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C# Complex32.SquareRoot方法代码示例

本文整理汇总了C#中Complex32.SquareRoot方法的典型用法代码示例。如果您正苦于以下问题:C# Complex32.SquareRoot方法的具体用法?C# Complex32.SquareRoot怎么用?C# Complex32.SquareRoot使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在Complex32的用法示例。


在下文中一共展示了Complex32.SquareRoot方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C#代码示例。

示例1: CanComputeSquareRoot

 public void CanComputeSquareRoot()
 {
     var complex = new Complex32(1.19209289550780998537e-7f, 1.19209289550780998537e-7f);
     AssertHelpers.AlmostEqual(
         new Complex32(0.00037933934912842666f, 0.00015712750315077684f), complex.SquareRoot(), 7);
     complex = new Complex32(0.0f, 1.19209289550780998537e-7f);
     AssertHelpers.AlmostEqual(
         new Complex32(0.00024414062499999973f, 0.00024414062499999976f), complex.SquareRoot(), 7);
     complex = new Complex32(0.0f, -1.19209289550780998537e-7f);
     AssertHelpers.AlmostEqual(
         new Complex32(0.00024414062499999973f, -0.00024414062499999976f), complex.SquareRoot(), 7);
     complex = new Complex32(0.0f, 0.5f);
     AssertHelpers.AlmostEqual(new Complex32(0.5f, 0.5f), complex.SquareRoot(), 7);
     complex = new Complex32(0.0f, -0.5f);
     AssertHelpers.AlmostEqual(new Complex32(0.5f, -0.5f), complex.SquareRoot(), 7);
     complex = new Complex32(0.0f, -8.388608e6f);
     AssertHelpers.AlmostEqual(new Complex32(2048.0f, -2048.0f), complex.SquareRoot(), 7);
     complex = new Complex32(8.388608e6f, 1.19209289550780998537e-7f);
     AssertHelpers.AlmostEqual(new Complex32(2896.3093757400989f, 2.0579515874459933e-11f), complex.SquareRoot(), 7);
     complex = new Complex32(0.0f, 0.0f);
     AssertHelpers.AlmostEqual(Complex32.Zero, complex.SquareRoot(), 7);
 }
开发者ID:xmap2008,项目名称:mathnet-numerics,代码行数:22,代码来源:Complex32Test.cs


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