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C# MemberMapper.Map方法代码示例

本文整理汇总了C#中MemberMapper.Map方法的典型用法代码示例。如果您正苦于以下问题:C# MemberMapper.Map方法的具体用法?C# MemberMapper.Map怎么用?C# MemberMapper.Map使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在MemberMapper的用法示例。


在下文中一共展示了MemberMapper.Map方法的15个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C#代码示例。

示例1: ClearMapCacheIsRespected

        public void ClearMapCacheIsRespected()
        {
            var mapper = new MemberMapper();

              mapper.CreateMap<SourceType, DestinationType>(customMapping: src => new
              {
            ID = src.ID * 10,
            Name = src.Name + src.Name
              });

              var source = new SourceType
              {
            ID = 10,
            Name = "x"
              };

              var result = mapper.Map<DestinationType>(source);

              Assert.AreEqual(100, result.ID);
              Assert.AreEqual("xx", result.Name);

              mapper.ClearMapCache();

              result = mapper.Map<DestinationType>(source);

              Assert.AreEqual(10, result.ID);
              Assert.AreEqual("x", result.Name);
        }
开发者ID:JulianR,项目名称:ThisMember,代码行数:28,代码来源:MemberMapperTests.cs

示例2: MappingConditionIsRespectedForNestedCollectionMembers

        //[TestMethod]
        public void MappingConditionIsRespectedForNestedCollectionMembers()
        {
            var mapper = new MemberMapper();

              int i = 10;

              mapper.CreateMapProposal<SourceTypeCollection, DestinationTypeCollection>()
            .ForMember(dest => dest.Nested).OnlyIf(src => i == 0)
            .FinalizeMap();

              var source = new SourceTypeCollection
              {
            Nested = new List<NestedSourceType>
            {
              new NestedSourceType
              {
            Foo = "Bla"
              }
            }
              };

              var result = mapper.Map<SourceTypeCollection, DestinationTypeCollection>(source);

              Assert.IsNull(result.Nested);

              //i = 0;

              result = mapper.Map<SourceTypeCollection, DestinationTypeCollection>(source);

              Assert.AreEqual("Bla", result.Nested.Single().Foo);
        }
开发者ID:JulianR,项目名称:ThisMember,代码行数:32,代码来源:ProposedMapMutationTests.cs

示例3: WithListStringToWithListString

        public void WithListStringToWithListString()
        {
            var mapper = new MemberMapper();

              mapper.Options.Debug.DebugInformationEnabled = true;

              var source = new WithListofString { Foo = new List<string> { "test" } };

              var result = mapper.Map(source, new WithListofString());

              Assert.IsTrue(object.ReferenceEquals(source.Foo, result.Foo));

              var x = result;

              result.Foo = x.Foo;

              var newResult = mapper.Map(source, result);

              Assert.IsTrue(object.ReferenceEquals(result, newResult));
              Assert.IsTrue(object.ReferenceEquals(result.Foo, newResult.Foo));
              Assert.AreEqual(1, newResult.Foo.Count);

              var otherSource = new WithListofString { Foo = new List<string> { "test1" } };

              mapper.Map(otherSource, result);

              Assert.IsTrue(object.ReferenceEquals(result.Foo, newResult.Foo));
              Assert.AreEqual(2, result.Foo.Count);
        }
开发者ID:JulianR,项目名称:ThisMember,代码行数:29,代码来源:ReferenceEqualityTests.cs

示例4: MappingConditionIsRespected

        public void MappingConditionIsRespected()
        {
            var mapper = new MemberMapper();

              mapper.CreateMapProposal<SourceType, DestinationType>()
            .ForMember(dest => dest.Name).OnlyIf(src => src.ID == 0)
            .FinalizeMap();

              var source = new SourceType
              {
            ID = 10,
            Name = "X",
            Nested = new NestedSourceType
            {
              Foo = "Bla"
            }
              };

              var result = mapper.Map<SourceType, DestinationType>(source);

