本文整理汇总了C#中MachineCodeEmitter.EmitRelativeJumpAndCall方法的典型用法代码示例。如果您正苦于以下问题：C# MachineCodeEmitter.EmitRelativeJumpAndCall方法的具体用法？C# MachineCodeEmitter.EmitRelativeJumpAndCall怎么用？C# MachineCodeEmitter.EmitRelativeJumpAndCall使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类MachineCodeEmitter的用法示例。
在下文中一共展示了MachineCodeEmitter.EmitRelativeJumpAndCall方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C#代码示例。
示例1: Emit
/// <summary>
/// Emits the specified platform instruction.
/// </summary>
/// <param name="context">The context.</param>
/// <param name="emitter">The emitter.</param>
protected override void Emit(Context context, MachineCodeEmitter emitter)
{
if (context.OperandCount == 0)
{
emitter.EmitRelativeJumpAndCall(0x00, context.BranchTargets[0]);
}
else
throw new Exception("Not supported combination of operands");
}示例2: Emit
/// <summary>
/// Emits the specified platform instruction.
/// </summary>
/// <param name="context">The context.</param>
/// <param name="emitter">The emitter.</param>
protected override void Emit(Context context, MachineCodeEmitter emitter)
{
if (context.OperandCount == 0)
{
int displacement = context.BranchTargets[0];
if (IsBetween(displacement, -1024, 1022))
{
emitter.EmitRelativeJumpAndCall(0x01, context.BranchTargets[0]);
}
else
if (IsBetween(displacement, -2097151, 2097150))
{
emitter.EmitNoRegisterAndK21(0x50, context.BranchTargets[0]);
}
else
throw new OverflowException();
}
else
throw new Exception("Not supported combination of operands");
}