本文整理汇总了C#中BinaryTree.PopMax方法的典型用法代码示例。如果您正苦于以下问题：C# BinaryTree.PopMax方法的具体用法？C# BinaryTree.PopMax怎么用？C# BinaryTree.PopMax使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类BinaryTree的用法示例。
在下文中一共展示了BinaryTree.PopMax方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C#代码示例。
示例1: Solve
private int Solve()
{
Square current = new Square(new int[] {0, 0}, 1, 0);
BinaryTree<Square> store = new BinaryTree<Square>();
store.Add(current);
double targetSize = 0;
while(!store.Empty()) {
current = store.PopMax();
int[] curentCoordinates = current.GetCoordinates();
if(curentCoordinates[0] == coordinates[0] && curentCoordinates[1] == coordinates[1]) {
targetSize = current.GetSize();
}
Square[] children = current.GetChildren();
foreach (Square child in children) {
int[] childCoordinates = child.GetCoordinates();
if(childCoordinates[0] <= coordinates[0] && childCoordinates[1] <= coordinates[1]) {
store.Add(child);
}
}
}
int count = 0;
int result = -1;
current = new Square(new int[] { 0, 0 }, 1, 0);
store.Add(current);
while (!store.Empty()) {
count++;
current = store.PopMax();
int[] curentCoordinates = current.GetCoordinates();
if (curentCoordinates[0] == coordinates[0] && curentCoordinates[1] == coordinates[1]) {
result = count;
}
Square[] children = current.GetChildren();
for (int i = 0; i < children.Length; i++) {
if (targetSize <= children[i].GetSize()) {
store.Add(children[i]);
}
}
}
return result;
}