本文整理汇总了C#中MemberAccessExpressionSyntax.GetTrailingTrivia方法的典型用法代码示例。如果您正苦于以下问题：C# MemberAccessExpressionSyntax.GetTrailingTrivia方法的具体用法？C# MemberAccessExpressionSyntax.GetTrailingTrivia怎么用？C# MemberAccessExpressionSyntax.GetTrailingTrivia使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类MemberAccessExpressionSyntax的用法示例。
在下文中一共展示了MemberAccessExpressionSyntax.GetTrailingTrivia方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C#代码示例。
示例1: InsertAsyncCall
private async Task<Document> InsertAsyncCall(Document document, MemberAccessExpressionSyntax memberAccess, CancellationToken cancellationToken)
{
var name = memberAccess.Name.Identifier.ValueText;
ExpressionSyntax oldNode, newNode, newMemberAccess;
switch (name)
{
case "WaitAny":
newMemberAccess = memberAccess.WithName((SimpleNameSyntax)SyntaxFactory.ParseName("WhenAny"));
break;
case "WaitAll":
newMemberAccess = memberAccess.WithName((SimpleNameSyntax)SyntaxFactory.ParseName("WhenAny"));
break;
case "Wait":
newMemberAccess = memberAccess.Expression;
break;
case "Result":
newMemberAccess = memberAccess.Expression;
break;
case "Sleep":
newMemberAccess = SyntaxFactory.ParseExpression("Task.Delay");
break;
default:
newMemberAccess = memberAccess.WithName((SimpleNameSyntax)SyntaxFactory.ParseName(memberAccess.Name.Identifier.ValueText + "Async"));
break;
}
var invoc = memberAccess.Parent as InvocationExpressionSyntax;
// WaitAny, WaitAll, Wait, Sleep, XyzAsync etc.
if (invoc != null)
{
oldNode = invoc;
newNode = name == "Wait" ? newMemberAccess : invoc.WithExpression(newMemberAccess);
}
// t.Result
else
{
oldNode = memberAccess;
newNode = newMemberAccess;
}
newNode = SyntaxFactory.AwaitExpression(newNode)
.WithAdditionalAnnotations(Formatter.Annotation)
.WithLeadingTrivia(memberAccess.GetLeadingTrivia())
.WithTrailingTrivia(memberAccess.GetTrailingTrivia());
if (oldNode.Parent.Kind() == SyntaxKind.SimpleMemberAccessExpression)
{
newNode = SyntaxFactory.ParenthesizedExpression(newNode);
}
var root = await document.GetSyntaxRootAsync().ConfigureAwait(false);
var newRoot = root.ReplaceNode(oldNode, newNode);
return document.WithSyntaxRoot(newRoot);
}