return null;
                     } else {
                         return oExp.AppointmentItem;
                     }
                 } catch (System.Exception ex) {
                     MainForm.Instance.Logboxout(ex.Message);
                     MainForm.Instance.Logboxout("If this keeps happening, please restart OGCS.");
                     break;
                 }
             }
         }
         if (ai == null) log.Warn("Unable to find Outlook exception for " + instanceDate);
     }
     return ai;
 }
开发者ID:EduShareGeorgian,项目名称:OutlookGoogleSync,代码行数:31,代码来源:Recurrence.cs


注:本文中的RecurrencePattern.GetOccurrence方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。