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C# ItemCollection.SequenceEqual方法代码示例

本文整理汇总了C#中ItemCollection.SequenceEqual方法的典型用法代码示例。如果您正苦于以下问题:C# ItemCollection.SequenceEqual方法的具体用法?C# ItemCollection.SequenceEqual怎么用?C# ItemCollection.SequenceEqual使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在ItemCollection的用法示例。


在下文中一共展示了ItemCollection.SequenceEqual方法的3个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C#代码示例。

示例1: Test_sorting_update_item_changes_order

		public void Test_sorting_update_item_changes_order()
		{
			var item1 = new ActivityMonitorComponent.WorkItem(new WorkItemData { Identifier = 1, Status = WorkItemStatusEnum.Canceled });
			var item2 = new ActivityMonitorComponent.WorkItem(new WorkItemData { Identifier = 2, Status = WorkItemStatusEnum.Complete });
			var item3 = new ActivityMonitorComponent.WorkItem(new WorkItemData { Identifier = 3, Status = WorkItemStatusEnum.Failed });
			var item4 = new ActivityMonitorComponent.WorkItem(new WorkItemData { Identifier = 4, Status = WorkItemStatusEnum.Idle });
			var item5 = new ActivityMonitorComponent.WorkItem(new WorkItemData { Identifier = 5, Status = WorkItemStatusEnum.Pending });

			var items = new ItemCollection<ActivityMonitorComponent.WorkItem>();
			var manager = new ActivityMonitorComponent.WorkItemUpdateManager(items, NoFilter, () => { });

			// insert items in sorted order, and verify that this order is preserved
			manager.Update(new[] { item1, item2, item3, item4, item5 }, StatusComparison);
			Assert.IsTrue(items.SequenceEqual(new[] { item1, item2, item3, item4, item5 }));

			// item 1 changes to Complete - should not cause a change in list order
			item1 = new ActivityMonitorComponent.WorkItem(new WorkItemData { Identifier = 1, Status = WorkItemStatusEnum.Canceling });
			manager.Update(new[] { item1 }, StatusComparison);
			Assert.IsTrue(items.SequenceEqual(new[] { item1, item2, item3, item4, item5 }));

			// item 4 changes to Complete, causing it to be repositioned in the list
			item4 = new ActivityMonitorComponent.WorkItem(new WorkItemData { Identifier = 4, Status = WorkItemStatusEnum.Complete });
			manager.Update(new[] { item4 }, StatusComparison);
			Assert.IsTrue(items.SequenceEqual(new[] { item1, item2, item4, item3, item5 }) || items.SequenceEqual(new[] { item1, item4, item2, item3, item5 }));
		}
开发者ID:nhannd,项目名称:Xian,代码行数:25,代码来源:ActivityMonitorComponentTests.cs

示例2: Test_sorting_update_nonsort_property_retains_order

		public void Test_sorting_update_nonsort_property_retains_order()
		{
			var item1 = new ActivityMonitorComponent.WorkItem(new WorkItemData { Identifier = 1, Status = WorkItemStatusEnum.Pending, Priority = WorkItemPriorityEnum.Normal });
			var item2 = new ActivityMonitorComponent.WorkItem(new WorkItemData { Identifier = 2, Status = WorkItemStatusEnum.Pending, Priority = WorkItemPriorityEnum.Normal });
			var item3 = new ActivityMonitorComponent.WorkItem(new WorkItemData { Identifier = 3, Status = WorkItemStatusEnum.Pending, Priority = WorkItemPriorityEnum.Normal });
			var item4 = new ActivityMonitorComponent.WorkItem(new WorkItemData { Identifier = 4, Status = WorkItemStatusEnum.Pending, Priority = WorkItemPriorityEnum.Normal });
			var item5 = new ActivityMonitorComponent.WorkItem(new WorkItemData { Identifier = 5, Status = WorkItemStatusEnum.Pending, Priority = WorkItemPriorityEnum.Normal });

			var items = new ItemCollection<ActivityMonitorComponent.WorkItem>();
			items.AddRange(new[] { item1, item2, item3, item4, item5 });

			// the idea here is that if an item is updated, but the sorty property (Status) has not changed,
			// then the item does not move around in the list, but is updated in place
			var manager = new ActivityMonitorComponent.WorkItemUpdateManager(items, NoFilter, () => { });

			// item 1 Priority changes - should not cause a change in list order
			var x = new ActivityMonitorComponent.WorkItem(new WorkItemData { Identifier = 1, Status = WorkItemStatusEnum.Pending, Priority = WorkItemPriorityEnum.Stat});
			manager.Update(new[] { x }, StatusComparison);
			Assert.IsTrue(items.SequenceEqual(new[] { item1, item2, item3, item4, item5 }));

			// item 4 Priority changes - should not cause a change in list order
			var y = new ActivityMonitorComponent.WorkItem(new WorkItemData { Identifier = 4, Status = WorkItemStatusEnum.Pending, Priority = WorkItemPriorityEnum.High});
			manager.Update(new[] { y }, StatusComparison);
			Assert.IsTrue(items.SequenceEqual(new[] { item1, item2, item3, item4, item5 }));
		}
开发者ID:nhannd,项目名称:Xian,代码行数:25,代码来源:ActivityMonitorComponentTests.cs

示例3: Test_sorting_items_inserted_in_sorted_order

		public void Test_sorting_items_inserted_in_sorted_order()
		{
			var item1 = new ActivityMonitorComponent.WorkItem(new WorkItemData { Identifier = 1, Status = WorkItemStatusEnum.Canceled });
			var item2 = new ActivityMonitorComponent.WorkItem(new WorkItemData { Identifier = 2, Status = WorkItemStatusEnum.Complete });
			var item3 = new ActivityMonitorComponent.WorkItem(new WorkItemData { Identifier = 3, Status = WorkItemStatusEnum.Failed });
			var item4 = new ActivityMonitorComponent.WorkItem(new WorkItemData { Identifier = 4, Status = WorkItemStatusEnum.Idle });
			var item5 = new ActivityMonitorComponent.WorkItem(new WorkItemData { Identifier = 5, Status = WorkItemStatusEnum.Pending });

			var items = new ItemCollection<ActivityMonitorComponent.WorkItem>();
			var manager = new ActivityMonitorComponent.WorkItemUpdateManager(items, NoFilter, () => { });

			// insert items in sorted order, and verify that this order is preserved
			manager.Update(new [] { item1, item2, item3, item4, item5 }, StatusComparison);
			Assert.IsTrue(items.SequenceEqual(new[] { item1, item2, item3, item4, item5 }));

			// insert items in reverse order, and verify that they still end up in sorted order
			items.Clear();
			manager.Update(new[] { item5, item4, item3, item2, item1 }, StatusComparison);
			Assert.IsTrue(items.SequenceEqual(new[] { item1, item2, item3, item4, item5 }));

			// insert items out of sorted order, and verify that they still end up in sorted order
			items.Clear();
			manager.Update(new[] { item3, item5, item4, item1, item2 }, StatusComparison);
			Assert.IsTrue(items.SequenceEqual(new[] { item1, item2, item3, item4, item5 }));
		}
开发者ID:nhannd,项目名称:Xian,代码行数:25,代码来源:ActivityMonitorComponentTests.cs


注:本文中的ItemCollection.SequenceEqual方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。