本文整理汇总了C#中Microsoft.VisualStudio.TestTools.UnitTesting.All方法的典型用法代码示例。如果您正苦于以下问题:C# Microsoft.VisualStudio.TestTools.UnitTesting.All方法的具体用法?C# Microsoft.VisualStudio.TestTools.UnitTesting.All怎么用?C# Microsoft.VisualStudio.TestTools.UnitTesting.All使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类Microsoft.VisualStudio.TestTools.UnitTesting
的用法示例。
在下文中一共展示了Microsoft.VisualStudio.TestTools.UnitTesting.All方法的2个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C#代码示例。
示例1: TestAllWithLocalCollection
public void TestAllWithLocalCollection()
{
// get all customers with a name that contains both 'm' and 'd' (don't use vowels since these often depend on collation)
string[] patterns = new[] { "m", "d" };
var list = db.Customers.Where(c => patterns.All(p => c.ContactName.Contains(p))).Select(c => c.ContactName).ToList();
var local = db.Customers.AsEnumerable().Where(c => patterns.All(p => c.ContactName.ToLower().Contains(p))).Select(c => c.ContactName).ToList();
AssertValue(local.Count, list.Count);
}
示例2: EnumerableTest
public void EnumerableTest()
{
using (var db = new LiteDatabase(new MemoryStream()))
{
var col = db.GetCollection<User>("Users");
col.EnsureIndex(x => x.Name, true);
col.EnsureIndex(x => x.Age);
col.Insert(new[] { new User() { Id = 1, Name = "John Smith", Age = 10 },
new User() { Id = 2, Name = "Jane Smith", Age = 12 },
new User() { Id = 3, Name = "John Doe", Age = 24 },
new User() { Id = 4, Name = "Jane Doe", Age = 42 } });
var empty = new string[] { };
Assert.AreEqual(0, col.Count(user => empty.All(name => user.Name.Contains(name))));
Assert.AreEqual(0, col.Count(user => empty.Any(name => user.Name.Contains(name))));
var firstNames = new[] { "John", "Jane", "Jon", "Janet" };
Assert.AreEqual(0, col.Count(user => firstNames.All(name => user.Name.StartsWith(name))));
Assert.AreEqual(4, col.Count(user => firstNames.Any(name => user.Name.StartsWith(name))));
var surnames = new[] { "Smith", "Doe", "Mason", "Brown" };
Assert.AreEqual(0, col.Count(user => surnames.All(name => user.Name.Contains(name))));
Assert.AreEqual(4, col.Count(user => surnames.Any(name => user.Name.Contains(name))));
var johnSmith = new[] { "John", "Smith" };
Assert.AreEqual(1, col.Count(user => johnSmith.All(name => user.Name.Contains(name))));
Assert.AreEqual(3, col.Count(user => johnSmith.Any(name => user.Name.Contains(name))));
var janeDoe = new[] { "Jane", "Doe" };
Assert.AreEqual(1, col.Count(user => janeDoe.All(name => user.Name.Contains(name))));
Assert.AreEqual(3, col.Count(user => janeDoe.Any(name => user.Name.Contains(name))));
var numRange = new[] { new { Min = 10, Max = 12 },
new { Min = 21, Max = 33 } };
var numQuery = numRange.Select(num => Query.And(Query.GTE("Age", num.Min), Query.LTE("Age", num.Max)));
var queryResult = col.Find(numQuery.Aggregate((lhs, rhs) => Query.Or(lhs, rhs)));
var lambdaResult = col.Find(p => numRange.Any(num => p.Age >= num.Min && p.Age <= num.Max));
Assert.IsTrue(queryResult.OrderBy(u => u.Name).SequenceEqual(lambdaResult.OrderBy(u => u.Name)));
}
}