本文整理汇总了C#中Pitch.IsInMidiRange方法的典型用法代码示例。如果您正苦于以下问题：C# Pitch.IsInMidiRange方法的具体用法？C# Pitch.IsInMidiRange怎么用？C# Pitch.IsInMidiRange使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类Pitch的用法示例。
在下文中一共展示了Pitch.IsInMidiRange方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C#代码示例。
示例1: EncodeNoteOn
/// <summary>
/// Encodes a Note On short message.
/// </summary>
/// <param name="channel">The channel.</param>
/// <param name="pitch">The pitch.</param>
/// <param name="velocity">The velocity 0..127.</param>
/// <returns>A value that can be passed to midiOutShortMsg.</returns>
/// <exception cref="ArgumentOutOfRangeException">pitch is not in MIDI range.</exception>
public static UInt32 EncodeNoteOn(Channel channel, Pitch pitch, int velocity)
{
channel.Validate();
if (!pitch.IsInMidiRange())
{
throw new ArgumentOutOfRangeException("Pitch out of MIDI range.");
}
if (velocity < 0 || velocity > 127)
{
throw new ArgumentOutOfRangeException("Velocity is out of range.");
}
return (UInt32)(0x90 | ((int)channel) | ((int)pitch << 8) | (velocity << 16));
}示例2: NoteMessage
/// <summary>
/// Protected constructor.
/// </summary>
protected NoteMessage(DeviceBase device, Channel channel, Pitch pitch, int velocity,
float time)
: base(device, channel, time)
{
if (!pitch.IsInMidiRange())
{
throw new ArgumentOutOfRangeException("pitch is out of MIDI range.");
}
if (velocity < 0 || velocity > 127)
{
throw new ArgumentOutOfRangeException("velocity");
}
this.pitch = pitch;
this.velocity = velocity;
}