              Assert.IsNull(result.Name);

              source.ID = 0;

              result = mapper.Map<SourceType, DestinationType>(source);

              Assert.AreEqual("X", result.Name);
        }
开发者ID:JulianR,项目名称:ThisMember,代码行数:28,代码来源:ProposedMapMutationTests.cs

示例5: RecursiveRelationshipsAreMappedCorrectly

        public void RecursiveRelationshipsAreMappedCorrectly()
        {
            var map = new MemberMapper();

              var source = new SourceType
              {
            ID = 10,
            Children = new List<SourceType>
            {
              new SourceType
              {
            ID = 11,
              },
              new SourceType
              {
            ID = 12,
            Children = new List<SourceType>
            {
              new SourceType
              {
                ID = 13
              }
            }
              }

            }
              };

              var result = map.Map<SourceType, DestinationType>(source);
        }
开发者ID:JulianR,项目名称:ThisMember,代码行数:30,代码来源:RecursiveMapTests.cs

示例6: BaseClassMappingAndInheritedClassMappingIsRespected

        public void BaseClassMappingAndInheritedClassMappingIsRespected()
        {
            var mapper = new MemberMapper();

              mapper.Options.Strictness.ThrowWithoutCorrespondingSourceMember = true;

              mapper.CreateMap<SourceBase, DestinationBase>(customMapping: src => new DestinationBase
              {
            Test = src.ID
              });

              mapper.CreateMap<SecondSourceInherited, SecondDestinationInherited>(customMapping: src => new SecondDestinationInherited
              {
            Bar = src.Foo
              });

              var result = mapper.Map<SecondSourceInherited, SecondDestinationInherited>(new SecondSourceInherited
              {
            ID = 10,
            Foo = "test"
              });

              Assert.AreEqual(10, result.Test);
              Assert.AreEqual("test", result.Bar);
        }
开发者ID:JulianR,项目名称:ThisMember,代码行数:25,代码来源:InheritanceTests.cs

示例7: ComplexTypeMappingRespectsExistingMapping

        public void ComplexTypeMappingRespectsExistingMapping()
        {
            var mapper = new MemberMapper();

              var proposed = mapper.CreateMap(typeof(ComplexSourceType), typeof(ComplexDestinationType),
              (s, p, option) =>
              {
            if (s.Name == "Name")
            {
              option.IgnoreMember();
            }
              });

              proposed.FinalizeMap();

              var source = new ComplexSourceType
              {
            ID = 5,
            Complex = new NestedSourceType
            {
              ID = 10,
              Name = "test"
            }
              };

              var destination = mapper.Map<ComplexSourceType, ComplexDestinationType>(source);

              Assert.AreEqual(destination.ID, 5);
              Assert.IsNotNull(destination.Complex);
              Assert.AreNotEqual(destination.Complex.Name, source.Complex.Name);
        }
开发者ID:JulianR,项目名称:MemberMapper,代码行数:31,代码来源:MemberMapperTests.cs

示例8: NonNullableGetsMappedToNullableNonPrimitiveVT

        public void NonNullableGetsMappedToNullableNonPrimitiveVT()
        {
            var mapper = new MemberMapper();

              var result = mapper.Map<NonNullableSourceNonPrimitiveVT, NullableDestinationNonPrimitiveVT>(new NonNullableSourceNonPrimitiveVT { ID = 10 });

              Assert.AreEqual(10, result.ID.Value);
        }
开发者ID:JulianR,项目名称:ThisMember,代码行数:8,代码来源:NullableValueTypesTests.cs

示例9: ParameterIsUsed

        public void ParameterIsUsed()
        {
            var mapper = new MemberMapper();

              mapper.CreateMap<SourceType, DestinationType, int>((src, i) => new DestinationType
              {
            ID = i
              });

              var result = mapper.Map(new SourceType(), new DestinationType(), 10);

              Assert.AreEqual(10, result.ID);

              result = mapper.Map(new SourceType(), new DestinationType(), 15);

