本文整理汇总了C#中CSharpSyntaxNode.IsQuery方法的典型用法代码示例。如果您正苦于以下问题:C# CSharpSyntaxNode.IsQuery方法的具体用法?C# CSharpSyntaxNode.IsQuery怎么用?C# CSharpSyntaxNode.IsQuery使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类CSharpSyntaxNode
的用法示例。
在下文中一共展示了CSharpSyntaxNode.IsQuery方法的2个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C#代码示例。
示例1: NodeIsExplicitType
private static bool NodeIsExplicitType(CSharpSyntaxNode node, CSharpSyntaxNode lambda)
{
Debug.Assert(node != null);
Debug.Assert(lambda != null);
Debug.Assert(lambda.IsAnonymousFunction() || lambda.IsQuery());
// UNDONE;
return false;
}
示例2: IsInAnonymousFunctionOrQuery
internal static bool IsInAnonymousFunctionOrQuery(int position, CSharpSyntaxNode lambdaExpressionOrQueryNode)
{
Debug.Assert(lambdaExpressionOrQueryNode.IsAnonymousFunction() || lambdaExpressionOrQueryNode.IsQuery());
SyntaxToken firstIncluded;
CSharpSyntaxNode body;
switch (lambdaExpressionOrQueryNode.Kind())
{
case SyntaxKind.SimpleLambdaExpression:
SimpleLambdaExpressionSyntax simple = (SimpleLambdaExpressionSyntax)lambdaExpressionOrQueryNode;
firstIncluded = simple.Parameter.Identifier;
body = simple.Body;
break;
case SyntaxKind.ParenthesizedLambdaExpression:
ParenthesizedLambdaExpressionSyntax parenthesized = (ParenthesizedLambdaExpressionSyntax)lambdaExpressionOrQueryNode;
firstIncluded = parenthesized.ParameterList.OpenParenToken;
body = parenthesized.Body;
break;
case SyntaxKind.AnonymousMethodExpression:
AnonymousMethodExpressionSyntax anon = (AnonymousMethodExpressionSyntax)lambdaExpressionOrQueryNode;
firstIncluded = anon.DelegateKeyword;
body = anon.Block;
break;
default:
// OK, so we have some kind of query clause. They all start with a keyword token, so we'll skip that.
firstIncluded = lambdaExpressionOrQueryNode.GetFirstToken().GetNextToken();
return IsBetweenTokens(position, firstIncluded, lambdaExpressionOrQueryNode.GetLastToken().GetNextToken());
}
var bodyStatement = body as StatementSyntax;
var firstExcluded = bodyStatement != null ?
GetFirstExcludedToken(bodyStatement) :
(SyntaxToken)SyntaxNavigator.Instance.GetNextToken(body, predicate: null, stepInto: null);
return IsBetweenTokens(position, firstIncluded, firstExcluded);
}