              Assert.AreEqual(15, result.ID);
        }
开发者ID:JulianR,项目名称:ThisMember,代码行数:17,代码来源:ParameterTests.cs

示例10: InvokingMapWithoutParameterAsMapWithParameterThrows

        public void InvokingMapWithoutParameterAsMapWithParameterThrows()
        {
            var mapper = new MemberMapper();

              mapper.CreateMap<SourceType, DestinationType>();

              var result = mapper.Map(new SourceType(), new DestinationType(), 1);
        }
开发者ID:JulianR,项目名称:ThisMember,代码行数:8,代码来源:ParameterTests.cs

示例11: IntIsMappedToEnum

        public void IntIsMappedToEnum()
        {
            var mapper = new MemberMapper();

              var result = mapper.Map<IntClass, EnumClass>(new IntClass { Foo = 2 });

              Assert.AreEqual(Foo.B, result.Foo);
        }
开发者ID:JulianR,项目名称:ThisMember,代码行数:8,代码来源:EnumTests.cs

示例12: EnumIsMappedToInt

        public void EnumIsMappedToInt()
        {
            var mapper = new MemberMapper();

              var result = mapper.Map<EnumClass, IntClass>(new EnumClass { Foo = Foo.B });

              Assert.AreEqual(2, result.Foo);
        }
开发者ID:JulianR,项目名称:ThisMember,代码行数:8,代码来源:EnumTests.cs

示例13: DirectMapping

        public static void DirectMapping()
        {
            var customer = new Customer
              {
            ID = 1,
            FirstName = "First",
            LastName = "Last",
            Orders = new List<Order>
            {
              new Order
              {
            ID = 1,
            Amount = 10,
              },
              new Order
              {
            ID = 2,
            Amount = 20
              }
            }
              };

              var mapper = new MemberMapper();

              // Explicit source and destination type, just pass a source type instance
              var dto = mapper.Map<Customer, CustomerDto>(customer);

              // Just specify what ThisMember should map to, pass in any type that you think can be mapped
              dto = mapper.Map<CustomerDto>(customer);

              // Update the existing Customer, just set a new FirstName for him
              dto = new CustomerDto
              {
            FirstName = "NewName"
              };

              // For that we have to set an option that null-values from the source are ignored, so that LastName does not get set to null
              mapper.Options.Conventions.IgnoreMembersWithNullValueOnSource = true;

              // Setting an option that affects map generation has no effect on maps that have already been generated. Normally there'd be little
              // need to set this option on the fly, you would just have a seperate mapper for doing these mappings. But for this sample, it works fine.
              mapper.ClearMapCache(); // We could also have called mapper.CreateMap<CustomerDto, Customer>(), which always recreates the map.

              // Only FirstName will have changed now on customer, because the null (or null-equivalent in case of nullable value types) values were ignored.
              mapper.Map(dto, customer);
        }
开发者ID:JulianR,项目名称:ThisMember,代码行数:46,代码来源:SimpleScenarios.cs

示例14: MapForMapWithParameterThrowsForMapWithoutParameter

        public void MapForMapWithParameterThrowsForMapWithoutParameter()
        {
            var mapper = new MemberMapper();

              mapper.CreateMap<SourceType, DestinationType>();

              mapper.Map<SourceType, DestinationType, int>(new SourceType(), 0);
        }
开发者ID:JulianR,项目名称:ThisMember,代码行数:8,代码来源:GenericsTests.cs

示例15: DictionaryToIDictionaryIsReferenceEqual

        public void DictionaryToIDictionaryIsReferenceEqual()
        {
            var mapper = new MemberMapper();
              var source = new DictionaryClass { Foo = new Dictionary<int, string>() };
              var result = mapper.Map(source, new IDictionaryClass());

              Assert.IsTrue(object.ReferenceEquals(source.Foo, result.Foo));
        }
开发者ID:JulianR,项目名称:ThisMember,代码行数:8,代码来源:DictionaryTests.cs


注:本文中的MemberMapper.Map方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。